@ Kametrixom answerに基づいて、配列内のsumの並列計算のためのテストアプリケーションをいくつか作成しました。iOS上の配列のスウィートメタル並列和計算
私のテストアプリケーションは、次のようになります。
import UIKit
import Metal
class ViewController: UIViewController {
// Data type, has to be the same as in the shader
typealias DataType = CInt
override func viewDidLoad() {
super.viewDidLoad()
let data = (0..<10000000).map{ _ in DataType(200) } // Our data, randomly generated
var start, end : UInt64
var result:DataType = 0
start = mach_absolute_time()
data.withUnsafeBufferPointer { buffer in
for elem in buffer {
result += elem
}
}
end = mach_absolute_time()
print("CPU result: \(result), time: \(Double(end - start)/Double(NSEC_PER_SEC))")
result = 0
start = mach_absolute_time()
result = sumParallel4(data)
end = mach_absolute_time()
print("Metal result: \(result), time: \(Double(end - start)/Double(NSEC_PER_SEC))")
result = 0
start = mach_absolute_time()
result = sumParralel(data)
end = mach_absolute_time()
print("Metal result: \(result), time: \(Double(end - start)/Double(NSEC_PER_SEC))")
result = 0
start = mach_absolute_time()
result = sumParallel3(data)
end = mach_absolute_time()
print("Metal result: \(result), time: \(Double(end - start)/Double(NSEC_PER_SEC))")
}
func sumParralel(data : Array<DataType>) -> DataType {
let count = data.count
let elementsPerSum: Int = Int(sqrt(Double(count)))
let device = MTLCreateSystemDefaultDevice()!
let parsum = device.newDefaultLibrary()!.newFunctionWithName("parsum")!
let pipeline = try! device.newComputePipelineStateWithFunction(parsum)
var dataCount = CUnsignedInt(count)
var elementsPerSumC = CUnsignedInt(elementsPerSum)
let resultsCount = (count + elementsPerSum - 1)/elementsPerSum // Number of individual results = count/elementsPerSum (rounded up)
let dataBuffer = device.newBufferWithBytes(data, length: strideof(DataType) * count, options: []) // Our data in a buffer (copied)
let resultsBuffer = device.newBufferWithLength(strideof(DataType) * resultsCount, options: []) // A buffer for individual results (zero initialized)
let results = UnsafeBufferPointer<DataType>(start: UnsafePointer(resultsBuffer.contents()), count: resultsCount) // Our results in convenient form to compute the actual result later
let queue = device.newCommandQueue()
let cmds = queue.commandBuffer()
let encoder = cmds.computeCommandEncoder()
encoder.setComputePipelineState(pipeline)
encoder.setBuffer(dataBuffer, offset: 0, atIndex: 0)
encoder.setBytes(&dataCount, length: sizeofValue(dataCount), atIndex: 1)
encoder.setBuffer(resultsBuffer, offset: 0, atIndex: 2)
encoder.setBytes(&elementsPerSumC, length: sizeofValue(elementsPerSumC), atIndex: 3)
// We have to calculate the sum `resultCount` times => amount of threadgroups is `resultsCount`/`threadExecutionWidth` (rounded up) because each threadgroup will process `threadExecutionWidth` threads
let threadgroupsPerGrid = MTLSize(width: (resultsCount + pipeline.threadExecutionWidth - 1)/pipeline.threadExecutionWidth, height: 1, depth: 1)
// Here we set that each threadgroup should process `threadExecutionWidth` threads, the only important thing for performance is that this number is a multiple of `threadExecutionWidth` (here 1 times)
let threadsPerThreadgroup = MTLSize(width: pipeline.threadExecutionWidth, height: 1, depth: 1)
encoder.dispatchThreadgroups(threadgroupsPerGrid, threadsPerThreadgroup: threadsPerThreadgroup)
encoder.endEncoding()
var result : DataType = 0
cmds.commit()
cmds.waitUntilCompleted()
for elem in results {
result += elem
}
return result
}
func sumParralel1(data : Array<DataType>) -> UnsafeBufferPointer<DataType> {
let count = data.count
let elementsPerSum: Int = Int(sqrt(Double(count)))
let device = MTLCreateSystemDefaultDevice()!
let parsum = device.newDefaultLibrary()!.newFunctionWithName("parsum")!
let pipeline = try! device.newComputePipelineStateWithFunction(parsum)
var dataCount = CUnsignedInt(count)
var elementsPerSumC = CUnsignedInt(elementsPerSum)
let resultsCount = (count + elementsPerSum - 1)/elementsPerSum // Number of individual results = count/elementsPerSum (rounded up)
let dataBuffer = device.newBufferWithBytes(data, length: strideof(DataType) * count, options: []) // Our data in a buffer (copied)
let resultsBuffer = device.newBufferWithLength(strideof(DataType) * resultsCount, options: []) // A buffer for individual results (zero initialized)
let results = UnsafeBufferPointer<DataType>(start: UnsafePointer(resultsBuffer.contents()), count: resultsCount) // Our results in convenient form to compute the actual result later
let queue = device.newCommandQueue()
let cmds = queue.commandBuffer()
let encoder = cmds.computeCommandEncoder()
encoder.setComputePipelineState(pipeline)
encoder.setBuffer(dataBuffer, offset: 0, atIndex: 0)
encoder.setBytes(&dataCount, length: sizeofValue(dataCount), atIndex: 1)
encoder.setBuffer(resultsBuffer, offset: 0, atIndex: 2)
encoder.setBytes(&elementsPerSumC, length: sizeofValue(elementsPerSumC), atIndex: 3)
// We have to calculate the sum `resultCount` times => amount of threadgroups is `resultsCount`/`threadExecutionWidth` (rounded up) because each threadgroup will process `threadExecutionWidth` threads
let threadgroupsPerGrid = MTLSize(width: (resultsCount + pipeline.threadExecutionWidth - 1)/pipeline.threadExecutionWidth, height: 1, depth: 1)
// Here we set that each threadgroup should process `threadExecutionWidth` threads, the only important thing for performance is that this number is a multiple of `threadExecutionWidth` (here 1 times)
let threadsPerThreadgroup = MTLSize(width: pipeline.threadExecutionWidth, height: 1, depth: 1)
encoder.dispatchThreadgroups(threadgroupsPerGrid, threadsPerThreadgroup: threadsPerThreadgroup)
encoder.endEncoding()
cmds.commit()
cmds.waitUntilCompleted()
return results
}
func sumParallel3(data : Array<DataType>) -> DataType {
var results = sumParralel1(data)
repeat {
results = sumParralel1(Array(results))
} while results.count >= 100
var result : DataType = 0
for elem in results {
result += elem
}
return result
}
func sumParallel4(data : Array<DataType>) -> DataType {
let queue = NSOperationQueue()
queue.maxConcurrentOperationCount = 4
var a0 : DataType = 0
var a1 : DataType = 0
var a2 : DataType = 0
var a3 : DataType = 0
let op0 = NSBlockOperation(block : {
for i in 0..<(data.count/4) {
a0 = a0 + data[i]
}
})
let op1 = NSBlockOperation(block : {
for i in (data.count/4)..<(data.count/2) {
a1 = a1 + data[i]
}
})
let op2 = NSBlockOperation(block : {
for i in (data.count/2)..<(3 * data.count/4) {
a2 = a2 + data[i]
}
})
let op3 = NSBlockOperation(block : {
for i in (3 * data.count/4)..<(data.count) {
a3 = a3 + data[i]
}
})
queue.addOperation(op0)
queue.addOperation(op1)
queue.addOperation(op2)
queue.addOperation(op3)
queue.suspended = false
queue.waitUntilAllOperationsAreFinished()
let aaa: DataType = a0 + a1 + a2 + a3
return aaa
}
}
そして、私はこのようになりますシェーダ持っている:私の驚きの機能sumParallel4
で
kernel void parsum(const device DataType* data [[ buffer(0) ]],
const device uint& dataLength [[ buffer(1) ]],
device DataType* sums [[ buffer(2) ]],
const device uint& elementsPerSum [[ buffer(3) ]],
const uint tgPos [[ threadgroup_position_in_grid ]],
const uint tPerTg [[ threads_per_threadgroup ]],
const uint tPos [[ thread_position_in_threadgroup ]]) {
uint resultIndex = tgPos * tPerTg + tPos; // This is the index of the individual result, this var is unique to this thread
uint dataIndex = resultIndex * elementsPerSum; // Where the summation should begin
uint endIndex = dataIndex + elementsPerSum < dataLength ? dataIndex + elementsPerSum : dataLength; // The index where summation should end
for (; dataIndex < endIndex; dataIndex++)
sums[resultIndex] += data[dataIndex];
}
を、私はそれがshouldnと思った、最速でありますそうです。私が関数sumParralel
とsumParallel3
を呼び出すと、関数の順序を変更しても、最初の関数は常に遅くなることに気付きました。 (sumParral3を呼び出すと、最初はこれが遅くなりますが、これは遅いです。)
これはなぜですか?なぜsumParallel3はsumParallelよりずっと高速ではありませんか? sumParallel4はCPUで計算されますが、なぜ最速ですか?
posix_memalign
でGPU機能を更新するにはどうすればよいですか?私はそれがGPUとCPU間で共有メモリを持つので、より速く動作するはずですが、私は魔女の配列をこのように(データまたは結果)割り当てなければならないと、データが関数内で渡されたパラメータであればposix_memalign ?
呼び出しでグローバルオブジェクトを作成しているため、最初の実行が最も速いのは、2番目の実行でこれらのグローバルオブジェクトを作成する必要はなく、ただ要求するからです。 – Putz1103
これかもしれません! posix_memalignはどうですか?任意のアイデアをどのようにそれを使用するには? –
私はこれに全く経験はありませんが、このサイトはCPU/GPUのバッファ共有とメモリのアラインメントに関しては良い場所のようでした。 http://memkite.com/blog/2014/12/30/example-of-sharing-memory- between-gpu-and-cpu-with-swift-and-metal-for-ios8/幸運を祈る。 – Putz1103