はECC PKCS＃8公開鍵と秘密鍵は、私は、ECCは、公共とはBouncyCastleで生成した秘密持っ

Question

伝統的な形式に変換します

  Security.addProvider(new org.bouncycastle.jce.provider.BouncyCastleProvider()); 

      ECNamedCurveParameterSpec ecSpec = ECNamedCurveTable 
        .getParameterSpec("secp192r1"); 

      KeyPairGenerator g = KeyPairGenerator.getInstance("ECDSA", "BC"); 
      g.initialize(ecSpec, new SecureRandom()); 

      KeyPair pair = g.generateKeyPair(); 

      System.out.println(Arrays.toString(pair.getPrivate().getEncoded())); 
      System.out.println(Arrays.toString(pair.getPublic().getEncoded())); 


byte[] privateKey = new byte[]{48, 123, 2, 1, 0, 48, 19, 6, 7, 42, -122, 72, -50, 61, 2, 1, 6, 8, 42, -122, 72, -50, 61, 3, 1, 1, 4, 97, 48, 95, 2, 1, 1, 4, 24, 14, 117, 7, -120, 15, 109, -59, -35, 72, -91, 99, -2, 51, -120, 112, -47, -1, -115, 25, 48, -104, -93, 78, -7, -96, 10, 6, 8, 42, -122, 72, -50, 61, 3, 1, 1, -95, 52, 3, 50, 0, 4, 64, 48, -104, 32, 41, 13, 1, -75, -12, -51, -24, -13, 56, 75, 19, 74, -13, 75, -82, 35, 1, -50, -93, -115, -115, -34, -81, 119, -109, -50, -39, -57, -20, -67, 65, -50, 66, -122, 96, 84, 117, -49, -101, 54, -30, 77, -110, -122} 

byte[] publicKey = new byte[]{48, 73, 48, 19, 6, 7, 42, -122, 72, -50, 61, 2, 1, 6, 8, 42, -122, 72, -50, 61, 3, 1, 1, 3, 50, 0, 4, 64, 48, -104, 32, 41, 13, 1, -75, -12, -51, -24, -13, 56, 75, 19, 74, -13, 75, -82, 35, 1, -50, -93, -115, -115, -34, -81, 119, -109, -50, -39, -57, -20, -67, 65, -50, 66, -122, 96, 84, 117, -49, -101, 54, -30, 77, -110, -122} 

https://github.com/kmackay/micro-ecc/blob/master/uECC.hに後で再利用することができ、伝統的な形式に変換する方法は？ 0は最初25または49で追加されたときに、今では125と75

Answer 1

ている間、私は24のバイトはプライベートと48公開鍵必要なのは、時には、24と48を与えます：

ECPrivateKey ecPrivateKey = (ECPrivateKey)privateKey; 
    System.out.println(ecPrivateKey.getS().toByteArray().length); 

    ECPublicKey ecPublicKey = (ECPublicKey)publicKey; 
    System.out.println(ecPublicKey.getW().getAffineX().toByteArray().length + ecPublicKey.getW().getAffineY().toByteArray().length);