NSDateを使用して次の日付を取得するにはどうすればよいですか？

Question

可能性の重複：
iOS and finding Tomorrow

どのように私はNSDateを使用して、次の日付を取得することができます。私に解決策を送ってください。

Answer 1

以下では、yourDateは入力NSDateを表します。 nextDateは翌日を表します。

// start by retrieving day, weekday, month and year components for yourDate 
    NSCalendar *gregorian = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar]; 
    NSDateComponents *todayComponents = [gregorian components:(NSDayCalendarUnit | NSMonthCalendarUnit | NSYearCalendarUnit) fromDate:yourDate]; 
    NSInteger theDay = [todayComponents day]; 
    NSInteger theMonth = [todayComponents month]; 
    NSInteger theYear = [todayComponents year]; 

    // now build a NSDate object for yourDate using these components 
    NSDateComponents *components = [[NSDateComponents alloc] init]; 
    [components setDay:theDay]; 
    [components setMonth:theMonth]; 
    [components setYear:theYear]; 
    NSDate *thisDate = [gregorian dateFromComponents:components]; 
    [components release]; 

    // now build a NSDate object for the next day 
    NSDateComponents *offsetComponents = [[NSDateComponents alloc] init]; 
    [offsetComponents setDay:1]; 
    NSDate *nextDate = [gregorian dateByAddingComponents:offsetComponents toDate:thisDate options:0]; 
    [offsetComponents release]; 
    [gregorian release]; 

Answer 2

//のinitメソッドに以下のコードを追加するか、のviewDidLoad

[[NSUserDefaults standardUserDefaults] setObject:[NSDate date] forKey:@"Date"]; 

//あなたがこの方法について何次または前の日付を

NSDate *tomorrow = [[NSUserDefaults standardUserDefaults] valueForKey:@"Date"]; 
NSTimeInterval secondsPerDay = 24 * 60 * 60;  
NSDate *date = [tomorrow addTimeInterval:secondsPerDay]; //Change NSDate *date = [tomorrow addTimeInterval:-secondsPerDay]; for yesterday 
tomorrow = date; 
[self setDate:tomorrow]; 
dateTextField.text = [self getDate];   
[[NSUserDefaults standardUserDefaults] setObject:tomorrow forKey:@"Date"]; 

Answer 3

を取得したい、このコードを追加しますか？

http://www.drobnik.com/touch/2009/05/adding-days-to-nsdate/

NSDate *now = [NSDate date]; 
int daysToAdd = 50; // or 60 :-) 

// set up date components 
NSDateComponents *components = [[[NSDateComponents alloc] init] autorelease]; 
[components setDay:daysToAdd]; 

// create a calendar 
NSCalendar *gregorian = [[[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar] autorelease]; 

NSDate *newDate2 = [gregorian dateByAddingComponents:components toDate:now options:0]; 
NSLog(@"Clean: %@", newDate2); 

Answer 4

私は、このメソッドは私のためにうまく動作しますね。

NSString *zajtra = [[NSDate date] dateByAddingTimeInterval:86400]; 

Answer 5

NSDate *tomorrow = [NSDate dateWithTimeInterval:(24*60*60) sinceDate:[NSDate date]]; 

はるかに最も簡単な方法...