PythonでResume Parser APIにアクセスする

Question

私は、このコードをレジューム解析APIにアクセスするために使用しています。 「ResumeParser」オブジェクトには「エンコード」属性がありません。「AttributeError： 'ResumeParser'オブジェクトには属性名「 」がありません。このエラーを解決するにはどうすればよいですか？

あなたが代わりに _init_のコンストラクタメソッドとして __init__を定義する必要があり

import os 
from xml.dom import minidom 
from pysimplesoap.client import SoapClient 
from pysimplesoap.helpers import sort_dict 


class ParserClient(SoapClient): 
'''extends the soap client to encode the response with utf-8 encoding''' 
def wsdl_call(self,method,*args,**kwargs): 
    '''override wsdl call method to make sure unmarshall is not called''' 
    operation=self.get_operation(method) 
    inp=operation['input'] 
    header=operation.get('header') 
    if 'action' in operation: 
     self.action=operation['action'] 
    if header: 
     self._call_headers=sort_dict(header,self._headers) 
    method,params=self.wsdl_call_get_params(method,inp,*args,**kwargs) 
    response=self.call(method,*params) 
    return response 

def send(self,method,xml): 
    content=super(ParserClient,self).send(method,xml) 
    self.result=content 
    return content 


class ResumeParser(object): 
'''Connect to the resume parser's XML API to get parsed data''' 
def _init_(self,simple=True,timeout=60): 
    '''initialize resume parser class''' 
    self.wsdl="http://jobsite.onlineresumeparser.com/rPlusParseResume.asmx?WSDL" 
    self.secret="" #enter key here 
    self.encoding="base64" 
    self.simple=simple 
    self.client=ParserClient(wsdl=self.wsdl,timeout=timeout) 
    self.names=[] 

def get_file_content(self,file_path): 
    '''return the encoded content for a given file''' 
    file_obj=open(os.path.abspath(file_path),'r') 
    content=file_obj.read().encode(self.encoding) 
    file_obj.close() 
    return content 

def get_names(self,path): 
    '''Given a path to folder that contain resume files this method will parse 
    the resumes and will return the names of the candidates as a list''' 
    opt=os.path 
    resumes=[opt.join(path,r) for r in os.listdir(path) if opt.isfile(opt.join(path,r))] 
    #parse information for each resume 
    for resume in resumes: 
     try: 
      xml_data=self.get_xml(resume) 
      print xml_data 
      name=self.get_name_from_xml(xml_data) 

      if name: 
       self.names.append(name) 
       print name 
     except Exception,err: 
      print "error parsing resume:%s" % str(err) 
    return list(set(self.names)) 


def get_name_from_xml(self,data): 
    '''return the full name from the xml data given''' 
    xmldata=minidom.parseString(data) 
    name=xmldata.getElementsByTagName("CANDIDATE_FULL_NAME") 
    name=name[0].childNodes[0].data.title() 
    print '\n name of student: ',name 
    return name 

def get_xml(self,filepath): 
    '''fetches and returns the xml for the given file from the api''' 
    filename=os.path.basename(filepath) 
    base64=self.get_file_content(filepath) 
    filedata={ 
     'B64FileZippedContent':base64, 
     'FileName':filename, 
     'UserID':1, 
     'secretKey':self.secret 
     } 
    get=self.client.Get_SimpleXML if self.simple else self.client.get_HRXML 
    get(**filedata) 

    return self.process_raw_xml() 

def process_raw_xml(self,data=None): 
    '''processes and return the clean xml''' 
    raw=data if data else self.client.result 
    parsed=minidom.parseString(raw) 
    result=parsed.getElementsByTagName("Get_SimpleXMLResult")[0] 
    text_node=result.childNodes[0] 
    data=text_node.childNodes[0] 
    data=text_node.data.encode("UTF-8") 
    print data 
    return data 


obj1=ResumeParser() 
result=obj1.get_names("/home/Desktop/resumes/") 

print result 

Answer 1

（アンダースコアの数に注意を払う）