数日間の研究の後、まだ解決策が見つかりませんでした。LEFTジョインでHQLエラーが発生しました。
私はquerySyntaxExceptionを投げるこのHQL要求を持っている:
Caused by: org.hibernate.hql.internal.ast.QuerySyntaxException: with-clause referenced two different from-clause elements [SELECT patDataset.patient.sId , patData ,proDataset.professional.sId, proData FROM com.inovelan.cloud.persistence.server.entities.DataSet patDataset INNER JOIN patDataset.patient patient with patient. sId in (:patientSidList) LEFT JOIN patient.patientProfessionals ppRole with ppRole.id.roleCodingOidcodesystem= :codeSystem AND ppRole.id.roleCodingCode=:codingCode LEFT JOIN ppRole.professional proRole LEFT JOIN proRole.dataSet proDataset with proDataset.archive =:archive LEFT JOIN proDataset.dataProfessionals proData with proData.itemDefinition.id.id in (:proItemDefs) INNER JOIN patDataset.dataSetDefinition patDatasetDef with patDatasetDef.id.id in(:patDatasetDefIdList) INNER JOIN patDataset.dataPatients patData LEFT JOIN patDataset.dataPatients data_patient_PAT_SEXE with (data_patient_PAT_SEXE.itemDefinition.id.id=:data_patient_PAT_SEXE AND patDataset.dataSetDefinition.id.id ='DIRECTORY_PATIENT') LEFT JOIN patDataset.dataPatients data_patient_PAT_NOM_NAISSANCE with (data_patient_PAT_NOM_NAISSANCE.itemDefinition.id.id=:data_patient_PAT_NOM_NAISSANCE AND patDataset.dataSetDefinition.id.id ='DIRECTORY_PATIENT') LEFT JOIN patDataset.dataPatients data_patient_PAT_PRENOM with (data_patient_PAT_PRENOM.itemDefinition.id.id=:data_patient_PAT_PRENOM AND patDataset.dataSetDefinition.id.id ='DIRECTORY_PATIENT') WHERE patDataset.archive=:archive AND patient.active=:patientState AND (patDatasetDef.id.id =:dataset_def_pat_DIRECTORY_PATIENT AND patData.itemDefinition.id.id in (:itemdef_list_pat_DIRECTORY_PATIENT) ) AND patDataset.date = (SELECT MAX(patDataset2.date) FROM com.inovelan.cloud.persistence.server.entities.DataSet patDataset2 WHERE patDataset2.dataSetDefinition.id.id = patDataset.dataSetDefinition.id.id AND patDataset2.patient.sId = patDataset.patient.sId) ORDER BY (CASE WHEN data_patient_PAT_SEXE.stringValue IS NULL then 1 ELSE 0 END), data_patient_PAT_SEXE.stringValue ASC,(CASE WHEN data_patient_PAT_NOM_NAISSANCE.stringValue IS NULL then 1 ELSE 0 END), data_patient_PAT_NOM_NAISSANCE.stringValue ASC,(CASE WHEN data_patient_PAT_PRENOM.stringValue IS NULL then 1 ELSE 0 END), data_patient_PAT_PRENOM.stringValue ASC]
at org.hibernate.hql.internal.ast.QuerySyntaxException.convert(QuerySyntaxException.java:91)
at org.hibernate.hql.internal.ast.ErrorCounter.throwQueryException(ErrorCounter.java:109)
at org.hibernate.hql.internal.ast.QueryTranslatorImpl.analyze(QueryTranslatorImpl.java:284)
at org.hibernate.hql.internal.ast.QueryTranslatorImpl.doCompile(QueryTranslatorImpl.java:206)
at org.hibernate.hql.internal.ast.QueryTranslatorImpl.compile(QueryTranslatorImpl.java:158)
at org.hibernate.engine.query.spi.HQLQueryPlan.<init>(HQLQueryPlan.java:131)
at org.hibernate.engine.query.spi.HQLQueryPlan.<init>(HQLQueryPlan.java:93)
at org.hibernate.engine.query.spi.QueryPlanCache.getHQLQueryPlan(QueryPlanCache.java:167)
at org.hibernate.internal.AbstractSessionImpl.getHQLQueryPlan(AbstractSessionImpl.java:301)
at org.hibernate.internal.AbstractSessionImpl.createQuery(AbstractSessionImpl.java:236)
at org.hibernate.internal.SessionImpl.createQuery(SessionImpl.java:1836)
at org.hibernate.jpa.spi.AbstractEntityManagerImpl.createQuery(AbstractEntityManagerImpl.java:342)
私はそれをより理解しやすくするために要求を抽出し、その理由は、「左の参加は、」メタデータをソートすることである(それは常に要求に追加していません):
SELECT patDataset.patient.sId,
patData
FROM DataSet patDataset
INNER JOIN patDataset.patient patient
INNER JOIN patDataset.dataSetDefinition patDatasetDef WITH patDatasetDef.id.id IN(:patDatasetDefIdList)
LEFT JOIN patDataset.dataPatients data_patient_PAT_SEXE WITH (data_patient_PAT_SEXE.itemDefinition.id.id='SEXE'
AND patDatasetDef.id.id ='DIRECTORY_PATIENT')
WHERE patDataset.archive=:archive
AND patient.active=:patientState
ORDER BY (CASE
WHEN data_patient_PAT_SEXE.stringValue IS NULL THEN 1
ELSE 0
END), data_patient_PAT_SEXE.stringValue ASC
私はすでにSQLにしようと、私は完全に
LEFT OUTER JOIN dataPatient datapatien1 ON dataset.sId=datapatien1.dataSetSid
AND (datapatien1.itemDefinitionId ='SEXE')
AND datasetdef.id ='DIRECTORY_PATIENT'
作品をやりたいです
は私が休止状態https://hibernate.atlassian.net/browse/HHH-7321 でこの問題について聞いたが、私は、Hibernate 5.2で動作し、私はすでに同様の質問をチェックしました
[OK]をする必要があり、誰が同じ場合にのため
感謝を持っていませんあなたの助け