HTTPフォームのログインプログラムで間違いはどこですか？

Question

httpリクエストでログイン値を投稿して保護されたhtmlページを表示しようとしています...このサイトはsportguru.co.ukであり、正しくパスワードを投稿できないようです。私はこのコード（私の実際のログインの詳細を）実行すると：

/** 
* $Id: LoginByHttpPost.java 101 2010-03-13 23:52:31Z oneyour $ 
* 
* This is an accompanying program for the article 
* http://www.1your.com/drupal/LoginToWebsiteByHTTPPOSTCodeListing 
* 
* Copyright (c) 2009 - 2010 www.1your.com. All rights reserved. 
* 
* Redistribution and use in source and binary forms, with or without 
* modification, are permitted provided that the following conditions 
* are met: 
* 
* - Redistributions of source code must retain the above copyright 
*  notice, this list of conditions and the following disclaimer. 
* 
* - Redistributions in binary form must reproduce the above copyright 
*  notice, this list of conditions and the following disclaimer in the 
*  documentation and/or other materials provided with the distribution. 
* 
* - Neither the name of www.1your.com nor the names of its 
*  contributors may be used to endorse or promote products derived 
*  from this software without specific prior written permission. 
* 
* THIS SOFTWARE IS PROVIDED BY THE COPYRIGHT HOLDERS AND CONTRIBUTORS "AS 
* IS" AND ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, 
* THE IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR 
* PURPOSE ARE DISCLAIMED. IN NO EVENT SHALL THE COPYRIGHT OWNER OR 
* CONTRIBUTORS BE LIABLE FOR ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL, 
* EXEMPLARY, OR CONSEQUENTIAL DAMAGES (INCLUDING, BUT NOT LIMITED TO, 
* PROCUREMENT OF SUBSTITUTE GOODS OR SERVICES; LOSS OF USE, DATA, OR 
* PROFITS; OR BUSINESS INTERRUPTION) HOWEVER CAUSED AND ON ANY THEORY OF 
* LIABILITY, WHETHER IN CONTRACT, STRICT LIABILITY, OR TORT (INCLUDING 
* NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY OUT OF THE USE OF THIS 
* SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF SUCH DAMAGE. 
* 
*/ 

import java.net.*; 
import java.io.*; 

public class LoginByHttpPost 
{ 
    private static final String POST_CONTENT_TYPE = "application/x-www-form-urlencoded"; 
    private static final String LOGIN_ACTION_NAME = "Log in"; 
    private static final String LOGIN_USER_NAME_PARAMETER_NAME = "email"; 
    private static final String LOGIN_PASSWORD_PARAMETER_NAME = "password"; 

    private static final String LOGIN_USER_NAME = "emailAddress"; 
    private static final String LOGIN_PASSWORD = "password"; 

    private static final String TARGET_URL = "http://www.sportguru.co.uk/login_form.asp"; 

    public static void main (String args[]) 
    { 
     System.out.println("About to run the 'LogInByHttpPost' downloaded from www.1Your.com"); 
     LoginByHttpPost httpUrlBasicAuthentication = new LoginByHttpPost(); 
     httpUrlBasicAuthentication.httpPostLogin(); 
    } 

    /** 
    * The single public method of this class that 
    * 1. Prepares a login message 
    * 2. Makes the HTTP POST to the target URL 
    * 3. Reads and returns the response 
    * 
    * @throws IOException 
    * Any problems while doing the above. 
    * 
    */ 
    public void httpPostLogin() 
    { 
     try 
     { 
      // Prepare the content to be written 
      // throws UnsupportedEncodingException 
      String urlEncodedContent = preparePostContent(LOGIN_USER_NAME, LOGIN_PASSWORD); 

      HttpURLConnection urlConnection = doHttpPost(TARGET_URL, urlEncodedContent); 

      String response = readResponse(urlConnection); 

      System.out.println("Successfully made the HTPP POST."); 
      System.out.println("Recevied response is: '/n" + response + "'"); 

      System.out.println("/n Hope you found the article and this sample program useful./nPlease leave your feed back at www.1your.com and support us."); 
     } 
     catch(IOException ioException) 
     { 
      System.out.println("Problems encounterd."); 
     } 
    } 

    /** 
    * Using the given username and password, and using the static string variables, prepare 
    * the login message. Note that the username and password will encoded to the 
    * UTF-8 standard. 
    * 
    * @param loginUserName 
    * The user name for login 
    * 
    * @param loginPassword 
    * The password for login 
    * 
    * @return 
    * The complete login message that can be HTTP Posted 
    * 
    * @throws UnsupportedEncodingException 
    * Any problems during URL encoding 
    */ 
    private String preparePostContent(String loginUserName, String loginPassword) throws UnsupportedEncodingException 
    { 
     // Encode the user name and password to UTF-8 encoding standard 
     // throws UnsupportedEncodingException 
     String encodedLoginUserName = URLEncoder.encode(loginUserName, "UTF-8"); 
     String encodedLoginPassword = URLEncoder.encode(loginPassword, "UTF-8"); 

     String content = "Log in=" + LOGIN_ACTION_NAME +" &" + LOGIN_USER_NAME_PARAMETER_NAME +"=" 
     + encodedLoginUserName + "&" + LOGIN_PASSWORD_PARAMETER_NAME + "=" + encodedLoginPassword; 

     return content; 

    } 

    /** 
    * Makes a HTTP POST to the target URL by using an HttpURLConnection. 
    * 
    * @param targetUrl 
    * The URL to which the HTTP POST is made. 
    * 
    * @param content 
    * The contents which will be POSTed to the target URL. 
    * 
    * @return 
    * The open URLConnection which can be used to read any response. 
    * 
    * @throws IOException 
    */ 
    public HttpURLConnection doHttpPost(String targetUrl, String content) throws IOException 
    { 
     HttpURLConnection urlConnection = null; 
     DataOutputStream dataOutputStream = null; 
     try 
     { 
      // Open a connection to the target URL 
      // throws IOException 
      urlConnection = (HttpURLConnection)(new URL(targetUrl).openConnection()); 

      // Specifying that we intend to use this connection for input 
      urlConnection.setDoInput(true); 

      // Specifying that we intend to use this connection for output 
      urlConnection.setDoOutput(true); 

      // Specifying the content type of our post 
      urlConnection.setRequestProperty("Content-Type", POST_CONTENT_TYPE); 

      // Specifying the method of HTTP request which is POST 
      // throws ProtocolException 
      urlConnection.setRequestMethod("POST"); 

      // Prepare an output stream for writing data to the HTTP connection 
      // throws IOException 
      dataOutputStream = new DataOutputStream(urlConnection.getOutputStream()); 

      // throws IOException 
      dataOutputStream.writeBytes(content); 
      dataOutputStream.flush(); 
      dataOutputStream.close(); 

      return urlConnection; 
     } 
     catch(IOException ioException) 
     { 
      System.out.println("I/O problems while trying to do a HTTP post."); 
      ioException.printStackTrace(); 

      // Good practice: clean up the connections and streams 
      // to free up any resources if possible 
      if (dataOutputStream != null) 
      { 
       try 
       { 
        dataOutputStream.close(); 
       } 
       catch(Throwable ignore) 
       { 
        // Cannot do anything about problems while 
        // trying to clean up. Just ignore 
       } 
      } 
      if (urlConnection != null) 
      { 
       urlConnection.disconnect(); 
      } 

      // throw the exception so that the caller is aware that 
      // there was some problems 
      throw ioException; 
     } 
    } 

    /** 
    * Read response from the URL connection 
    * 
    * @param urlConnection 
    * The URLConncetion from which the response will be read 
    * 
    * @return 
    * The response read from the URLConnection 
    * 
    * @throws IOException 
    * When problems encountered during reading the response from the 
    * URLConnection. 
    */ 
    private String readResponse(HttpURLConnection urlConnection) throws IOException 
    { 

     BufferedReader bufferedReader = null; 
     try 
     { 
      // Prepare a reader to read the response from the URLConnection 
      // throws IOException 
      bufferedReader = new BufferedReader(new InputStreamReader(urlConnection.getInputStream())); 
      String responeLine; 

      // Good Practice: Use StringBuilder in this case 
      StringBuilder response = new StringBuilder(); 

      // Read untill there is nothing left in the stream 
      // throws IOException 
      while ((responeLine = bufferedReader.readLine()) != null) 
      { 
       response.append('\n'+responeLine); 
      } 

      return response.toString(); 
     } 
     catch(IOException ioException) 
     { 
      System.out.println("Problems while reading the response"); 
      ioException.printStackTrace(); 

      // throw the exception so that the caller is aware that 
      // there was some problems 
      throw ioException; 

     } 
     finally 
     { 
      // Good practice: clean up the connections and streams 
      // to free up any resources if possible 
      if (bufferedReader != null) 
      { 
       try 
       { 
        // throws IOException 
        bufferedReader.close(); 
       } 
       catch(Throwable ignore) 
       { 
        // Cannot do much with exceptions doing clean up 
        // Ignoring all exceptions 
       } 
      } 

     } 
    } 
} 

を私が受け取るHTMLページには、このフォームが含まれています

<form name="loginPage" method="post" action="login.asp" onSubmit="return submitForm()" style="margin:0px;padding:0px"> 
    <input type="hidden" name="pageReferer" value="" /> 
    <input type="hidden" name="logintype" value="page" /> 
    <input type="hidden" name="pagePoolCode" value="" /> 

<div style="border:2px solid #666666;width:486px"> 
    <div style="background-image:url(home/images/structure/header_login.gif);height:28px;"></div> 
    <div style="padding:7px;"> 
     <table cellspacing="2" cellspacing="0"> 
     <tr> 
      <td align="right" width="62">Email:</td> 
      <td><input type="text" name="pageEmail" value="emailAddress" size="32"></td> 
     </tr> 
     <tr> 
      <td align="right">Password:</td> 
      <td><input type="password" name="pagePassword" size="32"></td> 
     </tr> 
     <tr> 
      <td align="right"></td> 
      <td class="small"><a href="forgotten.asp"><strong>Forgotten</strong> your email address or password? Or has your<br /><strong>email changed</strong> since last you used the site? <strong>Click here</strong> &raquo;</a></td> 
     </tr> 
     <tr> 
      <td>&nbsp;</td> 
      <td style="padding-top:7px;"><input type="image" src="/home/images/buttons/login.gif" value="Log in"></td> 
     </tr> 

    </table> 
    </div> 
</div> 
</form> 

としては、メールアドレスが正しくフォームに掲載されて見ることができます。しかし、私はポストの後にHTMLページのソースを表示したい...私はクッキーや何かが必要ですか？

Answer 1

HTTPステータスコードを確認しましたか？リダイレクトがある可能性があります。

Answer 2

String content = "Log in=" + LOGIN_ACTION_NAME +" &" + LOGIN_USER_NAME_PARAMETER_NAME +"=" 
    + encodedLoginUserName + "&" + LOGIN_PASSWORD_PARAMETER_NAME + "=" + encodedLoginPassword; 

実際にはLog inにスペースが必要ですか？

Log%20inまたはLog+inとなります。 （私はあなたの完全な形が表示されないように、私はここでしか推測できます。）

---

だから、我々はこれらのフォームフィールドに送信する必要があります：

• pageReferer（空）
• logintypeを（ page）
• pagePoolCode（空）
• pageEmail（メールアドレス？）
• pagePassword（？パスワード）

も<input type="image" src="/home/images/buttons/login.gif" value="Log in">あります - これは何の名前属性を持っていないので、それが送信することはできません。したがって、私の最初の推測では、コンテンツ文字列のこの部分を単に省略することになります。これが機能しない場合

String content = LOGIN_USER_NAME_PARAMETER_NAME + "=" 
    + encodedLoginUserName + "&" + LOGIN_PASSWORD_PARAMETER_NAME + "=" + encodedLoginPassword; 

、文字列にも最初の3つのフィールドを追加していない：

String content = "pageReferer=&loginType=page&pagePoolCode=&" + 
    LOGIN_USER_NAME_PARAMETER_NAME + "=" 
    + encodedLoginUserName + "&" + LOGIN_PASSWORD_PARAMETER_NAME + "=" + encodedLoginPassword;