1つのSQLクエリで複数の日付範囲からデータを取得するにはどうすればよいですか？

Question

私は2つのクエリを持っています。各照会は、組織と顧客の間の合計発注数、および発注の受注総額を引き出します。クエリは日付範囲を除いて同一です。

SELECT org.organization_id, org.name, cust.name as customer, 
count(*) as num_orders, round (sum(cast(o.total_charge as real))) as receivables 
FROM 
organization as org, orders as o, organization as cust, reconcile_order as ro 
WHERE org.organization_id = o.shipper_org_id 
and o.broker_org_id = cust.organization_id 
and o.order_id = ro.order_id 
and o.status = 'D' 
and (ro.receive_payment_in_full = 0 or ro.receive_payment_in_full is NULL) 
and (NOW()::DATE - o.delivery_confirmed_date::DATE) < 31 
group by org.organization_id, org.name, 
cust.name 
order by org.name asc limit 20 

SELECT org.organization_id, org.name, cust.name as customer, 
count(*) as num_orders, round (sum(cast(o.total_charge as real))) as receivables 
FROM 
organization as org, orders as o, organization as cust, reconcile_order as ro 
WHERE org.organization_id = o.shipper_org_id 
and o.broker_org_id = cust.organization_id 
and o.order_id = ro.order_id 
and o.status = 'D' 
and (ro.receive_payment_in_full = 0 or ro.receive_payment_in_full is NULL) 
and (NOW()::DATE - o.delivery_confirmed_date::DATE) between 31 and 60 
group by org.organization_id, org.name, 
cust.name 
order by org.name asc limit 20 

しかし、私はこれらの列の隣の第二日付範囲の列の別のペアを出力するが、最初の日付の範囲内の注文や債権のための列を持つ単一のテーブルであるように、この1つのクエリを作成する必要があり、そして。 （すなわちnum_orders < 31、債権< 31、num_orders 31から60、債権31〜60）

Answer 1

イム私はあなたの正確な質問を理解していることを確認し、どのようにこの程度ではない：

Select earlier_ones.organization_id,earlier_ones.organization_id, name, customer, earlier_ones.receivables, later_ones.receivables 
FROM (
    SELECT org.organization_id, org.name, cust.name as customer, 
    count(*) as num_orders, round (sum(cast(o.total_charge as real))) as receivables 
    FROM 
    organization as org, orders as o, organization as cust, reconcile_order as ro 
    WHERE org.organization_id = o.shipper_org_id 
    and o.broker_org_id = cust.organization_id 
    and o.order_id = ro.order_id 
    and o.status = 'D' 
    and (ro.receive_payment_in_full = 0 or ro.receive_payment_in_full is NULL) 
    and (NOW()::DATE - o.delivery_confirmed_date::DATE) < 31 
    group by org.organization_id, org.name, 
    cust.name 
    order by org.name asc limit 20 
) earlier_ones 
LEFT JOIN (
    SELECT org.organization_id, org.name, cust.name as customer, 
    count(*) as num_orders, round (sum(cast(o.total_charge as real))) as receivables 
    FROM 
    organization as org, orders as o, organization as cust, reconcile_order as ro 
    WHERE org.organization_id = o.shipper_org_id 
    and o.broker_org_id = cust.organization_id 
    and o.order_id = ro.order_id 
    and o.status = 'D' 
    and (ro.receive_payment_in_full = 0 or ro.receive_payment_in_full is NULL) 
    and (NOW()::DATE - o.delivery_confirmed_date::DATE) between 31 and 60 
    group by org.organization_id, org.name, 
    cust.name 
    order by org.name asc limit 20 
) later_ones ON earlier_ones.organization_id = later_ones.organization_id AND earlier_ones.name = later_ones.name; 

Answer 2

あなたが条件を置くことができますcount（）関数とsum（）関数の中の文。

したがって、（両方の日付範囲で）すべての注文を戻すようにwhere句を調整した場合、select句に複数の結果列を作成し、必要な日付範囲から集計して合計することができます。

SELECT ... 
     count(CASE WHEN (NOW()::DATE - o.delivery_confirmed_date::DATE) < 31 THEN 1 ELSE NULL END) as num_orders_a, 
     round(sum(CASE WHEN (NOW()::DATE - o.delivery_confirmed_date::DATE) < 31 THEN cast(o.total_charge as real) ELSE NULL END)) as receivables_a, 
     count(CASE WHEN (NOW()::DATE - o.delivery_confirmed_date::DATE) BETWEEN 31 AND 60 THEN 1 ELSE NULL END) as num_orders_b, 
     round(sum(CASE WHEN (NOW()::DATE - o.delivery_confirmed_date::DATE) BETWEEN 31 AND 60 THEN cast(o.total_charge as real) ELSE NULL END)) as receivables_b 
(same FROM, WHERE, GROUP BY, and ORDER BY sections) 

Answer 3

この猫を肌には、いくつかの方法がありますが、パフォーマンスとコードの保守性との間に、ここで本当の潜在的なトレードオフが存在します。

ここでのCTEは、コードの可読性/透過性/保守性に役立ちます。これはそれを行うにはハックの道の少しですが、これは1つのアイデアです：私はより一般的なアプローチは、（current_date - o.delivery_confirmed_date::DATEとして）CTEから「days_delta」列を渡すかもしれないと思うと持って

with order_data as (
    SELECT 
    org.organization_id, org.name, cust.name as customer, 
    o.total_charge::real, 
    case 
     when current_date - o.delivery_confirmed_date::DATE < 31 then 1 
     when current_date - o.delivery_confirmed_date::date < 61 then 2 
     else 3 
    end as cat 
    FROM 
    organization as org, 
    orders as o, 
    organization as cust, 
    reconcile_order as ro 
    WHERE 
    org.organization_id = o.shipper_org_id 
    and o.broker_org_id = cust.organization_id 
    and o.order_id = ro.order_id 
    and o.status = 'D' 
    and (ro.receive_payment_in_full = 0 or ro.receive_payment_in_full is NULL) 
) 
select 
    organization_id, name, customer, 
    sum (case when cat = 1 then 1 else 0 end) as "Orders < 31", 
    round (sum (case when cat = 1 then total_charge else 0 end)) as "Rec < 31", 
    sum (case when cat = 2 then 1 else 0 end) as "Orders 31-60", 
    round (sum (case when cat = 2 then total_charge else 0 end)) as "Rec 31-60", 
    sum (case when cat = 3 then 1 else 0 end) as "Orders 61+", 
    round (sum (case when cat = 3 then total_charge else 0 end)) as "Rec 61+" 
from order_data 
group by 
    organization_id, name, name 
order by name asc 

あなたの合計関数は次のようになります。

sum (case when days_delta between 31 and 60 then ... end) as "31-60" 

そして...あなたがCTEを必要としないと言う人は誰もが正しいと言います。あなたはそうしない。私にとっては、コードを処理するほうが楽しいです。

- EDIT - CTE、サブクエリの

あまり魅力（とあまり機能）いとこ：

select 
    organization_id, name, customer, 
    sum (case when cat = 1 then 1 else 0 end) as "Orders < 31", 
    round (sum (case when cat = 1 then total_charge else 0 end)) as "Rec < 31", 
    sum (case when cat = 2 then 1 else 0 end) as "Orders 31-60", 
    round (sum (case when cat = 2 then total_charge else 0 end)) as "Rec 31-60", 
    sum (case when cat = 3 then 1 else 0 end) as "Orders 61+", 
    round (sum (case when cat = 3 then total_charge else 0 end)) as "Rec 61+" 
from (
    SELECT 
    org.organization_id, org.name, cust.name as customer, 
    o.total_charge::real, 
    case 
     when current_date - o.delivery_confirmed_date::DATE < 31 then 1 
     when current_date - o.delivery_confirmed_date::date < 61 then 2 
     else 3 
    end as cat 
    FROM 
    organization as org, 
    orders as o, 
    organization as cust, 
    reconcile_order as ro 
    WHERE 
    org.organization_id = o.shipper_org_id 
    and o.broker_org_id = cust.organization_id 
    and o.order_id = ro.order_id 
    and o.status = 'D' 
    and (ro.receive_payment_in_full = 0 or ro.receive_payment_in_full is NULL) 
) as order_data 
group by 
    organization_id, name, name 
order by name asc