列の値を異なる行に分割する

Question

私は以下のようにPharmacyIDとRegimenを持つ薬局テーブルを持っています。

PharmacyID Regimen 
140646  3TC/D4T/EFV 
140653  ABC/D4T/NVP 

私の望みはこのようなものを得ることです。

PharmacyID Regimen 
140646  3TC 
140646  D4T 
140646  EFV 
140653  ABC 
140653  D4T 
140653  NVP 

アムは、私はすべてのソリューション

を試していないグーグルで立ち往生

Answer 1

XMLを介し文字列分割のアプローチをオンザフライこれはで動作します：

DECLARE @tbl TABLE(PharmacyID INT,Regimen VARCHAR(100)); 
INSERT INTO @tbl VALUES(140646,'3TC/D4T/EFV') 
         ,(140653,'ABC/D4T/NVP'); 

WITH Casted AS (
       SELECT PharmacyID 
         ,CAST('<x>' + REPLACE((SELECT Regimen AS [*] FOR XML PATH('')),'/','</x><x>') + '</x>' AS XML) AS TheXML 
       FROM @tbl 
       ) 
SELECT PharmacyID 
     ,a.x.value(N'(./text())[1]','nvarchar(max)') AS Regimen 
FROM Casted 
CROSS APPLY Casted.TheXML.nodes(N'/x') AS A(x) 

Answer 2

create function [dbo].[udf_splitstring] (@tokens varchar(max), 
            @delimiter varchar(5)) 
returns @split table (
    token varchar(200) not null) 
as 



    begin 

     declare @list xml 

     select @list = cast('<a>' 
          + replace(@tokens, @delimiter, '</a><a>') 
          + '</a>' as xml) 

     insert into @split 
        (token) 
     select ltrim(t.value('.', 'varchar(200)')) as data 
     from @list.nodes('/a') as x(t) 

     return 

    end 



    CREATE TABLE #Table111 
     ([PharmacyID] int, [Regimen] varchar(11)) 
    ; 

    INSERT INTO #Table111 
     ([PharmacyID], [Regimen]) 
    VALUES 
     (140646, '3TC/D4T/EFV'), 
     (140653, 'ABC/D4T/NVP') 
    ; 
    select [PharmacyID], token FROM #Table111 as t1 
    CROSS APPLY [dbo].UDF_SPLITSTRING([Regimen],'/') as t2 

出力

PharmacyID token 
140646 3TC 
140646 D4T 
140646 EFV 
140653 ABC 
140653 D4T 
140653 NVP 

Answer 3

create table #temp1(string1 varchar(max)) 
Insert into #temp1 
Values('3TC/D4T/EFV'),('ABC/D4T/NVP') 

    SELECT 
    Replace(Replace(CAST(Tbl.Col.query('.') as varchar(max)),'<a>',''),'</a>','') 
    FROM 
(Select cast('<a>'+ replace(string1, '/', '</a><a>') + '</a>' as xml)as t 
    from #temp1) tl 
Cross apply 
    tl.t.nodes('/a') AS Tbl(Col)