SQL Server 2008で列を列に、列を列に、SQL Server 2008で列を切り替える方法

Question

SQL Server 2008では行を列に、列を列に切り替えるのに問題があり、ソリューションへのクエリを試しましたが、適切な結果が得られませんでした。

私は、次のような表をしました：

 
declare @tmpTable table 
(name varchar(20), date_ date, sales_code char(1), sales smallint, earned int) 

insert into @tmpTable 
values ('Robert', '2016/8/1', 'A', 2, 30), 
('Robert', '2016/8/1', 'B', 3, 45), 
('Robert', '2016/8/2', 'B', 1, 15), 
('Robert', '2016/8/3', 'B', 2, 30), 
('Jhon', '2016/8/1', 'A', 3, 45), 
('Jhon', '2016/8/2', 'A', 3, 45), 
('Jhon', '2016/8/3', 'B', 2, 30) 

select * from @tmpTable; 

結果：それは結果を表示します

 
select * from (
select name, 'sales_code' as category, date_, sales_code from (
select * from (
SELECT name, date_ 
     ,STUFF((SELECT ', ' + sales_code [text()] 
     FROM @tmpTable 
     WHERE date_ = t.date_ 
     FOR XML PATH(''), TYPE) 
     .value('.','NVARCHAR(MAX)'),1,2,' ') sales_code 
       ,STUFF((SELECT ', ' + convert(varchar(max), sales) [text()] 
     FROM @tmpTable 
     WHERE date_ = t.date_ 
     FOR XML PATH(''), TYPE) 
     .value('.','NVARCHAR(MAX)'),1,2,' ') sales 
       ,STUFF((SELECT ', ' + convert(varchar(max), earned) [text()] 
     FROM @tmpTable 
     WHERE date_ = t.date_ 
     FOR XML PATH(''), TYPE) 
     .value('.','NVARCHAR(MAX)'),1,2,' ') earned 
FROM @tmpTable t 
GROUP BY name, date_ 
) as a 
) as a 
) as a 
pivot (
    max(sales_code) FOR date_ IN ([2016/8/1], [2016/8/2], [2016/8/3]) 
)as pv 

union all 

select * from (
select name, 'sales' as category, date_, sales from (
select * from (
SELECT name, date_ 
     ,STUFF((SELECT ', ' + sales_code [text()] 
     FROM @tmpTable 
     WHERE date_ = t.date_ 
     FOR XML PATH(''), TYPE) 
     .value('.','NVARCHAR(MAX)'),1,2,' ') sales_code 
       ,STUFF((SELECT ', ' + convert(varchar(max), sales) [text()] 
     FROM @tmpTable 
     WHERE date_ = t.date_ 
     FOR XML PATH(''), TYPE) 
     .value('.','NVARCHAR(MAX)'),1,2,' ') sales 
       ,STUFF((SELECT ', ' + convert(varchar(max), earned) [text()] 
     FROM @tmpTable 
     WHERE date_ = t.date_ 
     FOR XML PATH(''), TYPE) 
     .value('.','NVARCHAR(MAX)'),1,2,' ') earned 
FROM @tmpTable t 
GROUP BY name, date_ 
) as a 
) as a 
) as a 
pivot (
    max(sales) FOR date_ IN ([2016/8/1], [2016/8/2], [2016/8/3]) 
)as pv 

union all 

select * from (
select name, 'earned' as category, date_, earned from (
select * from (
SELECT name, date_ 
     ,STUFF((SELECT ', ' + sales_code [text()] 
     FROM @tmpTable 
     WHERE date_ = t.date_ 
     FOR XML PATH(''), TYPE) 
     .value('.','NVARCHAR(MAX)'),1,2,' ') sales_code 
       ,STUFF((SELECT ', ' + convert(varchar(max), sales) [text()] 
     FROM @tmpTable 
     WHERE date_ = t.date_ 
     FOR XML PATH(''), TYPE) 
     .value('.','NVARCHAR(MAX)'),1,2,' ') sales 
       ,STUFF((SELECT ', ' + convert(varchar(max), earned) [text()] 
     FROM @tmpTable 
     WHERE date_ = t.date_ 
     FOR XML PATH(''), TYPE) 
     .value('.','NVARCHAR(MAX)'),1,2,' ') earned 
FROM @tmpTable t 
GROUP BY name, date_ 
) as a 
) as a 
) as a 
pivot (
    max(earned) FOR date_ IN ([2016/8/1], [2016/8/2], [2016/8/3]) 
)as pv 

：

 
Name  date_   sales_code sales earned 
------  ----------  ---------- ----- ------ 
Robert  2016-08-01  A   2  30 
Robert  2016-08-01  B   3  45 
Robert  2016-08-02  B   1  15 
Robert  2016-08-03  B   2  30 
Jhon  2016-08-01  A   3  45 
Jhon  2016-08-02  A   3  45 
Jhon  2016-08-03  B   2  30 

はその後、私は次のクエリを持っている

 
name  category 2016/8/1  2016/8/2 2016/8/3 
-------  -------- --------  -------  -------- 
Jhon  sales_code A, B, A   B, A  B, B 
Robert  sales_code A, B, A   B, A  B, B 
Jhon  sales  2, 3, 3   1, 3  2, 2 
Robert  sales  2, 3, 3   1, 3  2, 2 
Jhon  earned  30, 45, 45  15, 45  30, 30 
Robert  earned  30, 45, 45  15, 45  30, 30 

しかし、私は次のような結果を取得したいと思います：任意の助け

 
name  category 2016/8/1 2016/8/2 2016/8/3 
----  -------- -------- -------- -------- 
Robert  sales_code A, B  B   B 
Robert  sales  2, 3  1   2 
Robert  earned  30, 45  15   30 
Jhon  sales_code A   A   B 
Jhon  sales  3   3   2 
Jhon  earned  45   45   30 

おかげで多くのことを。

Answer 1

最初にデータをピボット解除する必要があります。すべてのデータ型が一致するため、2つの数値列をvarcharsに変換する必要があります。

名前を1つにまとめた値を取得するためにunpivotを使用する前にまだstuffを使用していますが、名前を取得するためにdistinctを使用します。

あなたがピボット解除した後、もう一度ピボットするだけです。

SELECT * 
FROM ( SELECT DISTINCT 
       Name, 
       date_, 
       sales_code = STUFF((SELECT ', ' + sales_code 
            FROM @tmpTable t2 
            WHERE t2.Name = t.Name AND t2.date_ = t.date_ 
            FOR XML PATH('')), 1, 2, ''), 
       sales  = STUFF((SELECT ', ' + CONVERT(VARCHAR, sales) 
            FROM @tmpTable t2 
            WHERE t2.Name = t.Name AND t2.date_ = t.date_ 
            FOR XML PATH('')), 1, 2, ''), 
       earned  = STUFF((SELECT ', ' + CONVERT(VARCHAR, earned) 
            FROM @tmpTable t2 
            WHERE t2.Name = t.Name AND t2.date_ = t.date_ 
            FOR XML PATH('')), 1, 2, '') 
     FROM @tmpTable t) t 
UNPIVOT (
    val 
    FOR category IN (sales_code, sales, earned) 
) up 
PIVOT (
    MAX(val) 
    FOR date_ IN ([2016-08-01], [2016-08-02], [2016-08-03]) 
) p 
ORDER BY name DESC, 
     category DESC