出力からパラメータを切り離す方法

Question

私はユーザーの場所（緯度と経度）が必要な単純なプロジェクトを作成しています。成功しました。

self.locations = [[NSMutableArray alloc] init]; 
self.locationManager = [[CLLocationManager alloc] init]; 
self.locationManager.distanceFilter = 10; 

self.locationManager.desiredAccuracy = kCLLocationAccuracyBest; 
self.locationManager.delegate = self; 
[self.locationManager requestAlwaysAuthorization]; 

[self.locationManager startUpdatingLocation]; 

...

- (void)locationManager:(CLLocationManager *)manager 
didUpdateToLocation:(CLLocation *)newLocation 
     fromLocation:(CLLocation *)oldLocation 
{ 



// Add another annotation to the map. 
MKPointAnnotation *annotation = [[MKPointAnnotation alloc] init]; 
annotation.coordinate = newLocation.coordinate; 
[self.map addAnnotation:annotation]; 

// Also add to our map so we can remove old values later 
[self.locations addObject:annotation]; 

// Remove values if the array is too big 
while (self.locations.count > 1) 
{ 
    annotation = [self.locations objectAtIndex:0]; 
    [self.locations removeObjectAtIndex:0]; 

    // Also remove from the map 
    [self.map removeAnnotation:annotation]; 
} 


if (UIApplication.sharedApplication.applicationState == UIApplicationStateActive) 
{ 
    // determine the region the points span so we can update our map's zoom. 
    double maxLat = -91; 
    double minLat = 91; 
    double maxLon = -181; 
    double minLon = 181; 

    for (MKPointAnnotation *annotation in self.locations) 
    { 
     CLLocationCoordinate2D coordinate = annotation.coordinate; 

     if (coordinate.latitude > maxLat) 
      maxLat = coordinate.latitude; 
     if (coordinate.latitude < minLat) 
      minLat = coordinate.latitude; 

     if (coordinate.longitude > maxLon) 
      maxLon = coordinate.longitude; 
     if (coordinate.longitude < minLon) 
      minLon = coordinate.longitude; 
    } 

    MKCoordinateRegion region; 
    region.span.latitudeDelta = (maxLat + 90) - (minLat + 90); 
    region.span.longitudeDelta = (maxLon + 180) - (minLon + 180); 

    _latitude1=[NSString stringWithFormat:@"Latitude:%f",newLocation.coordinate.latitude]; 
    _longitude1=[NSString stringWithFormat:@"Longitude:%f",newLocation.coordinate.longitude]; 


    AppDelegate *appDelegate = (AppDelegate *)[[UIApplication sharedApplication] delegate]; 
    appDelegate.fetchtokenString1 = [NSString stringWithString:_latitude1]; 
    appDelegate.fetchedriveridString1 = [NSString stringWithString:_longitude1]; 





    NSLog(@"%@",_latitude1); 
    NSLog(@"%@",_longitude1); 


    // the center point is the average of the max and mins 
    region.center.latitude = minLat + region.span.latitudeDelta/2; 
    region.center.longitude = minLon + region.span.longitudeDelta/2; 

    // Set the region of the map. 
    [self.map setRegion:region animated:YES]; 
} 
else 
{ 
    NSLog(@"App is backgrounded. New location is %@", newLocation); 
} 

私は、私は、サーバーに個別に緯度と経度を送りたい、この<+37.33370957,-122.06381723> +/- 5.00m (speed 34.53 mps/course 294.26) @ 5/26/16, 3:38:54 PM India Standard Time のような出力を得て てる今、私の質問は、私は緯度ことを分離する方法です上の出力から長時間。私は+37.33370957を1つの文字列で区切りたいとし、-122.06381723はこれが別の文字列であることを意味します...どうすればこのようにすることができますか？ この問題の解決策をご提案ください...！

Answer 1

これは動作するはずです：

NSString *rawString = @"<+37.33370957,-122.06381723> +/- 5.00m (speed 34.53 mps/course 294.26) @ 5/26/16, 3:38:54 PM India Standard Time"; 
NSRange range1 = [rawString rangeOfString:@"<"]; 
NSRange range2 = [rawString rangeOfString:@">"]; 
NSString *string = [rawString substringWithRange:NSMakeRange(range1.location + range1.length, range2.location - range1.location - range1.length)]; 
NSArray *components = [string componentsSeparatedByString:@","]; 
NSString *latitude = [components objectAtIndex:0]; 
NSString *longitude = [components objectAtIndex:1]; 

別の方法を：

NSString *rawString = @"<+37.33370957,-122.06381723> +/- 5.00m (speed 34.53 mps/course 294.26) @ 5/26/16, 3:38:54 PM India Standard Time"; 
NSRegularExpression *regex = [NSRegularExpression regularExpressionWithPattern:@"(?<=\\<)(.*?)(?=\\>)" options:NSRegularExpressionCaseInsensitive error:nil]; 
NSTextCheckingResult *match = [regex firstMatchInString:rawString options:0 range:NSMakeRange(0, [rawString length])]; 
NSArray *components = [[rawString substringWithRange:[match rangeAtIndex:0]] componentsSeparatedByString:@","]; 
NSString *latitude = [components objectAtIndex:0]; 
NSString *longitude = [components objectAtIndex:1]; 

は、おそらく正規表現とのより良い方法がありますが、悲しいことに、私はそれでいいじゃありません。

Answer 2

てみ37.33370957 + < として、-122.06381723> +/- 5.00メートル（速度34.53 MPS /もちろん294.26）5/26/16、3時38分54秒PMインド標準時

1. プット@それは文字列変数
2. ">"文字で分割文字列を別の文字列変数に入れます
3. "、"文字で分割して文字列を分割し、 "<"文字
4. 今すぐ入手できますLANG &多くは、送信するためには、