ビューテーブル内のSQL関数

Question

日付の間の年月日を示すこの関数があります。ビューテーブルでは、開始日と終了日のデータがあります。その機能をビューテーブルにどのように統合することが可能ですか？

USE [DB] 
GO 
SET ANSI_NULLS ON 
GO 
SET QUOTED_IDENTIFIER ON 
GO 

alter FUNCTION [db].[GetDateDifference] 
(
    @FromDate DATETIME, @ToDate DATETIME 
) 
RETURNS 
@DateDifference TABLE (
YEAR INT, MONTH INT, DAYS INT) 
AS 
BEGIN 
    DECLARE @Years INT, @Months INT, @Days INT, @tmpFromDate DATETIME 
    SET @Years = DATEDIFF(YEAR, @FromDate, @ToDate) 
    - (CASE WHEN DATEADD(YEAR, DATEDIFF(YEAR, @FromDate, @ToDate), 
       @FromDate) > @ToDate THEN 1 ELSE 0 END) 

    SET @tmpFromDate = DATEADD(YEAR, @Years , @FromDate) 
    SET @Months = DATEDIFF(MONTH, @tmpFromDate, @ToDate) 
    - (CASE WHEN DATEADD(MONTH,DATEDIFF(MONTH, @tmpFromDate, @ToDate), 
       @tmpFromDate) > @ToDate THEN 1 ELSE 0 END) 

    SET @tmpFromDate = DATEADD(MONTH, @Months , @tmpFromDate) 
    SET @Days = DATEDIFF(DAY, @tmpFromDate, @ToDate) 
    - (CASE WHEN DATEADD(DAY, DATEDIFF(DAY, @tmpFromDate, @ToDate), 
       @tmpFromDate) > @ToDate THEN 1 ELSE 0 END) 

    INSERT INTO @DateDifference 
    VALUES(@Years, @Months, @Days) 

    RETURN 
END 

、ここで私の見解テーブルです：

USE [DB] 
GO 
SET ANSI_NULLS ON 
GO 
SET QUOTED_IDENTIFIER ON 
GO 

alter VIEW [db].[View_ServiceTickets] 

AS 

SELECT TOP 99 

     ServiceTicketDate, 
     BillingDate as 'Project Finished', 
     InspectionScheduleDate 


FROM  tblServiceTicket INNER JOIN 
      tblServiceTicketReport on tblServiceTicket.ServiceTicketID = tblServiceTicketReport.ServiceTicketID 


where ServiceTicketDate > '2016' 
order by ServiceTicketDate desc 

GO 

はそんなに

Answer 1

をありがとう、私はあなたの関数の戻り値のデータ型がテーブルなので、あなたはそれを表として扱う使用しました。 次のコードをテストすることができます。

alter VIEW [db].[View_ServiceTickets] 

AS 

SELECT TOP 99 

    ServiceTicketDate, 
    BillingDate as 'Project Finished', 
    InspectionScheduleDate, 
    d.* 


FROM  tblServiceTicket INNER JOIN 
     tblServiceTicketReport on tblServiceTicket.ServiceTicketID = tblServiceTicketReport.ServiceTicketID 
     OUTER APPLY(SELECT YEAR,MONTH,DAYS FROM [db].[GetDateDifference](ServiceTicketDate,BillingDate)) d 


where ServiceTicketDate > '2016' 
order by ServiceTicketDate desc