どうすれば私のアンドロイドアプリからokhttpでPHPサーバーにデータを投稿できますか？

Question

私はokhttpを使ってサーバからデータを投稿して取得するために以下のコードを書いていますが、動作していません。 NewTest.java

public class NewTest extends AppCompatActivity { 

    TextView txtJson; 
    Button btnOkay; 

    @Override 
    protected void onCreate(Bundle savedInstanceState) { 
     super.onCreate(savedInstanceState); 
     setContentView(R.layout.activity_new_test); 

     txtJson= (TextView) findViewById(R.id.txtJson); 

     findViewById(R.id.txtJson)).getText().toString()); 

     assert (findViewById(R.id.btnOkay)) != null; 
     (findViewById(R.id.btnOkay)).setOnClickListener(new View.OnClickListener() { 
      @Override 
      public void onClick(View v) { 

       new TaskPostWebService("url written here").execute(((TextView) findViewById(R.id.txtJson)).getText().toString()); 
      } 
     }); 

    } 

    private class TaskWebServiceGet extends AsyncTask<String,Void,String> { 

     @Override 
     protected void onPreExecute() 
     { 
      super.onPreExecute(); 
     } 

     @Override 
     protected String doInBackground(String... params) { 

      try { 

       OkHttpClient client = new OkHttpClient(); 

       Request request = new Request.Builder() 
         .url(params[0]) 
         .build(); 

       Response response = client.newCall(request).execute(); 

       String responseJson = response.body().string(); 
       Log.i("@", "" + responseJson); 
      } 
      catch (Exception e){ 

       e.printStackTrace(); 
      } 
      return null; 
     } 

     @Override 
     protected void onPostExecute(String s) { 
      super.onPostExecute(s); 
     } 
    } 

    private class TaskPostWebService extends AsyncTask<String,Void,String> { 
     private String url; 
     private ProgressDialog progressDialog; 

     public TaskPostWebService(String url){ 

      this.url = url; 
     } 
     @Override 
     protected void onPreExecute() { 
      super.onPreExecute(); 
      progressDialog = ProgressDialog.show(NewTest.this,"",""); 
     } 

     @Override 
     protected String doInBackground(String... params) { 

      String fact = ""; 
      try { 

       OkHttpClient client = new OkHttpClient(); 

       RequestBody body = new FormBody.Builder() 
         .add("\"nonce\" : \"G9Ivek\",", params[0]) 
         .add("\"iUserId \": \"477\",", params[1]) 

          .build(); 

       Request request = new Request.Builder() 
         .url(url) 
         .post(body) 
         .build(); 

       Response response = client.newCall(request).execute(); // hits server 

       String json = response.body().string(); // server gives response 

       ObjectMapper mapper = new ObjectMapper(); 
       Map<String,String> map = mapper.readValue(json, new TypeReference<Map>() { // convert json to object 
       }); 

       if(map != null){ 

        fact = map.get("gruesomeFact"); 

       } 
       Log.i("@",""+json); 
      } 
      catch (Exception e){ 
       e.printStackTrace(); 
      } 
      return fact; 
     } 
     @Override 
     protected void onPostExecute(String s) { 
      super.onPostExecute(s); 

      TextView text = (TextView) findViewById(R.id.txtJson); 
      text.setText(s); 
      progressDialog.dismiss(); 
     } 
    } 

} 

では、私はアクセス拒否メッセージを取得しています。

誰かが間違っていることを教えてもらえますか？

Answer 1

回答は以下の通りです。出来た。 今、私はlistviewでレスポンスを表示したいと思います。これを行う方法？

*/publicクラス NewTestはAppCompatActivity {

TextView txtJson; 
    Button btnOkay; 

    @Override 
    protected void onCreate(Bundle savedInstanceState) { 
     super.onCreate(savedInstanceState); 
     setContentView(R.layout.activity_new_test); 

     txtJson= (TextView) findViewById(R.id.txtJson); 


     assert (findViewById(R.id.btnOkay)) != null; 
     (findViewById(R.id.btnOkay)).setOnClickListener(new View.OnClickListener() { 
      @Override 
      public void onClick(View v) { 

       new TaskPostWebService("written url here").execute(((TextView) 
findViewById(R.id.txtJson)).getText().toString()); 

      } 
     }); 

    } 
    private class TaskPostWebService extends AsyncTask<String,Void,String> { 

     private String url; 
     private ProgressDialog progressDialog; 
     private JSONParser jsonParser; 

     public TaskPostWebService(String url){ 

      this.url = url; 
     } 
     @Override 
     protected void onPreExecute() { 
      super.onPreExecute(); 
      progressDialog = ProgressDialog.show(NewTest.this,"",""); 
     } 

     @Override 
     protected String doInBackground(String... params) { 

     String fact = ""; 
      try { 

       final MediaType JSON = MediaType.parse("application/json"); 

       android.util.Log.e("charset", "charset - " + JSON.charset()); 
       OkHttpClient client = new OkHttpClient(); 

//Create a JSONObject with the data to be sent to the server 
       final JSONObject dataToSend = new JSONObject() 
         .put("nonce", "G9Ivek") 
         .put("iUserId", "477"); 

       android.util.Log.e("data - ", "data - " + dataToSend.toString()); 

//Create request object 
       Request request = new Request.Builder() 
         .url("written url here") 
         .post(RequestBody.create(JSON, dataToSend.toString().getBytes(Charset.forName("UTF-8")))) 
         .addHeader("Content-Type", "application/json") 
         .build(); 

       android.util.Log.e("request - ", "request - " + request.toString()); 
       android.util.Log.e("headers - ", "headers - " + request.headers().toString()); 
       android.util.Log.e("body - ", "body - " + request.body().toString()); 

//Make the request 
       Response response = client.newCall(request).execute(); 
       android.util.Log.e("response", " " + response.body().string()); //Convert the response to String 
       String responseData = response.body().string(); 

//Construct JSONObject of the response string 
       JSONObject dataReceived = new JSONObject(responseData); 

//See the response from the server 
       Log.i("response data", dataReceived.toString()); 
      } 
      catch (Exception e){ 
       e.printStackTrace(); 
      } 
      return fact; 
     } 

     @Override 
     protected void onPostExecute(String s) { 
      super.onPostExecute(s); 

      TextView text = (TextView) findViewById(R.id.txtJson); 
      text.setText(s); 
      progressDialog.dismiss(); 
     } 
    } 

Kindly tell me how to show response of this in listview. Thanks 

Answer 2

は、あなたのdoInBackground()方法で次のようにPOSTリクエストを行うようにしてください：コードへ

private final MediaType JSON = MediaType.parse("application/json; charset=utf-8"); 

OkHttpClient client = new OkHttpClient(); 

//Create a JSONObject with the data to be sent to the server 
JSONObject dataToSend = new JSONObject() 
    .put("nonce", "G9Ivek") 
    .put("iUserId", "477"); 

//Create request object 
Request request = new Request.Builder() 
    .url(url) 
    .post(RequestBody.create(JSON, dataToSend.toString())) 
    .build(); 

//Make the request 
Response response = client.newCall(request).execute(); 

//Convert the response to String 
String responseData = response.body().string(); 

//Construct JSONObject of the response string 
JSONObject dataReceived = new JSONObject(responseData); 

//See the response from the server 
Log.i("response data", dataReceived.toString());