1列に同じ値を持つ複数の行

Question

こんにちは私は以下のケースで問題があります。 は私が見つける「n」を1つのAPPLICATION_NAMEのステータスを失敗した必然的な結果として、それを返す必要が

App_name  date   status 
Application 1 10-MAR-17 SUCCEEDED 
Application 1 11-MAR-17 SUCCEEDED 
Application 1 12-MAR-17 FAILED 
Application 1 13-MAR-17 SUCCEEDED 
Application 1 14-MAR-17 SUCCEEDED 
Application 1 15-MAR-17 FAILED 
Application 1 16-MAR-17 SUCCEEDED 
Application 1 17-MAR-17 SUCCEEDED 
Application 1 18-MAR-17 FAILED 
Application 1 19-MAR-17 SUCCEEDED 
Application 1 20-MAR-17 SUCCEEDED 
Application 1 21-MAR-17 FAILED 
Application 1 22-MAR-17 SUCCEEDED 
Application 1 23-MAR-17 SUCCEEDED 
Application 1 25-MAR-17 SUCCEEDED 
Application 3 20-MAR-17 FAILED 
Application 3 21-MAR-17 FAILED 
Application 3 22-MAR-17 FAILED 
Application 3 23-MAR-17 FAILED 
Application 3 24-MAR-17 FAILED 

ように、テーブル「アプリケーションログ」を持っています。たとえば、n = 5の場合、クエリはapp_name = Application 3を返す必要があります。

Answer 1

次のクエリはSQL Serverで機能します。これは、単一のOLAP機能を利用し、別のアプローチである

SELECT [App_name] 
FROM (
    SELECT [App_name], [date], [status], 
      ROW_NUMBER() OVER (PARTITION BY App_name ORDER BY [date]) 
      - 
      ROW_NUMBER() OVER (PARTITION BY App_name, 
              CASE 
              WHEN status = 'FAILED' THEN 1 
              ELSE 2 
              END 
          ORDER BY [date]) AS grp 
    FROM ApplicationLog) AS t 
WHERE status = 'FAILED' 
GROUP BY [App_name], grp 
HAVING COUNT(*) >= 5 

Demo here

Answer 2

：

SELECT App_name, Max(date) AS LastFail 
FROM 
(
    SELECT App_name, date, status, 
     -- check if the last 5 rows only contain FAILED 
      Min(CASE WHEN status = 'FAILED' THEN 1 ELSE 0 end) 
      Over (PARTITION BY App_name 
       ORDER BY date 
     -- caution, as this includes the current row it must be n-1 
       ROWS 4 Preceding) AS x 
    FROM ApplicationLog 
) AS t 
WHERE x = 1 
GROUP BY App_name