列名のSQL ServerでPivotテーブルを返すにはどうすればよいですか？

Question

投稿された質問で、列名に基づいていない結果に基づいてピボットを行うことを確認しました この結果を取得するSQLスクリプトは何かアドバイスできますか？

実際の結果

期待される結果、事前に

ありがとう。

Answer 1

あなたはunion allでこれを行うことができます。

select 'name' as which, 
     max(case when id = 1 then name end) as [1], 
     max(case when id = 2 then name end) as [2], 
     max(case when id = 3 then name end) as [3], 
     max(case when id = 4 then name end) as [4] 
from t 
union all 
select 'state' as which, 
     max(case when id = 1 then state end) as [1], 
     max(case when id = 2 then state end) as [2], 
     max(case when id = 3 then state end) as [3], 
     max(case when id = 4 then state end) as [4] 
from t; 

Answer 2

その後、あなたは動的SQLクエリを使用することができます。あなたによると

declare @sql as varchar(max); 

select @sql = 'select '+ char(39) + 'name' + char(39) + ' as [id],' + 
stuff((select distinct ', max(case when [id] = ' 
    + cast([id] as varchar(100)) + ' then [name] end) 
     as [' + cast([id] as varchar(100)) + ']' 
    from #t 
    for xml path('') 
), 1, 2, '') + 
' from #t union all ' + 
'select '+ char(39) + 'state' + char(39) + ' as [id],' + 
stuff((select distinct ', max(case when [id] = ' 
    + cast([id] as varchar(100)) + ' then [state] end) 
     as [' + cast([id] as varchar(100)) + ']' 
    from #t 
    for xml path('') 
), 1, 2, '') + 
' from #t'; 

exec(@sql); 

Chanage #t

クエリ。