SQL文

Question

私は声明

select 
    ID, name,Departmen, date, clock_in, clock_out, 
    DATEDIFF(MINUTE, on_duty, clock_in) as late, 
    DATEDIFF(MINUTE, off_duty, clock_out) as Early, 
    DATEDIFF(MINUTE, on_duty, clock_in) - DATEDIFF(MINUTE, off_duty, clock_out) as total_telat when late <=30 from kkpsurabaya 

私はtotal_telatを作りたいだけ1-30min

Answer 1

使用CASE . . WHEN . . END

select ID, 
    name, 
    Departmen, date, clock_in, clock_out, 
    DATEDIFF(MINUTE, on_duty, clock_in) as late , 
    DATEDIFF(MINUTE, off_duty, clock_out) as Early, 
    CASE 
    WHEN DATEDIFF(MINUTE, on_duty, clock_in) < 30 
    THEN DATEDIFF(MINUTE,on_duty, clock_in) - DATEDIFF(MINUTE ,off_duty, clock_out) 
    END as total_telat 
from kkpsurabaya 

Answer 2

Caseステートメントを数えるとき、または場合に選択したい場合に選択する最も近いのとアウトのすべてのバージョンによってサポートされている場合。これはあなたの理解の一例に過ぎません。私は、ケースについての勉強があなたが必要とするものを達成するのに役立つことを願っています

SELECT CAST(
      CASE 
        WHEN (DATEDIFF(MINUTE,on_duty, clock_in) - DATEDIFF(MINUTE ,off_duty, clock_out))> '0' or (DATEDIFF(MINUTE,on_duty, clock_in) - DATEDIFF(MINUTE ,off_duty, clock_out)) < '31' 
        THEN 1 
        ELSE 0 
      END AS bit) as Saleable, * 
FROM Product 

Answer 3

SELECT ID 
     ,NAME 
     ,Departmen 
     ,DATE 
     ,clock_in 
     ,clock_out 
     ,DATEDIFF(MINUTE, on_duty, clock_in) AS late 
     ,DATEDIFF(MINUTE, off_duty, clock_out) AS Early 
     ,total_telat = iif(DATEDIFF(MINUTE, on_duty, clock_in)<= 30, DATEDIFF(MINUTE, on_duty, clock_in) - DATEDIFF(MINUTE, off_duty, clock_out), NULL) 
    FROM kkpsurabaya