2つの独立したmysqlテーブルからコンポジットデータを取得

Question

2つの異なるテーブルまたは独立したテーブルからコンポジットデータを取得したい。 ここに私のテーブル構造があります。

表1：この表データに

CREATE TABLE `keywords` (
    `id` int(11) NOT NULL AUTO_INCREMENT, 
    `keyword` varchar(255) NOT NULL DEFAULT '', 
    PRIMARY KEY (`id`), 
    UNIQUE KEY `keyword` (`keyword`) 
) 

は次のようである：

+----+---------+ 
| id | keyword | 
+----+---------+ 
| 2 | apple | 
| 1 | Banana | 
| 8 | ginger | 
| 6 | grapes | 
| 7 | guava | 
| 10 | milk | 
| 3 | onion | 
| 4 | potato | 
| 9 | tea  | 
| 5 | tomato | 
+----+---------+ 

表2。この表のデータで

CREATE TABLE `Rfps` (
    `id` int(11) NOT NULL AUTO_INCREMENT, 
    `subject` varchar(255) NOT NULL DEFAULT '', 
    PRIMARY KEY (`id`) 
) 

ようなものです：

+----+----------------------------------+ 
| id | subject       | 
+----+----------------------------------+ 
| 1 | I would like to have some banana | 
| 2 | I need some tea     | 
| 3 | I like grapes     | 
| 4 | yes. Beer, Banana, Onion   | 
| 5 | capsicum       | 
+----+----------------------------------+ 

私のモトは、これらのTABLE1のキーワードを持っている表2に対象者のIDを取得することです。

私が好きなクエリを作成しました：これは、その結果を与えている

select * from Rfps where CONCAT(subject) REGEXP (select GROUP_CONCAT(keyword SEPARATOR '|') as keyword from keywords); 

：

+----+----------------------------------+ 
| id | subject       | 
+----+----------------------------------+ 
| 1 | I would like to have some banana | 
| 2 | I need some tea     | 
| 3 | I like grapes     | 
| 4 | yes. Beer, Banana, Onion   | 
| 5 | capsicum       | 
+----+----------------------------------+ 

しかし、キーワードのID、またはキーワードを得ていません。

しかし、私は次のようにフェッチ場合：

+----+----------------------------------+----+---------+ 
| id | subject       | id | keyword | 
+----+----------------------------------+----+---------+ 
| 1 | I would like to have some banana | 2 | apple | 
| 2 | I need some tea     | 2 | apple | 
| 3 | I like grapes     | 2 | apple | 
| 4 | yes. Beer, Banana, Onion   | 2 | apple | 
| 1 | I would like to have some banana | 1 | Banana | 
| 2 | I need some tea     | 1 | Banana | 
| 3 | I like grapes     | 1 | Banana | 
| 4 | yes. Beer, Banana, Onion   | 1 | Banana | 
| 1 | I would like to have some banana | 8 | ginger | 
| 2 | I need some tea     | 8 | ginger | 
| 3 | I like grapes     | 8 | ginger | 
| 4 | yes. Beer, Banana, Onion   | 8 | ginger | 
| 1 | I would like to have some banana | 6 | grapes | 
| 2 | I need some tea     | 6 | grapes | 
| 3 | I like grapes     | 6 | grapes | 
| 4 | yes. Beer, Banana, Onion   | 6 | grapes | 
| 1 | I would like to have some banana | 7 | guava | 
| 2 | I need some tea     | 7 | guava | 
| 3 | I like grapes     | 7 | guava | 
| 4 | yes. Beer, Banana, Onion   | 7 | guava | 
| 1 | I would like to have some banana | 10 | milk | 
| 2 | I need some tea     | 10 | milk | 
| 3 | I like grapes     | 10 | milk | 
| 4 | yes. Beer, Banana, Onion   | 10 | milk | 
| 1 | I would like to have some banana | 3 | onion | 
| 2 | I need some tea     | 3 | onion | 
| 3 | I like grapes     | 3 | onion | 
| 4 | yes. Beer, Banana, Onion   | 3 | onion | 
| 1 | I would like to have some banana | 4 | potato | 
| 2 | I need some tea     | 4 | potato | 
| 3 | I like grapes     | 4 | potato | 
| 4 | yes. Beer, Banana, Onion   | 4 | potato | 
| 1 | I would like to have some banana | 9 | tea  | 
| 2 | I need some tea     | 9 | tea  | 
| 3 | I like grapes     | 9 | tea  | 
| 4 | yes. Beer, Banana, Onion   | 9 | tea  | 
| 1 | I would like to have some banana | 5 | tomato | 
| 2 | I need some tea     | 5 | tomato | 
| 3 | I like grapes     | 5 | tomato | 
| 4 | yes. Beer, Banana, Onion   | 5 | tomato | 
+----+----------------------------------+----+---------+ 

繰り返し行：

select Rfps.id,Rfps.subject,keywords.id,keywords.keyword from Rfps,keywords where CONCAT(subject) REGEXP (select GROUP_CONCAT(keyword SEPARATOR '|') as keyword from keywords); 

これは、データを与えています。

Answer 1

CONCAT()文字列をまとめています。それを1つの列だけにすることは役に立たず、索引の潜在的な使用を防ぎます。
Regexpもまた過剰です。代わりにLIKEを使用してください。 、編集男のための感謝を

select 
* 
from 
keywords k 
join Rfps r on r.subject like concat('%', k.keyword, '%');