foreachの列を返し、私はテーブルにそれを有効にする必要があり

Question

私は、次のJSONテーブル

[ 
    ["TITLE", "CONTENT", "DATE"], 
    ["Monday", "Content of the monday post goes here", "09:55\n10:00\n10:30\n11:00\n15:45"], 
    ["Tuesday", "Content of the tuesday day goes here", "08:00\n11:00\n16:00\n16:00\n21:00\n"], 
] 

私はforeachがjson内容に

$days = json_decode(file_get_contents('json_file')); 
     foreach($days as $item){ 
      if(isset($item)){ 
       $firstColumn = $item; 
      } 
      echo $firstColumn[0]; 

     }; 

$firstColumn[0]リターンを得るために使用する「タイトル」 、 "Monday"、 "Friday"

テーブルに追加するにはどうすればよいですか？

<table class="table"> 
    <thead> 
    <tr> 
     <th> Title </th> 
     <th>Content</th> 
     <th>Date</th> 
    </tr> 
    </thead> 
    <tbody> 
     <tr> 
     <td></td> 
     <td></td> 
     <td></td> 
     </tr> 
    </tbody> 
</table> 

Answer 1

以下のようにそれを実行します - but how can I add it into a return inside a function? - ：あなたの質問についてhttps://prnt.sc/h8nit6

- 私の地元の終わりに

<?php 

$days = [ 
    ["TITLE", "CONTENT", "DATE"], 
    ["Monday", "Content of the monday post goes here", "09:55\n10:00\n10:30\n11:00\n15:45"], 
    ["Tuesday", "Content of the tuesday day goes here", "08:00\n11:00\n16:00\n16:00\n21:00\n"], 
]; // as you said that you got this array already 
unset($days[0]); 
?> 
<table class="table"> 
    <thead> 
    <tr> 
     <th> Title </th> 
     <th>Content</th> 
     <th>Date</th> 
    </tr> 
    </thead> 
    <tbody> 
    <?php foreach($days as $day){?> 
     <tr> 
     <td><?php echo $day[0];?></td> 
     <td><?php echo $day[1];?></td> 
     <td><?php echo $day[2];?></td> 
     </tr> 
    <?php }?> 
    </tbody> 
</table> 

出力。私はあなたが以下のようにしたいと思う： -

function returnFullHtml(){ 
    $days = json_decode(file_get_contents('json_file'));// now you got the array what you shhown in your question input 
    unset($days[0]); 
    $html = '<table class="table"> 
     <thead> 
      <tr> 
       <th> Title </th> 
       <th>Content</th> 
       <th>Date</th> 
      </tr> 
     </thead> 
     <tbody>'; 
    foreach($days as $day){ 
     $html .= '<tr><td>'. $day[0] .'</td><td>' . $day[1] .'</td><td>' . $day[2] .'</td></tr>'; 
    } 
    $html .= '</tbody></table>'; 
    return $html; 

} 

Answer 2

この

echo '<table class="table">'; 
    $items = json_decode(file_get_contents('json_file')); 
    $headers = array_shift($items); 

    echo '<thead>'; 
    foreach($headers as $value){ 
     echo '<th>'.$value.'</th>'; 
    } 
    echo '</thead>'; 

    echo '<tbody>'; 
    foreach($items as $item){ 
     echo '<tr>'; 
     foreach($item as $value){ 
      echo '<td>'.$value.'</td>'; 
     } 
     echo '</tr>'; 
    }; 
    echo '</tbody>'; 
echo '</table>'; 

Answer 3

がこの作品OBJ

<?php 
if (sizeof($days) > 0) { //If json is not empty 
    $firstColumn = $days[0] ; //First Column (<thead> values) 
    ?> 
    <table> 
     <thead> 
      <tr> 
       <?php foreach ($firstColumn AS $k => $v) { ?> 
        <th><?php echo $v?></th> 
       <?php } ?> 
      </tr> 
     </thead> 
     <tbody> 
      <?php 
      foreach($days as $k => $v) { 
       if ($k != 0) { ?> 
        <tr> 
        <?php 
        foreach ($v AS $k1 => $v1) { ?> 
         <td><?php echo $v1 ?></td> 
        <?php 
        } ?> 
        </tr> 
       <?php 
       } 
      } ?> 
     </tbody> 
    </table> 
    <?php 
} ?>