その検証が、私はそれは、例えば、呼び出されたメソッドに戻りたい失敗した場合、私は、検証のための方法を使用するプログラムを持っている:これが実行されると呼び出し元のメソッドに戻るには?
def obtain_pokemon_name
print 'Enter Pokemon: '
pokemon = gets.chomp.capitalize
obtain_basic_attack(pokemon)
end
def obtain_basic_attack(poke)
print 'Enter basic attack: '
basic_attack = gets.chomp.downcase
check_attacks(poke, basic_attack)
obtain_spec_attack(poke)
end
def obtain_spec_attack(poke)
print 'Enter special attack: '
spec_attack = gets.chomp.downcase
check_attacks(poke, spec_attack)
end
def check_attacks(pokemon, attack)
if POKEMON_ATTACKS[pokemon][attack] == nil
puts "#{attack} is not one of #{pokemon}'s attacks, try again.."
return # to where this function was called
else
attack
end
end
begin
obtain_pokemon_name
rescue => e
puts "Failed with error code: #{e}"
end
:
Enter Pokemon: arbok
Enter basic attack: eat
eat is not one of Arbok's attacks, try again..
Enter special attack: test
test is not one of Arbok's attacks, try again..
アタックリスト:
POKEMON_ATTACKS = {
'Bulbasaur' => {'tackle' => 10.9, 'vine whip' => 15.4, 'power whip' => 21.4, 'seed bomb' => 12.5, 'sludge bomb' => 19.2},
'Ivysaur' => {'razor leaf' => 10.3, 'vine whip' => 15.4, 'power whip' => 21.4, 'sludge bomb' => 19.2, 'solar beam' => 13.3},
'Kakuna' => {'bug bite' => 13.3, 'poison sting' => 10.3, 'struggle' => 8.8},
'Beedrill' => {'bug bite' => 13.3, 'poison jab' => 14.3, 'aerial ace' => 8.6, 'sludge bomb' => 19.2, 'x-scissor' => 14.3},
'Pidgey' => {'quick attack' => 7.5, 'tackle' => 10.9, 'aerial ace' => 8.6, 'air cutter' => 7.6, 'twister' => 5.6},
'Ekans' => {'acid' => 9.5, 'poison sting' => 10.3, 'gunk shot' => 20.0, 'sludge bomb' => 19.2, 'wrap' => 3.8},
'Arbok' => {'acid' => 9.5, 'bite' => 12.0, 'dark pulse' => 12.9, 'gunk shot' => 20.0, 'sludge wave' => 17.6},
}
だから私の質問私は、呼び出し元のメソッドに戻って返すことができますどのような攻撃は、データに存在しない場合、ありますか?したがって、例えばarbok
と呼び、攻撃がtackle
であれば、それはハッシュに存在しません。どうすればobtain_basic_attack(poke)
メソッドに戻りますか?右ここ
再帰を見てみることをお勧めします。ここには良いアナロジーがあります:http://stackoverflow.com/questions/717725/understanding-recursion – Un3qual