どのように自分自身に配列を結合するのですか

Question

私は約250人の従業員の配列を持っています。私は彼らの配列の1つまたは2つの要素が異なるほとんどの従業員の重複を持っています。同じ "empNum"を持つ配列を検出して組み合わせるにはどうしたらいいですか？以下の例は、私が133個の要素を組み合わせた例です。 1は、上記から配列および他の配列に明確なempNumsを得るために：私は試してみました何

Array 
(
[0] => Array 
    (
     [empNum] => 17         
     [wksWrkd] => 2 
     [trcode] => 1 
     [appn] => 51000550000    
     [totalHours] => 20.00 
     [rate] => 12.00 
     [net] => 240.00 
     [overHours] => .00 
     [holidayHours] => .00 
     [overtimePay] => .00 
     [otherPay] => .00 
     [holidayPay] => .00 
     [ctu] => .00 
     [cta] => .00 
     [ptu] => .00 
     [pta] => .00 
     [sickHours] => .0000 
     [vacaHours] => .0000 
     [gross] => 240.00 
    ) 

[1] => Array 
    (
     [empNum] => 17         
     [wksWrkd] => 2 
     [trcode] => 1 
     [appn] => 20000560000    
     [totalHours] => 34.00 
     [rate] => 12.00 
     [net] => 408.00 
     [overHours] => .00 
     [holidayHours] => .00 
     [overtimePay] => .00 
     [otherPay] => .00 
     [holidayPay] => .00 
     [ctu] => .00 
     [cta] => .00 
     [ptu] => .00 
     [pta] => .00 
     [sickHours] => .0000 
     [vacaHours] => .0000 
     [gross] => 408.00 
    ) 

[2] => Array 
    (
     [empNum] => 17         
     [wksWrkd] => 2 
     [trcode] => 1 
     [appn] => 51000550005    
     [totalHours] => 54.00 
     [rate] => 12.00 
     [net] => 648.00 
     [overHours] => .00 
     [holidayHours] => .00 
     [overtimePay] => .00 
     [otherPay] => .00 
     [holidayPay] => .00 
     [ctu] => .00 
     [cta] => .00 
     [ptu] => .00 
     [pta] => .00 
     [sickHours] => .0000 
     [vacaHours] => .0000 
     [gross] => 648.00 
    ) 

[3] => Array 
    (
     [empNum] => 17         
     [wksWrkd] => 2 
     [trcode] => 1 
     [appn] => 20000560005    
     [totalHours] => 13.00 
     [rate] => 12.00 
     [net] => 156.00 
     [overHours] => .00 
     [holidayHours] => .00 
     [overtimePay] => .00 
     [otherPay] => .00 
     [holidayPay] => .00 
     [ctu] => .00 
     [cta] => .00 
     [ptu] => .00 
     [pta] => .00 
     [sickHours] => .0000 
     [vacaHours] => .0000 
     [gross] => 156.00 
    ) 

[4] => Array 
    (
     [empNum] => 17         
     [wksWrkd] => 2 
     [trcode] => 4 
     [appn] => 51000550000    
     [totalHours] => .00 
     [rate] => .00 
     [net] => .00 
     [overHours] => 4.00 
     [holidayHours] => 72.00 
     [overtimePay] => .00 
     [otherPay] => .00 
     [holidayPay] => .00 
     [ctu] => .00 
     [cta] => .00 
     [ptu] => .00 
     [pta] => .00 
     [sickHours] => .0000 
     [vacaHours] => .0000 
     [gross] => 72.00 
    ) 

[5] => Array 
    (
     [empNum] => 17         
     [wksWrkd] => 2 
     [trcode] => 4 
     [appn] => 51000550005    
     [totalHours] => .00 
     [rate] => .00 
     [net] => .00 
     [overHours] => .25 
     [holidayHours] => 4.50 
     [overtimePay] => .00 
     [otherPay] => .00 
     [holidayPay] => .00 
     [ctu] => .00 
     [cta] => .00 
     [ptu] => .00 
     [pta] => .00 
     [sickHours] => .0000 
     [vacaHours] => .0000 
     [gross] => 4.50 
    ) 

[6] => Array 
    (
     [empNum] => 17         
     [wksWrkd] => 2 
     [trcode] => 4 
     [appn] => 20000560005    
     [totalHours] => .00 
     [rate] => .00 
     [net] => .00 
     [overHours] => .25 
     [holidayHours] => 4.50 
     [overtimePay] => .00 
     [otherPay] => .00 
     [holidayPay] => .00 
     [ctu] => .00 
     [cta] => .00 
     [ptu] => .00 
     [pta] => .00 
     [sickHours] => .0000 
     [vacaHours] => .0000 
     [gross] => 4.50 
    ) 

) 

は、2つのクエリです。私は2つのforeachをしましたが、要素をそれ自身と比較し、要素が変更されると次の要素に移動する方法はわかりません。私はarray_merge（）とarray_merge_recursive（）も試みました。

Answer 1

コード

$processedArray = array(); 
    $finalOutput = array(); 
    foreach($elements as $elem){ 
     if(!in_array($elem["empNum"],$processedArray)){ 
      $processedArray[] = $elem["empNum"]; 
      finalOutput[] = $elem; 
      } 
    } 

$ finalOutputの下に試してみてください、私はphp.netにこのソリューションを発見したユニークなEMPNUMで

Answer 2

If two keys are the same, the second one prevails. 

Example: 
<?php 
print_r(array_combine(Array('a','a','b'), Array(1,2,3))); 
?> 
Returns: 
Array 
(
    [a] => 2 
    [b] => 3 
) 

But if you need to keep all values, you can use the function below: 

<?php 
function array_combine_($keys, $values) 
{ 
    $result = array(); 
    foreach ($keys as $i => $k) { 
     $result[$k][] = $values[$i]; 
    } 
    array_walk($result, create_function('&$v', '$v = (count($v) == 1)? array_pop($v): $v;')); 
    return $result; 
} 

print_r(array_combine_(Array('a','a','b'), Array(1,2,3))); 
?> 
Returns: 
Array 
(
    [a] => Array 
     (
      [0] => 1 
      [1] => 2 
     ) 

    [b] => 3 
) 

項目の値です。私はこれがあなたが探しているものだと思います。