6
問題:生のIDフィールドではなく、結合された答えを作成したい場合を除いて、意図したとおりに動作するGROUP_CONCATクエリがあります。内部結合をmySQL GROUP_CONCAT文に追加
現在のクエリ:
SELECT user.user_id, user.user, GROUP_CONCAT(user_roles.roleID separator ', ') roles
FROM user
JOIN user_roles ON user.user_ID = user_roles.user_ID
GROUP BY users.user_ID, users.user
は結果を与える:
+----------+---------+----------------------------+
| user_ID | user | roles |
+----------+---------+----------------------------+
| 1 | Smith | 1, 3 |
+----------+---------+----------------------------+
| 2 | Jones | 1, 2, 3 |
+----------+---------+----------------------------+
望ましい結果:
+----------+---------+----------------------------+
| user_ID | user | roles |
+----------+---------+----------------------------+
| 1 | Smith | Admin, Other |
+----------+---------+----------------------------+
| 2 | Jones | Admin, Staff, Other |
+----------+---------+----------------------------+
Userテーブル:
+----------+---------+
| user_ID | user |
+----------+---------+
| 1 | Smith |
+----------+---------+
| 2 | Jones |
+----------+---------+
*がテーブルをusers_roles:*
+----------+---------+
| user_ID | role_ID |
+----------+---------+
| 1 | 1 |
+----------+---------+
| 2 | 1 |
+----------+---------+
| 2 | 2 |
+----------+---------+
| 2 | 3 |
+----------+---------+
| 1 | 3 |
+----------+---------+
役割テーブル:
+----------+-----------+
| role_ID | role_name |
+----------+-----------+
| 1 | Admin |
+----------+-----------+
| 2 | Staff |
+----------+-----------+
| 3 | Other |
+----------+-----------+
THAを試してみてくださいnks Vikram - これは動作します – Laurence