キーボードから受信ワードを使ってJavaを再起動する方法

Question

ゲームを終了したときに再びプレイしたいかどうかをユーザーに尋ねます。現在、それらを実行する唯一の方法は、プログラムを再度呼び出すことです。しかし、私は彼らがゲームを終えた後にもう一度遊びたいかどうかをユーザーに促したいと思います。

public class Hangman 
{ 

    Random r; 
    GetData get; 
    String[] words = {"eat","what" }; 
    String word; 
    boolean finished = false; 
    int badGuessCount=0; 
    boolean [] foundLetters; 
    String entryWord =" "; 

    public Hangman() 
    { 
     r = new Random(); 
     get = new GetData(); 
     playAGame(); 
    } 

    public void playAGame() 
    { 

     word = words[r.nextInt(words.length)]; 

     foundLetters = new boolean[word.length()]; 

     while (!finished) 
     { 
      showGallows(); 
      showWord(); 
      getGuess(); 
      checkGuess(); 
      if (badGuessCount==6) 
      { 
       System.out.print('\u000C'); 
       showGallows(); 
       System.out.println("Sorry, but you lost."); 
       System.out.println("The word was: "+word); 
       finished=true; 
      } 
     } 
    } 

    public void showGallows() 
    { 
     System.out.print('\u000C'); 
     if (badGuessCount==0) 
      man_0(); 
     if (badGuessCount==1) 
      man_1(); 
     if (badGuessCount==2) 
      man_2(); 
     if (badGuessCount==3) 
      man_3(); 
     if (badGuessCount==4) 
      man_4(); 
     if (badGuessCount==5) 
      man_5(); 
     if (badGuessCount==6) 
      completedMan(); 



     System.out.println("\n"); 
    } 

    public boolean showWord() 
    { 
     boolean goodGuess = false; 
     char ch = entryWord.charAt(0); 
     for (int lc=0; lc < word.length(); lc++) 
      if (foundLetters[lc]==true) 
      { 
       System.out.print(word.charAt(lc)+" "); 
      } 
      else if (word.charAt(lc)==ch) 
        { 
         System.out.print(word.charAt(lc)+" "); 
         foundLetters[lc] = true; 
         goodGuess = true; 
        } 
        else 
         System.out.print("_ "); 
     return goodGuess; 
    } 

    public void getGuess() 
    { 
     System.out.println("\n\n\nWhat letter do you want to guess?"); 
     System.out.println("Type the whole word to guess the word."); 
     System.out.println("You have "+(6 - badGuessCount)+ "guess left."); 
     System.out.print("Enter guess"); 
     entryWord = get.aWord(); 
    } 

    public void checkGuess() 
    { 
     boolean goodGuess; 
     if (entryWord.length()>1) 
     { 
      if (entryWord.equals(word)) 
      { 
       System.out.println("\n\nYes You won!"); 
       finished = true; 
       System.out.println("close and run if you want to play again!"); 
       String pause = get.aWord(); 
      }  
    } 
    else 
    { 
     showGallows(); 
     goodGuess = showWord(); 
     if (goodGuess) 
     { 
      System.out.println("\n\n\nGood guess"); 
      System.out.println("Press the Enter key to continue!"); 
      String pause = get.aWord(); 
     } 
      else 
      { 
      badGuessCount++; 
      System.out.println("\n\n\nBad guess!"); 
      System.out.println("Press the Enter key to continue!"); 
      String pause = get.aWord(); 
      } 
     } 

    } 

    //public void completedMan() 


} 

ユーザーに再度プレイを促し、入力に基づいてゲームを再開するにはどうすればよいですか？

Answer 1

playAGame();自体をループ内に配置する必要があります。

do 
{ 
    playAGame(); 
} while (UserWantsToKeepPlaying()); 

private boolean UserWantsToKeepPlaying() { 
    // Ask the user if they want to keep playing 
} 

私はdo示唆 - あなたは常に少なくとも一度ゲームをプレイするだろう、とあなたは（おそらく）、彼らはゲームをプレイし終わった後まで再びプレーを促すたくないのでwhileループを。

Answer 2

while（UserWantsToKeepPlaying（））;私は

do 
    { 
     playAGame(); 
    } while (UserWantsToKeepPlaying()); 
} 

public boolean UserWantsToKeepPlaying(int number) 
{ 
    for (int i = 1; i > number; i--) 
    if (number % i == 0 && i != number) return false; 
    else return true; 
    System.out.print("\n\n Play Again 'No' Press 0 Yes' Press 1 : "); 
}