連続した不連続な日付範囲を特定します

Question

xという名前のテーブルがあります。データは以下の通りです。私は現在、不連続なデータを識別するために、次のクエリを使用し

Acccount_num start_dt end_dt 
A111326  02/01/2016 02/11/2016 
A111326  02/12/2016 03/05/2016 
A111326  03/02/2016 03/16/2016 
A111331  02/28/2016 02/29/2016 
A111331  02/29/2016 03/29/2016 
A999999  08/25/2015 08/25/2015 
A999999  12/19/2015 12/22/2015 
A222222  11/06/2015 11/10/2015 
A222222  05/16/2016 05/17/2016 

両方A111326 A111331とは、連続したデータとして識別されなければならないとA999999と
A222222は、私のコードdata.In不連続として識別されなければなりません。また、A111326は不連続なデータとして誤って識別されます。 A111326が不連続なデータとして識別されないように、以下のコードを変更するのを手伝ってください。事前に助けていただきありがとうございます。あなたの問題の

(SELECT account_num 
       FROM (SELECT account_num, 
          (MAX (
           END_DT) 
           OVER (PARTITION BY account_num 
            ORDER BY START_DT)) 
           START_DT, 
          (LEAD (
           START_DT) 
           OVER (PARTITION BY account_num 
            ORDER BY START_DT)) 
           END_DT 
         FROM x 
         WHERE (START_DT + 1) <= 
           (END_DT - 1)) 
       WHERE START_DT < END_DT); 

Answer 1

WITH cte AS (
    SELECT 
     AccountNumber 
     ,CASE 
      WHEN 
      LAG(End_Dt) OVER (PARTITION BY AccountNumber ORDER BY End_Dt) IS NULL THEN 0 
      WHEN 
      LAG(End_Dt) OVER (PARTITION BY AccountNumber ORDER BY End_Dt) >= Start_Dt - 1 THEN 0 
      ELSE 1 
     END as discontiguous 
    FROM 
     #Table 
) 

SELECT 
    AccountNumber 
    ,CASE WHEN SUM(discontiguous) > 0 THEN 'discontiguous' ELSE 'contiguous' END 
FROM 
    cte 
GROUP BY 
    AccountNumber; 

Oneを連続した所望の結果はまた、あなたの例のデータセット内の重複日付範囲が含まれていることです。例A1113263/2/2016で始まり、前に行を終了して3/5/2015と重複していることを意味します。

Answer 2

Oracleのセットアップ：

CREATE TABLE accounts (Account_num, start_dt, end_dt) AS 
SELECT 'A', DATE '2016-02-01', DATE '2016-02-11' FROM DUAL UNION ALL 
SELECT 'A', DATE '2016-02-12', DATE '2016-03-05' FROM DUAL UNION ALL 
SELECT 'A', DATE '2016-03-02', DATE '2016-03-16' FROM DUAL UNION ALL 
SELECT 'B', DATE '2016-02-28', DATE '2016-02-29' FROM DUAL UNION ALL 
SELECT 'B', DATE '2016-02-29', DATE '2016-03-29' FROM DUAL UNION ALL 
SELECT 'C', DATE '2015-08-25', DATE '2015-08-25' FROM DUAL UNION ALL 
SELECT 'C', DATE '2015-12-19', DATE '2015-12-22' FROM DUAL UNION ALL 
SELECT 'D', DATE '2015-11-06', DATE '2015-11-10' FROM DUAL UNION ALL 
SELECT 'D', DATE '2016-05-16', DATE '2016-05-17' FROM DUAL UNION ALL 
SELECT 'E', DATE '2016-01-01', DATE '2016-01-02' FROM DUAL UNION ALL 
SELECT 'E', DATE '2016-01-05', DATE '2016-01-06' FROM DUAL UNION ALL 
SELECT 'E', DATE '2016-01-03', DATE '2016-01-07' FROM DUAL; 

クエリ：

WITH times (account_num, dt, lvl) AS (
    SELECT Account_num, start_dt - 1, 1 FROM accounts 
UNION ALL 
    SELECT Account_num, end_dt,  -1 FROM accounts 
) 
, totals (account_num, dt, total) AS (
    SELECT account_num, 
     dt, 
     SUM(lvl) OVER (PARTITION BY Account_num ORDER BY dt, lvl DESC) 
    FROM times 
) 
SELECT Account_num, 
     CASE WHEN COUNT(CASE total WHEN 0 THEN 1 END) > 1 
      THEN 'N' 
      ELSE 'Y' 
      END AS is_contiguous 
FROM totals 
GROUP BY Account_Num 
ORDER BY Account_Num; 

出力：

ACCOUNT_NUM IS_CONTIGUOUS 
----------- ------------- 
A   Y 
B   Y 
C   N 
D   N 
E   Y 

もうひとつのクエリ：

（それはちょうどUNION ALLではなくUNPIVOTを使用して、まったく同じ方法です。）

SELECT Account_num, 
     CASE WHEN COUNT(CASE total WHEN 0 THEN 1 END) > 1 
      THEN 'N' 
      ELSE 'Y' 
      END AS is_contiguous 
FROM (
    SELECT Account_num, 
     SUM(lvl) OVER (PARTITION BY Account_Num 
          ORDER BY CASE lvl WHEN 1 THEN dt - 1 ELSE dt END, 
            lvl DESC 
         ) AS total 
    FROM accounts 
    UNPIVOT (dt FOR lvl IN (start_dt AS 1, end_dt AS -1)) 
) 
GROUP BY Account_Num 
ORDER BY Account_Num;