私は私の側で正常に動作しているGET応答のためのコードのこの部分を使用しています:
HttpClient client = new DefaultHttpClient();
HttpGet request = new HttpGet(requestUrl);
HttpResponse response=null;
try {
response = client.execute(request);
} catch (ClientProtocolException e) {
Log.d(TAG,"1. "+e.toString());
} catch (IOException e) {
Log.d(TAG,"2. "+e.toString());
}
int status_code=response.getStatusLine().getStatusCode();
Log.d(TAG,"Response Code returned ="+status_code);
BufferedReader in=null;
try {
in = new BufferedReader(new InputStreamReader(response.getEntity().getContent()));
} catch (IllegalStateException e) {
Log.d(TAG,"3. "+e.toString());
} catch (IOException e) {
Log.d(TAG,"4. "+e.toString());
}
StringBuffer sb = new StringBuffer("");
String line = "";
String newline = System.getProperty("line.separator");
try {
while ((line = in.readLine()) !=null){
sb.append(line + newline);
}
String data = sb.toString();
Log.d(TAG,data);
} catch (IOException e) {
Log.d(TAG,"5. "+e.toString());
}
try {
in.close();
} catch (IOException e) {
Log.d(TAG,"6. "+e.toString());
}
String data = sb.toString();
try {
if(status_code==200 || status_code==401){
JSONObject responseJSONObject = new JSONObject(data);
responseJSONObject.put("tpg_status_code", status_code);
}
} catch (JSONException e) {
Log.d(TAG,"6. "+e.toString());
}
'getResponse'はどこから来ましたか(このコードはどのクラスに置かれていますか?)、エラーは何ですか? – jadkik94