一致する行のみを返すSQL Server

Question

このシンプルですが、私は本当に立ち往生しています。ここで私は同じ構造を持っており、この場合のデータまたはレコード

TableAの

Ref cola colb id 
------------------ 
1  a  b 14 
1  a  b 24 

TableBの二つの表から必要な結果セットの例がある

Ref cola colb id 
------------------ 
1  a  b 1 
1  a  b 2 
1  a  b 3 

期待される結果：

Ref cola colb id Ref1 cola1 colb1 id1 
---------------------------------------- 
1  a  b 14 1  a  b 1 
1  a  b 24 1  a  b 2 

Answer 1

使用：

SELECT * 
FROM table1 t1 
JOIN Table2 t2 
ON t1.Ref =t2.Ref AND t1.cola = t2.cola 
    AND t1.colb = t2.colb AND t1.id = t2.id 

又は

SELECT * 
FROM table1 t1 
JOIN Table2 t2 
USING (Ref , cola , colb, id) 

Answer 2

もう一つの方法は

;with cte 
as 
(
select Ref, cola, colb, id, 
hashbytes('sha1',concat(Ref, cola, colb)) as tb1hash 
from table1 
) 
select 
t1.Ref, --all required cols 
from cte c 
join 
(
select Ref, cola, colb, id, 
hashbytes('sha1',concat(Ref, cola, colb)) as tb2hash 
from table2 
) b 
on 
b.tb2hash=c.tb1hash 

Answer 3

が推測されるであろう：

;WITH TableAWithRowNum 
AS (
SELECT *, ROW_NUMBER(ORDER BY id) AS RowNum 
FROM dbo.TableA 
), TableBWithRowNum 
AS (
SELECT *, ROW_NUMBER(ORDER BY id) AS RowNum 
FROM dbo.TableB 
) 
SELECT a.*, b.* 
FROM TableAWithRowNum a 
INNER JOIN TableBWithRowNum b ON a.Ref = b.Ref 
--AND other join predicates on ColA, ... etc. 
AND a.RowNum = b.RowNum