Rubyは同じキーと複数の値を持つハッシュの配列を結合します

Question

私は実際には2つの配列の組み合わせである次の配列を持っています。私の目標は、従業員IDが898989である2つのハッシュを組み合わせて、それらの数を合計してそのタイプを両方に変更できるということです。私は私のハッシュの他の値を失うが、私が欲しいものに近いです下のコードを試してみました。すべての値をマップし、私が望むようにカウントを追加するような操作をする簡単な方法はありますか？

combined = [{"@rid"=>"#-2:1", "employeeId"=> "898989", "count"=>1, :type=>"wiki" }, 
     {"@rid"=>"#-2:3", "employeeId"=> "2423213", "count"=>7, :type=>"search"}, 
     {"@rid"=>"#-2:2", "employeeId"=> "555555", "count"=>2, :type=>"search"}, 
     {"@rid"=>"#-2:5", "employeeId"=> "898989", "count"=>2, :type=>"search"}, 
     {"@rid"=>"#-2:1", "employeeId"=> "5453454", "count"=>1, :type=>"search"}, 
     {"@rid"=>"#-2:4", "employeeId"=>"987654321", "count"=>1, :type=>"search"}] 

merged_array_hash = combined.group_by { |h1| h1["employeeId"] }.map do |k,v| 
    { "employeeId" => k, :types => v.map { |h2| h2[:type] }.join(", ") } 
end 

merged_array_hashはビーイングを終わる：

[{employeeId: "898989",types: "wiki, search"}, 
{employeeId: "2423213",types: "search"}, 
{employeeId: "555555",types: "search"}, 
{employeeId: "5453454",types:"search"}, 
{employeeId: "987654321",types: "search"}] 

私が取得しているよ何を：

[{employeeId: "898989",type: "both", count: 2}, 
{employeeId: "2423213",type: "search", count: 7}, 
{employeeId: "555555",type: "search", count: 2}, 
{employeeId: "5453454",type:"search", count: 1}, 
{employeeId: "987654321",type: "search", count: 1}] 

Answer 1

ない美しいが、それは仕事を得るでしょう：

combined.group_by { |h1| h1["employeeId"] }.map do |k,v| 
    types = v.map { |h2| h2[:type] } 
    count = v.sum { |x| x['count'] } 

    { employeeId: k, 
    types: (types.length == 1 ? types[0] : 'both'), 
    count: count } 

end 

=> [{:employeeId =>"898989", :types=>"both", :count=>3}, 
    {:employeeId =>"2423213", :types=>"search", :count=>7}, 
    {:employeeId =>"555555", :types=>"search", :count=>2}, 
    {:employeeId =>"5453454", :types=>"search", :count=>1}, 
    {:employeeId =>"987654321", :types=>"search", :count=>1}] 

Answer 2

また美しくない、またtを得る彼の仕事は、潜在的に読みやすく、行わ

hash = {} 
combined.each do |h| 
    employeeId, count, type = h.values_at("employeeId", "count", :type) 
    if hash.include? employeeId 
    hash[employeeId][:count] += count 
    hash[employeeId][:type] = "both" #assumes duplicates can only occur if item is in both lists 
    else 
    hash[employeeId] = { :employeeId => employeeId, :type => type, :count => count } 
    end 
end 
hash.values 

テスト：

[{:employeeId=>"898989", :type=>"both", :count=>3}, 
{:employeeId=>"2423213", :type=>"search", :count=>7}, 
{:employeeId=>"555555", :type=>"search", :count=>2}, 
{:employeeId=>"5453454", :type=>"search", :count=>1}, 
{:employeeId=>"987654321", :type=>"search", :count=>1}]