試合金額この文字列を考慮すると、特定のサブストリング

Question

後：

Looking for a front-end developer who can fix a bug on my Wordpress site. The header logo disappeared after I updated some plugins. \n\nI have tried disabling all plugins but it didn't help.Budget: $25\nPosted On: May 06, 2016 16:29 UTCCategory: Web, Mobile & Software Dev > Web DevelopmentSkills:  WordPress   Country: Denmarkclick to apply 

私は、文字列Budget:後の価格の値を取得したいと思います。私は任意の金額を抽出するために/\$[\d.]+/を試みたが、それは文字列でBudget:を、次の1だけでなく、任意の金額を取るだろう

：私はすべて同じパターン（文字列「予算」の後に価格右）と、文字列の数を持っています

どうすれば実現できますか？

Answer 1

r =/
    \b   # match a word break 
    [Bb]  # match "B" or "b" 
    udget:  # match string 
    \s+\$  # match one or more spaces followed by a dollar sign 
    \K   # discard all matches so far 
    \d{1,3}  # match between one or three digits 
    (?:\,\d{3}) # match a comma followed by three digits in a non-capture group 
    *   # perform the preceding match zero or more times 
    (?:\.\d\d) # match a period followed by two digits in a non-capture group 
    ?   # make the preceding match optional 
    /x   # free-spacing regex definition mode 

"Some text Budget: $25\nsome more text"[r]   #=> "25" 
"Some text Budget: $25.42\nsome more text"[r]   #=> "25.24" 
"Some text Budget: $25,642,328\nsome more text"[r] #=> "25,642,328" 
"Some text Budget: $25,642,328.01\nsome more text"[r] #=> "25,642,328.01" 

これは実際には非常に適切ではないので、

"Some text Budget: $25,64,328.01\nsome more text"[r] #=> "25" 

はnilを返す必要があります。残念ながら、大手術の修正コール：

r =/
    \b    # match a word break 
    [Bb]   # match "B" or "b" 
    udget:   # match string 
    \s+\$   # match 1 or more spaces followed by a dollar sign 
    \K    # discard all matches so far 
    \d{1,3}   # match between 1 and 3 digits 
    (?:    # begin a non-capture group 
     (?![\,\d]) # match a comma or digit in a negative lookahead 
     |    # or 
     (?:   # begin a non-capture group 
     (?:\,\d{3}) # match a comma followed by 3 digits in a non-capture group 
     +   # perform preceding match 1 or more times 
    )    # end non-capture group 
    )    # end non-capture group 
    (?:\.\d\d)  # match a period followed by 2 digits in a non-capture group 
    ?    # make the preceding match optional 
    /x 

"Some text Budget: $25\nsome more text"[r]   #=> "25" 
"Some text Budget: $25.42\nsome more text"[r]   #=> "25.24" 
"Some text Budget: $25,642,328\nsome more text"[r] #=> "25,642,328" 
"Some text Budget: $25,642,328.01\nsome more text"[r] #=> "25,642,328.01" 
"Some text Budget: $25,64,328.01\nsome more text"[r] #=> nil 

Answer 2

このお試しください：s1場合

def extract_budget s 
    m = s.match(/Budget: \$([\d,.]+)\n/) 
    if m.nil? 
    nil 
    else 
    m.captures[0].gsub(/,/, "").to_f 
    end 
end 

は、あなたの文字列で、s2は同じ文字列であるが、 "予算：$ 25,000.53"：で

irb> extract_budget s1 
=> 25.0 
irb> extract_budget s2 
=> 25000.53 
irb> extract_budget "foo" 
=> nil 

Answer 3

あなたは、文字列「予算：」と言う：

/Budget:(\s*\$\d*)/