配列を含む配列をその出現に従って置換

Question

配列内の対応するアルファベット文字で置き換える方法。あなたの配列が1から26までの文字列値が含まれている場合

Example: 
["1","2","3","3","2","3"] 

Replace: 1 -> A, 2-> B, 3-> C 

Result should be 
["A","B","C","C","B","C"] 

Answer 1

のように試すことができます：

let array = ["1", "2", "3", "3", "2", "3"] 

let replacementRules = ["1": "A", "2": "B", "3": "C"] 

let result = array.map{replacementRules[$0] ?? $0} 
print(result) 
//["A", "B", "C", "C", "B", "C"] 

Answer 2

、あなたはあなたが交換のルールにDictionaryを使用することができ、この

let alphabetArray = ["A", "B", "C", "D", "E", "F", "G", "H", "I", "J", "K", "L", "M", "N", "O", "P", "Q", "R", "S", "T", "U", "V", "W", "X", "Y", "Z"] 
    let arr = ["1","2","3","3","2","3"] 
    var newArr = [String]() 
    newArr = arr.map { (item) in 
     alphabetArray[Int(item)! - 1] 
    } 
    print(newArr) 

Answer 3

var arr = ["1","2","3","3","2","3"] 
for i in 0..<arr.count { 
    switch(arr[i]) { 
     case "1": 
      arr[i] = "A" 
      break 
     case "2": 
      arr[i] = "B" 
      break 
     case "3": 
      arr[i] = "C" 
      break 
    default: break 
    } 

}