'はSTD :: out_of_range'

Question

// Headers and namespace 
#include <iostream> 
#include <vector> 
#include <algorithm> 
#include <numeric> 
#include <string> 

using namespace std; 

int main() 
{ 
    //Create original table 
    vector<string> table = { "ABCDE", "FGHIJ", "KLMNO", "PRSTU", "VWXYZ" }; 

    //Get user input 
    string msg,key; 
    cout << "Enter encrypted message: "; 
    // must use cin for strings not regular cin 
    getline(cin,msg); 
    cout << "Enter key: "; 
    getline(cin,key); 

    //Remove duplicate letters 
    string newKey; 
    // changed ii + 
    for (int ii = 0; ii < key.size(); ii+= 1) { 
     if (count(newKey.begin(),newKey.end(),key.at(ii)) == 0) { 
      newKey.push_back(key.at(ii)); 
     } 
    } 


    //Check which letters from table are not already in key 
    //should be < not <= because it starts at 0 
    for (int ii = 0; ii < 5; ii += 1) { 
     for (int jj = 0; jj < 5; jj += 1) { 
      if (count(newKey.begin(),newKey.end(),table.at(ii).at(jj)) == 0) { 
       newKey.push_back(table.at(ii).at(jj)); 
      } 
     } 
    } 

    //Create new table 

    cout << "Updated table: " << endl; 
    //kk must begin at 0 not 1 
    int kk = 0; 
     for (int ii = 0; ii < 5; ii += 1) { 
       for (int jj = 0; jj < 5; jj += 1) { 
       table.at(ii).at(jj) = newKey.at(kk); 
       cout << table.at(ii).at(jj); 
       kk += 1; 

     } 
      //move end line to outer for loop to make table 
      cout << endl; 
    } 


    //Copy original message 
    // msg and decrypt in wrong order 
    string decrypt = msg; 

    //Process every letter in message in groups of two 
    //counter must start at 1 
    int cnt = 1; 
    //change to <= 
    while (cnt <= msg.size()-1) { 
     //Look for two letters, skipping spaces/punctuation 
     string letters; 
     vector<int> spot; 
     while (letters.size() < 2) { 

      if (isalpha(msg.at(cnt))) { 
       letters.push_back(toupper(msg.at(cnt))); 
       spot.push_back(cnt); 
      } 
      //missing ; 
      cnt += 1; 
     } 

     //Find the row and columns of the two letters 
     int r1 = 0,c1 = 0; 
     for (int ii = 0; ii < 5; ii += 1) { 
      //letters must start at 1 
      c1 = table.at(ii).find(letters.at(1)); 
      if (c1 != string::npos) { 

       // order of lines switched so code r1=ii will be used 
       r1 = ii; 
       break; 
      } 

     } 

     int r2 = 0,c2 = 0; 
     for (int ii = 0; ii < 5; ii += 1) { 
      //letters must start at 2 
      c2 = table.at(ii).find(letters.at(2)); 
      if (c2 != string::npos) { 
       // order of lines switched so code r1=ii will be used 
       r2 = ii; 
       break; 
      } 

     } 



     //If the letters are in the same row 
     //switched contents of if and elseif statements 
     if (r1 == r2) { 
      c1 = c1-1; 
      c2 = c2-1; 
      //If in the same column 
     } else if (c1 == c2) { 
      r1 = r1-1; 
      r2 = r2-1; 
      //Different row/column combo 
     } else { 
      //must swap c2 with c1 
      swap(c2,c1); 
     } 

     //Adjust r1,c1 and r2,c2 to make sure they don't off the table 
     //all must be == not less than zero 
     if (c1 == 0) { c1 = 5; } 
     if (c2 == 0) { c2 = 5; } 
     if (r1 == 0) { r1 = 5; } 
     if (r2 == 0) { r2 = 5; } 

     //Find new letters for pair 
     decrypt.at(spot.at(1)) = table.at(r1).at(c1); 
     decrypt.at(spot.at(2)) = table.at(r2).at(c2); 

     //Correct for lowercase 
     // missing beginning curly brace 
     //spot must be at 1 
     if (islower(msg.at(spot.at(1)))) { 
      //spot must be at 1 
      decrypt.at(spot.at(1)) = tolower(decrypt.at(spot.at(1))); 
     } 
     //spot must be at 2 
     if (islower(msg.at(spot.at(2)))) { 
      //spot must be at 2 
      decrypt.at(spot.at(2)) = tolower(decrypt.at(spot.at(2))); 
     } 

    } 

//Remove any X's 
decrypt.erase(remove(decrypt.begin(),decrypt.end(),'X'),decrypt.end()); 

//Show secret message 
cout << "Secret message: " << decrypt << endl; 

return 0; 
} 

それはライン86でエラーを投げているのインスタンス投げた後に呼び出さ終了 "のC1 = table.atを（II）.find（letters.at（1））;"。このエラーを解決する方法が不明です。私は数時間の間それをぶち壊すのを見つめていませんでした。私はインターネットとこのサイトを検索し、解決策を見つけることができませんでした。助けてください。

Answer 1

コードをデバッグしようとしましたが、例外は99行目でc2 = table.at(ii).find(letters.at(2));でスローされます。実際には99行目では2の文字にアクセスしていますが、2の文字はエラーです。