文字列配列で個別の値を取得するにはどうすればよいですか？

Question

私は別にように、これらの個別の値を取得するために、これらの2つの文字列の配列を比較したい2つの文字列の配列ここ

string[] oldname = ["arun","jack","tom"]; 
string[] newname = ["jack","hardy","arun"]; 

を持っています。これらを達成する方法を

oldname = ["tom"]; 
newname = ["hardy"]; 

...

Answer 1

string[] oldNameDistinct = oldname.Where(s => !newname.Contains(s)).ToArray(); 
string[] newNameDistinct = newname.Where(s => !oldname.Contains(s)).ToArray(); 

Answer 2

てみよう2つのアレイが以下のように定義された：

string[] oldname = new[] { "arun", "jack", "tom" }; 
string[] newname = new string[] { "jack", "hardy", "arun" }; 

次に、拡張メソッド.Exceptを使用して、探している結果を得ることができます。これを試してみてください、次のコードとworking example

var distinctInOld = oldname.Except(newname); 
var distinctInNew = newname.Except(oldname); 

Answer 3

を考えてみましょう：

string[] oldname = new string[] { "arun", "jack", "tom" }; 
    string[] newname = new string[] { "jack", "hardy", "arun" }; 

    List<string> distinctoldname = new List<string>(); 
    List<string> distinctnewname = new List<string>(); 

    foreach (string txt in oldname) 
    { 
     if (Array.IndexOf(newname, txt) == -1) 
     distinctoldname.Add(txt); 
    } 

    foreach (string txt in newname) 
    { 
     if (Array.IndexOf(oldname, txt) == -1) 
      distinctnewname.Add(txt); 
    } 


    //here you can get both the arrays separately 

・ホープ、この助け:)

Answer 4

string[] oldname = new []{"arun","jack","tom"}; 
string[] newname = new []{"jack","hardy","arun"}; 

// use linq to loop through through each list and return values not included in the other list. 
var distinctOldName = oldname.Where(o => newname.All(n => n != o)); 
var distinctNewName = newname.Where(n => oldname.All(o => o != n)); 

distinctOldName.Dump(); // result is tom 
distinctNewName.Dump(); // result is hardy