すべての入力が空でないかどうかを確認する単純な検証を追加するにはどうすればよいですか?PHPで単純な検証を追加するには?
私は、少なくとも1つのフォームが空であれば、PHPファイルにエラーを表示する簡単な検証を目指しています。すべてが完全に満たされたときに入力をデータベースに追加します。 htmlフォームのフォームフィールドに入力するたびに変数を設定しました。
HTMLコード:
<html>
<head>
<title>FEATHER FRIENDS PIZZA SHOP</title>
</head>
<img src="pics/logo.png">
<style>
img {
display: block;
margin: auto;
width:100%;
}
input[type=text], select {
width: 100%;
padding: 12px 20px;
margin: 8px 0;
display: inline-block;
border: 1px solid #ccc;
border-radius: 4px;
box-sizing: border-box;
}
input[type=submit] {
width: 100%;
background-color: #4CAF50;
color: white;
padding: 14px 20px;
margin: 8px 0;
border: none;
border-radius: 4px;
cursor: pointer;
}
input[type=reset] {
width: 100%;
background-color: #bfac2c;
color: white;
padding: 14px 20px;
margin: 8px 0;
border: none;
border-radius: 4px;
cursor: pointer;
}
input[type=reset]:hover {
background-color: #c43848;
}
input[type=submit]:hover {
background-color: #c43848;
}
div {
background-image: url('pics/bg.png');
background-attachment: fixed;
background-repeat: no-repeat;
background-size: 100% 100%;
padding: 100px;
}
body {
display: block;
margin: auto;
width: 100%;
height: 100%;
background-color: #f6f6d4;
background-attachment: fixed;
background-repeat: no-repeat;
background-size: 100% 100%;
}
</style>
<div>
<body>
<img src="pics/pizza.png">
<form action="http://localhost/insert.php" method="post">
<img src="pics/name.png">
<input type="text" id="fname" name="name" placeholder="Your full name...">
<img src="pics/size.png">
<select id="size" name="size">
<option value="small">Small</option>
<option value="medium">Medium</option>
<option value="large">Large</option>
<option value="extra large">Extra Large</option>
</select>
<img src="pics/crust.png">
<select id="crust" name="crust">
<option value="pan">Pan</option>
<option value="thin">Thin</option>
<option value="stuffed">Stuffed</option>
<option value="handtossed">Hand-Tossed</option>
<option value="deepdish">Deep Dish</option>
</select>
<img src="pics/garnish.png">
<input type="text" id="garnish" name="garnish" placeholder="Write your choices here! Ex: Pepperoni, Cheese, Bacon, Mushroom">
<img src="pics/address.png">
<input type="text" id="address" name="address" placeholder="Where should we deliver?">
<img src="pics/contact.png">
<input type="text" id="contact" name="contact" placeholder="What is your contact number?">
<input type="submit" value="Submit">
<input type="reset" value="Reset your Order?">
</form>
</div>
</body>
</html>
PHPコード:ここで
<?php
$link = mysqli_connect("localhost", "root", "", "pizza");
if($link === false){
die("ERROR: Could not connect. " . mysqli_connect_error());
}
$name = mysqli_real_escape_string($link, $_POST['name']);
$size = mysqli_real_escape_string($link, $_POST['size']);
$crust = mysqli_real_escape_string($link, $_POST['crust']);
$garnish = mysqli_real_escape_string($link, $_POST['garnish']);
$address = mysqli_real_escape_string($link, $_POST['address']);
$contact = mysqli_real_escape_string($link, $_POST['contact']);
$sql = "INSERT INTO deliver (name, size, crust, garnish, address, contact)
VALUES ('$name', '$size', '$crust', '$garnish', '$address', '$contact')";
if(mysqli_query($link, $sql)){
echo "Data successfully Saved.";
} else{
echo "ERROR: Could not able to execute $sql. " . mysqli_error($link);
}
mysqli_close($link);
?>
はこれをフォロー: https://stackoverflow.com/questions/19790601/php-simple-form-validation – Saurabh