私は、次のレコードを検索するために、SQLウィンドウ関数のLEADを使用し、ユーザーと日によって仕切られています。その後、同じユーザーと同じ日付の2回の作業分を計算しました。
データを一時テーブルに挿入してグループ化し、合計作業時間を取得します。 SELECT * FROM #tempTime;を使用できます。最後の選択クエリの前にを実行して、結果を確認してください。これは、コードが正しく動作しているかどうかを示します。
決勝コード:
IF OBJECT_ID('dbo.Fichajes') IS NULL
CREATE TABLE dbo.Fichajes(
[Empleado] [varchar](20) NULL,
[Obra] [varchar](20) NULL,
[Hora] [datetime2](7) NULL,
[Entrada] [bit] NULL,
[Motivo] [varchar](20) NULL,
[Activated] [bit] NULL
)
;
INSERT [dbo].[Fichajes] ([Empleado], [Obra], [Hora], [Entrada], [Motivo], [Activated]) VALUES (N'12212332W', N'PRY12345', CAST(N'2017-04-17 12:03:00.0000000' AS DateTime2), 1, NULL, NULL)
INSERT [dbo].[Fichajes] ([Empleado], [Obra], [Hora], [Entrada], [Motivo], [Activated]) VALUES (N'20498090R', N'PRY12345', CAST(N'2017-04-20 12:21:00.0000000' AS DateTime2), 1, NULL, NULL)
INSERT [dbo].[Fichajes] ([Empleado], [Obra], [Hora], [Entrada], [Motivo], [Activated]) VALUES (N'20498090R', N'PRY12345', CAST(N'2017-04-20 12:25:00.0000000' AS DateTime2), 0, NULL, NULL)
INSERT [dbo].[Fichajes] ([Empleado], [Obra], [Hora], [Entrada], [Motivo], [Activated]) VALUES (N'41435568N', N'PRY12345', CAST(N'2017-04-20 12:23:00.0000000' AS DateTime2), 1, NULL, NULL)
INSERT [dbo].[Fichajes] ([Empleado], [Obra], [Hora], [Entrada], [Motivo], [Activated]) VALUES (N'41435568N', N'PRY12345', CAST(N'2017-04-20 12:29:00.0000000' AS DateTime2), 0, NULL, NULL)
INSERT [dbo].[Fichajes] ([Empleado], [Obra], [Hora], [Entrada], [Motivo], [Activated]) VALUES (N'20498090R', N'PRY12345', CAST(N'2017-04-25 10:00:00.0000000' AS DateTime2), 1, NULL, NULL)
INSERT [dbo].[Fichajes] ([Empleado], [Obra], [Hora], [Entrada], [Motivo], [Activated]) VALUES (N'20498090R', N'PRY12345', CAST(N'2017-04-25 11:15:00.0000000' AS DateTime2), 0, NULL, NULL)
IF OBJECT_ID('tempdb..#tempTime') IS NOT NULL DROP TABLE #tempTime;
with c1 AS
(
SELECT
[Empleado]
,[Obra]
,[Entrada]
,[Motivo]
,[Activated]
,CONVERT(date, Hora) AS [Date]
,CONVERT(time, Hora, 114) AS [Time]
,[Hora]
FROM [dbo].[Fichajes]
)
SELECT
[Empleado]
,[Hora]
,LAG([Hora]) OVER(PARTITION BY [Empleado], [Date] ORDER BY [Empleado], [Hora] ASC) AS PreviousRecord
,LEAD([Hora]) OVER(PARTITION BY [Empleado], [Date] ORDER BY [Empleado], [Hora] ASC) AS NextRecord
,DATEDIFF(MINUTE, [Hora], LEAD([Hora]) OVER(PARTITION BY [Empleado], [Date] ORDER BY [Empleado], [Hora] ASC)) AS [Minutes]
INTO #tempTime
FROM c1
;
SELECT
[Empleado]
,SUM([Minutes]) AS WorkingMinutes
FROM #tempTime
GROUP BY [Empleado]
;
@jarlh MSSQLが、最後に、SQL – Pablo
MySQLとMS SQL Serverが異なる日付/時刻の機能を持っています。 – jarlh
@jarlh混乱して申し訳ありませんが、最初の投稿は私のクエリです – Pablo