データベースからデータをフェッチしてテーブル形式で表示する方法は？

Question

次のコードを使用して、データベースからデータを取得しています。私はすべての列の値を挿入するとき、私の出力が正しいことを示します。たとえば、 'Hip'のNULL値を挿入して表形式で表示しないようにします。

事前におかげで助けてください！

$sizeArray   = explode(',', $rows['sizes']); 
$bustArray   = explode(',', $rows['bust']); 
$hipArray   = explode(',', $rows['hip']); 
$lengthArray  = explode(',', $rows['length']); 
$lengthArraybottom = explode(',', $rows['lengthbottom']); 
$shoulderArray  = explode(',', $rows['shoulder']); 

foreach ($sizeArray as $key => $value) { 
    foreach ($bustArray as $bkey => $bvalue) { 
     foreach ($waistArray as $Wkey => $Wvalue) { 
      foreach ($hipArray as $hkey => $hvalue) { 
       foreach ($lengthArray as $lkey => $lvalue) { 
        foreach ($lengthArraybottom as $lkeybottom => $lbottomvalue) { 
         foreach ($shoulderArray as $skey => $svalue) { 
          if ($key == $bkey && $bkey == $Wkey && $Wkey == $hkey && $hkey == $lkey && $lkey == $lkeybottom && $lkeybottom == $skey) { 

           echo '<tr><td>' . $value . '</td>'; 
           echo '<td>' . $bvalue . '</td>'; 
           echo '<td>' . Wvalue . '</td>'; 
           echo '<td>' . $hvalue . '</td>'; 
           echo '<td>' . $lvalue . '</td>'; 
           echo '<td>' . $lbottomvalue . '</td>'; 
           echo '<td>' . $svalue . '</td></tr>'; 

          } 
         } 
        } 
       } 
      } 
     } 
    } 
} 

Answer 1

<table class="data-table"> 
    <caption class="title">Sales Data of Electronic Division</caption> 
    <thead> 
     <tr> 
      <th>NO</th> 
      <th>CUSTOMER</th> 
      <th>ITEM</th> 
      <th>DATE</th> 
      <th>AMOUNT</th> 
     </tr> 
    </thead> 
    <tbody> 
    <?php 
    $no  = 1; 
    $total = 0; 
    while ($row = mysqli_fetch_array($query)) 
    { 
     $amount = $row['amount'] == 0 ? '' : number_format($row['amount']); 
     echo '<tr> 
       <td>'.$no.'</td> 
       <td>'.$row['name'].'</td> 
       <td>'.$row['item'].'</td> 
       <td>'. date('F d, Y', strtotime($row['date'])) . '</td> 
       <td>'.$amount.'</td> 
      </tr>'; 
     $total += $row['amount']; 
     $no++; 
    }?> 
    </tbody> 
    <tfoot> 
     <tr> 
      <th colspan="4">TOTAL</th> 
      <th><?=number_format($total)?></th> 
     </tr> 
    </tfoot> 
</table> 

Refrence：http://webdevzoom.com/display-mysql-data-html-5-table-using-php/