xsd.exeから派生したxsd.exeからXMLをデシリアライズする際にエラーが発生しました。

Question

私はこの問題の回答をすべて読みましたが、私の場合はすべて解決しましたが（良い解決策ですが）、

私はそれの関連する部分を投稿しますので、それは7000+ラインのクラスを生成し

Xsd.exeでは/ C neworder.xsd

と私のXSDファイルからのAC＃クラスを作成しました。ほんの少しの抜粋です

using System; 
using System.Diagnostics; 
using System.Xml.Serialization; 
using System.Collections; 
using System.Xml.Schema; 
using System.ComponentModel; 
using System.IO; 
using System.Text; 
using System.Xml; 
using System.Collections.Generic; 


[System.CodeDom.Compiler.GeneratedCodeAttribute("System.Xml", "4.0.30319.34234")] 
[System.SerializableAttribute()] 
[System.ComponentModel.DesignerCategoryAttribute("code")] 
[System.Xml.Serialization.XmlTypeAttribute(AnonymousType = true, Namespace = "http://www.foo.com/schemas/w/v1.0")] 
[System.Xml.Serialization.XmlRootAttribute("new-order", Namespace = "http://www.foo.com/schemas/w/v1.0")] 
public partial class neworder 
{ 

    private List<customertype> customersField; 

    private string suppliercodeField; 

    private string versionField; 

    private static System.Xml.Serialization.XmlSerializer serializer; 

    public neworder() 
    { 
     this.customersField = new List<customertype>(); 
    } 

    [System.Xml.Serialization.XmlArrayAttribute(Order = 0)] 
    [System.Xml.Serialization.XmlArrayItemAttribute("customer",IsNullable = false)] 
    public List<customertype> customers 
    { 
     get 
     { 
      return this.customersField; 
     } 
     set 
     { 
      this.customersField = value; 
     } 
    } 

    [System.Xml.Serialization.XmlAttributeAttribute("supplier-code")] 
    public string suppliercode 
    { 
     get 
     { 
      return this.suppliercodeField; 
     } 
     set 
     { 
      this.suppliercodeField = value; 
     } 
    } 

    [System.Xml.Serialization.XmlAttributeAttribute("version")] 
    public string version 
    { 
     get 
     { 
      return this.versionField; 
     } 
     set 
     { 
      this.versionField = value; 
     } 
    } 

    private static System.Xml.Serialization.XmlSerializer Serializer 
    { 
     get 
     { 
      if ((serializer == null)) 
      { 
       serializer = new System.Xml.Serialization.XmlSerializer(typeof(neworder)); 
      } 
      return serializer; 
     } 
    } 
public static neworder Deserialize(string xml) 
     { 
      System.IO.StringReader stringReader = null; 
      try 
      { 
       stringReader = new System.IO.StringReader(xml); 
       return ((neworder)(Serializer.Deserialize(System.Xml.XmlReader.Create(stringReader)))); 
      } 
      finally 
      { 
       if ((stringReader != null)) 
       { 
        stringReader.Dispose(); 
       } 
      } 
     } 

私はこれを解決しますならば、私は残りの部分を解決することができるように感じるように、残りは今それは重要ではありません。

これは私が私が手にエラーが悪名高いです以下

XmlSerializer ser = new XmlSerializer(typeof(neworder)); 
    neworder feed = (neworder)ser.Deserialize(new FileStream(filePath, FileMode.Open)) ; 

でそれをデシリアライズしよう

<new-order xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://www.foo.com/schema/w/v1.0" version="1.0" supplier-code="FAKECODE" schemaLocation="http://www.foo.com/schemas/w/v1.0/TransmissionEnvelope.xsd"> 
    <customers> 
    <customer w-number="123456" customer-number="12345-12345"> 
     <client-info> 
     <client-name>John Doe</client-name> 
     <w-id>433348</w-id> 
     </client-info> 
     <transferee-name> 
     <first>John</first> 
     <last>Doe</last> 
     </transferee-name> 
     <spouse-name> 
     <first /> 
     <last /> 
     </spouse-name> 
     <o-address> 
     <street1>123 Fake st</street1> 
     <city>Fakeville</city> 
     <state>CA</state> 
     <postal-code>90210</postal-code> 
     <country>USA</country> 
     </o-address> 
     <d-address> 
     <street1 /> 
     <city>harbour</city> 
     <state>VA</state> 
     <postal-code>55555</postal-code> 
     <country>USA</country> 
     </d-address> 
     <contact-info> 
     <phone> 
      <phone-type>CELL</phone-type> 
      <phone-number>555-555-5555</phone-number> 
     </phone> 
     <phone> 
      <phone-type>HOME</phone-type> 
      <phone-number>555-555-5555</phone-number> 
     </phone> 
     <phone> 
      <phone-type>WORK</phone-type> 
      <phone-number /> 
     </phone> 
     <email>johndoe@email.com</email> 
     <comments>Just any comments here</comments> 
     </contact-info> 

    </customer> 
    </customers> 
</new-order> 

XMLファイルの先頭部分である：

ありXML文書のエラーです（1,2）。 http://www.foo.com/schema/w/v1.0 '>は期待されていませんでした。

私は、上記のことを行う属性XMLROOTとしてルートノートを確認することについて何度も何度も読んできました。そしてそれには正しい名前空間があります。

XmlRootAttributeをXmlRootに変更しようとしました。何もない。 私は名前空間を削除して、クラスを再実行しようとしましたが、何もしませんでした。

すべてが正当だと思われるので、ここで間違っているかもしれないことに私の脳を壊す。

Answer 1

....これを試してみてください

使用.....

using System; 
using System.Collections.Generic; 
using System.IO; 
using System.Linq; 
using System.Text; 
using System.Threading.Tasks; 
using System.Xml; 
using System.Xml.Serialization; 

クラス.....

[XmlRoot(ElementName = "client-info", Namespace = "http://www.foo.com/schema/w/v1.0")] 
public class Clientinfo 
{ 
    [XmlElement(ElementName = "client-name", Namespace = "http://www.foo.com/schema/w/v1.0")] 
    public string Clientname { get; set; } 
    [XmlElement(ElementName = "w-id", Namespace = "http://www.foo.com/schema/w/v1.0")] 
    public string Wid { get; set; } 
} 

[XmlRoot(ElementName = "transferee-name", Namespace = "http://www.foo.com/schema/w/v1.0")] 
public class Transfereename 
{ 
    [XmlElement(ElementName = "first", Namespace = "http://www.foo.com/schema/w/v1.0")] 
    public string First { get; set; } 
    [XmlElement(ElementName = "last", Namespace = "http://www.foo.com/schema/w/v1.0")] 
    public string Last { get; set; } 
} 

[XmlRoot(ElementName = "spouse-name", Namespace = "http://www.foo.com/schema/w/v1.0")] 
public class Spousename 
{ 
    [XmlElement(ElementName = "first", Namespace = "http://www.foo.com/schema/w/v1.0")] 
    public string First { get; set; } 
    [XmlElement(ElementName = "last", Namespace = "http://www.foo.com/schema/w/v1.0")] 
    public string Last { get; set; } 
} 

[XmlRoot(ElementName = "o-address", Namespace = "http://www.foo.com/schema/w/v1.0")] 
public class Oaddress 
{ 
    [XmlElement(ElementName = "street1", Namespace = "http://www.foo.com/schema/w/v1.0")] 
    public string Street1 { get; set; } 
    [XmlElement(ElementName = "city", Namespace = "http://www.foo.com/schema/w/v1.0")] 
    public string City { get; set; } 
    [XmlElement(ElementName = "state", Namespace = "http://www.foo.com/schema/w/v1.0")] 
    public string State { get; set; } 
    [XmlElement(ElementName = "postal-code", Namespace = "http://www.foo.com/schema/w/v1.0")] 
    public string Postalcode { get; set; } 
    [XmlElement(ElementName = "country", Namespace = "http://www.foo.com/schema/w/v1.0")] 
    public string Country { get; set; } 
} 

[XmlRoot(ElementName = "d-address", Namespace = "http://www.foo.com/schema/w/v1.0")] 
public class Daddress 
{ 
    [XmlElement(ElementName = "street1", Namespace = "http://www.foo.com/schema/w/v1.0")] 
    public string Street1 { get; set; } 
    [XmlElement(ElementName = "city", Namespace = "http://www.foo.com/schema/w/v1.0")] 
    public string City { get; set; } 
    [XmlElement(ElementName = "state", Namespace = "http://www.foo.com/schema/w/v1.0")] 
    public string State { get; set; } 
    [XmlElement(ElementName = "postal-code", Namespace = "http://www.foo.com/schema/w/v1.0")] 
    public string Postalcode { get; set; } 
    [XmlElement(ElementName = "country", Namespace = "http://www.foo.com/schema/w/v1.0")] 
    public string Country { get; set; } 
} 

[XmlRoot(ElementName = "phone", Namespace = "http://www.foo.com/schema/w/v1.0")] 
public class Phone 
{ 
    [XmlElement(ElementName = "phone-type", Namespace = "http://www.foo.com/schema/w/v1.0")] 
    public string Phonetype { get; set; } 
    [XmlElement(ElementName = "phone-number", Namespace = "http://www.foo.com/schema/w/v1.0")] 
    public string Phonenumber { get; set; } 
} 

[XmlRoot(ElementName = "contact-info", Namespace = "http://www.foo.com/schema/w/v1.0")] 
public class Contactinfo 
{ 
    [XmlElement(ElementName = "phone", Namespace = "http://www.foo.com/schema/w/v1.0")] 
    public List<Phone> Phone { get; set; } 
    [XmlElement(ElementName = "email", Namespace = "http://www.foo.com/schema/w/v1.0")] 
    public string Email { get; set; } 
    [XmlElement(ElementName = "comments", Namespace = "http://www.foo.com/schema/w/v1.0")] 
    public string Comments { get; set; } 
} 

[XmlRoot(ElementName = "customer", Namespace = "http://www.foo.com/schema/w/v1.0")] 
public class Customer 
{ 
    [XmlElement(ElementName = "client-info", Namespace = "http://www.foo.com/schema/w/v1.0")] 
    public Clientinfo Clientinfo { get; set; } 
    [XmlElement(ElementName = "transferee-name", Namespace = "http://www.foo.com/schema/w/v1.0")] 
    public Transfereename Transfereename { get; set; } 
    [XmlElement(ElementName = "spouse-name", Namespace = "http://www.foo.com/schema/w/v1.0")] 
    public Spousename Spousename { get; set; } 
    [XmlElement(ElementName = "o-address", Namespace = "http://www.foo.com/schema/w/v1.0")] 
    public Oaddress Oaddress { get; set; } 
    [XmlElement(ElementName = "d-address", Namespace = "http://www.foo.com/schema/w/v1.0")] 
    public Daddress Daddress { get; set; } 
    [XmlElement(ElementName = "contact-info", Namespace = "http://www.foo.com/schema/w/v1.0")] 
    public Contactinfo Contactinfo { get; set; } 
    [XmlAttribute(AttributeName = "w-number")] 
    public string Wnumber { get; set; } 
    [XmlAttribute(AttributeName = "customer-number")] 
    public string Customernumber { get; set; } 
} 

[XmlRoot(ElementName = "customers", Namespace = "http://www.foo.com/schema/w/v1.0")] 
public class Customers 
{ 
    [XmlElement(ElementName = "customer", Namespace = "http://www.foo.com/schema/w/v1.0")] 
    public Customer Customer { get; set; } 
} 

[XmlRoot(ElementName = "new-order", Namespace = "http://www.foo.com/schema/w/v1.0")] 
public class Neworder 
{ 
    [XmlElement(ElementName = "customers", Namespace = "http://www.foo.com/schema/w/v1.0")] 
    public Customers Customers { get; set; } 
    [XmlAttribute(AttributeName = "xsi", Namespace = "http://www.w3.org/2000/xmlns/")] 
    public string Xsi { get; set; } 
    [XmlAttribute(AttributeName = "xmlns")] 
    public string Xmlns { get; set; } 
    [XmlAttribute(AttributeName = "version")] 
    public string Version { get; set; } 
    [XmlAttribute(AttributeName = "supplier-code")] 
    public string Suppliercode { get; set; } 
    [XmlAttribute(AttributeName = "schemaLocation")] 
    public string SchemaLocation { get; set; } 
} 

コード（あなたが投稿したXML用） .....

 string strXML = File.ReadAllText("xml.xml"); 
     byte[] bufXML = ASCIIEncoding.UTF8.GetBytes(strXML); 
     MemoryStream ms1 = new MemoryStream(bufXML); 

     // Deserialize to object 
     XmlSerializer serializer = new XmlSerializer(typeof(Neworder)); 
     try 
     { 
      using (XmlReader reader = new XmlTextReader(ms1)) 
      { 
       Neworder deserializedXML = (Neworder)serializer.Deserialize(reader); 

      }// put a break point here and mouse-over deserializedXML…. 
     } 
     catch (Exception ex) 
     { 
      throw; 
     } 

私はあなたのXMLを文字列から読み込んでいますxml.xmlと呼ばれるアプリケーションビルドフォルダ内のファイル...他の場所からXML文字列を取得するか、xml.xmlファイルを作成して上記のコードをXMLに保存する必要があります。