数行のコードを持つ文字の行列を別の行列に変換するにはどうすればよいですか？

Question

I持っている（私はマトリックス型に固執していない - それはまたdata.frame、...することができる）、次のマトリック：私はそれが

 V1 V2 V3 V4 
[1,] "Jan" "Jan" "Jul" "Jul" 
[2,] "01" "01" "06" "06" 
[3,] "Dec" "Jun" "Dec" "Dec" 
[4,] "31" "30" "31" "31" 
[5,] "00" "12" "09" "09" 
[6,] "00" "00" "00" "00" 
[7,] "24" "18" "19" "19" 
[8,] "00" "00" "00" "00" 

のように見えるようにするにはどうすればよい

df <- structure(c("Jan-01", "Dec-31", "00-00", "24-00", "Jan-01", "Jun-30", 
"12-00", "18-00", "Jul-06", "Dec-31", "09-00", "19-00", "Jul-06", 
"Dec-31", "09-00", "19-00"), .Dim = c(4L, 4L), .Dimnames = list(
    NULL, c("V1", "V2", "V3", "V4"))) 

#  V1  V2  V3  V4  
# [1,] "Jan-01" "Jan-01" "Jul-06" "Jul-06" 
# [2,] "Dec-31" "Jun-30" "Dec-31" "Dec-31" 
# [3,] "00-00" "12-00" "09-00" "09-00" 
# [4,] "24-00" "18-00" "19-00" "19-00" 

これは、各セルを「 - 」で分割し、2行のベクトルに変換することを意味します。
hereの方法で試しましたが、結果は良好ではありませんでした。ここでt(str_split_fixed(new_standard, "\\-", 8))

Answer 1

が一つの解決策である：

library(stringr) 
matrix(t(str_split_fixed(df, "-", 2)), ncol = 4) 
#  [,1] [,2] [,3] [,4] 
# [1,] "Jan" "Jan" "Jul" "Jul" 
# [2,] "01" "01" "06" "06" 
# [3,] "Dec" "Jun" "Dec" "Dec" 
# [4,] "31" "30" "31" "31" 
# [5,] "00" "12" "09" "09" 
# [6,] "00" "00" "00" "00" 
# [7,] "24" "18" "19" "19" 
# [8,] "00" "00" "00" "00" 

Answer 2

列の数が私の場合には固定されていないと我々はscan

base Rから

matrix(scan(text=df, sep="-", what ="", quiet=TRUE), ncol=4) 
#  [,1] [,2] [,3] [,4] 
#[1,] "Jan" "Jan" "Jul" "Jul" 
#[2,] "01" "01" "06" "06" 
#[3,] "Dec" "Jun" "Dec" "Dec" 
#[4,] "31" "30" "31" "31" 
#[5,] "00" "12" "09" "09" 
#[6,] "00" "00" "00" "00" 
#[7,] "24" "18" "19" "19" 
#[8,] "00" "00" "00" "00"