C文字配列内の重複する文字を削除します。

Question

テキストファイルには "abbcccdddd"があります。私は "abcd"を配列に格納したい。前

：TX [0]、TX [1] = B、TX [3] = Cを、TX [6] =後D

=：TX [0] TX、=を[1] = b、tx [2] = c、tx [3] = d

#include <stdio.h> 
#include <string.h> 
#include <stdlib.h> 

void main() 
{ 
    FILE *fp = fopen("D:\\C#\\Zip\\Text001.txt", "r"); 
    char x; 
    int size; 
    int j, k; 
    int i = 0; 

    fseek(fp, 0, SEEK_END); 
    size = ftell(fp); 
    fseek(fp, 0, SEEK_SET); 
    char tx[size]; 
    x = fgetc(fp); 

    while (x != EOF) 
    { 
     tx[i] = x; 
     printf("%c", tx[i]); 
     x = fgetc(fp); 
     i++; 
    } 
} 

Answer 1

remove_repeatation（）がこれを行います。

void remove_repeatation(char *str) 
{ 
    char flag[256] = {0}; //Assuming sizeof char is 8. So max 256 different characters. 
    int i   = 0; 
    int j   = 0; 

    for(i=0; str[i] != '\0';) 
    { 
     if(0 == flag[str[i]]) //Check if character is already found. 
     { 
      flag[str[i]] = 1; //If a character is found for the first time, enable corresponding flag. 
      i++; //Go to next byte in the array. 
     } 
     else 
     { 
      for(j=i; str[j] != '\0'; j++) 
       str[j] = str[j+1]; //If repeated character, shift the array entries to 1 byte left. 
     } 
    } 
} 

Answer 2

MayurKことによって、上記のコードの編集：

char* remove_repeatation(char *str) 
{ 
    char flag[256] = {0}; //Assuming sizeof char is 8. So max 256 different characters. 
    int i   = 0; 
    int j   = 0; 

    for(i=0; str[i] != '\0'; i++) 
    { 
     if(0 == flag[str[i]]) //Check if character is already found. 
     { 
      flag[str[i]] = 1; //If a character is found for the first time, enable corresponding flag. 
      str[j] = str[i]; 
      j++; 
     } 
    } 
    str[j] = '\0'; 
    return *str; 
}