のmysql - グループが、私はグループフィールドにしたいが、列のすべての行を表示したい列

Question

のすべての行がremainと呼ばれる示しています。ここ

をグループ化することなく、電流出力です：

グループと

そして出力：

そして、私はこれをしたいとき、Iグループ：

ここ

は、MySQLのクエリです：

SELECT staff.name, 
    staff.designation_id_designation, 
    staff.status_id_status, 
    Concat_Ws('=', leave_remain.leave_type_id_leave_type, leave_remain.days) AS 
    remain 
FROM staff INNER JOIN 
    leave_remain ON staff.id_staff = leave_remain.staff_id_staff 
GROUP BY staff.name  

Answer 1

使用GROUP_CONCAT

SELECT staff.name, 
     staff.designation_id_designation, 
     staff.status_id_status, 
     GROUP_CONCAT(Concat_Ws('=', leave_remain.leave_type_id_leave_type, leave_remain.days)) AS remain 
FROM staff 
     INNER JOIN leave_remain 
      ON staff.id_staff = leave_remain.staff_id_staff 
GROUP BY staff.name, staff.designation_id_designation, staff.status_id_status 

• SQLFiddle Demo

他のリンク（S）

• MySQL GROUP_CONCAT

Answer 2

これを試してみてください：

SELECT staff.name, 
    staff.designation_id_designation, 
    staff.status_id_status, 
    GROUP_CONCAT(Concat_Ws('=', leave_remain.leave_type_id_leave_type, leave_remain.days) SEPARATOR ' ') AS remain 
FROM staff INNER JOIN 
    leave_remain ON staff.id_staff = leave_remain.staff_id_staff 
GROUP BY staff.designation_id_designation, 
     staff.name, 
     staff.status_id_status; 

Answer 3

しようと、この本のために、我々は '' でgroup_contact別々に使用する必要があります。

SELECT staff.name, 
    staff.designation_id_designation, 
    staff.status_id_status, 
    GROUP_CONCAT(Concat_Ws('=', leave_remain.leave_type_id_leave_type, leave_remain.days) SEPARATOR ' ') AS remain 
FROM staff 
INNER JOIN 
    leave_remain 
ON 
staff.id_staff = leave_remain.staff_id_staff 
GROUP BY staff.designation_id_designation, 
     staff.name, 
     staff.status_id_status;