複数のオブジェクトを含むリストビューへのJSON解析Android

Question

ヘルプが必要

私はオブジェクトを取得する必要がありますが、取得することはできません。 私は複数のオブジェクトを使用して検索しましたが、成功しませんでした。 JSON：

{ 
    "status": 1, 
    "data": [{ 
     "restaurent_id": "1", 
     "user_id": "6", 
     "zone_id": "1", 
     "restaurentAddress": { 
      "restaurent_address_id": "1" 
     }, 
     "restaurentInfo": { 
      "restaurent_info_id": "1", 
      "restaurent_bussiness_owner_name": "Vijay" 
     }, 
     "restaurentSetting": { 
      "restaurent_setting_id": "1", 
      "minimum_purcase": "200", 
      "payment_method_id": "1", 
      "title": "Best Hotel" 
     }, 
     "zone": { 
      "zone_id": "1", 
      "by_zipcode": "1" 
     } 

    }] 
} 

と私はrestaurentAddressとrestaurentInfoを取得したい

MY mainActivity.javaファイル

package com.example.premi.jsonlist; 
import android.app.Activity; 
import android.os.Bundle; 
import android.widget.TextView; 

import org.json.JSONArray; 
import org.json.JSONException; 
import org.json.JSONObject; 

public class MainActivity extends Activity { 
    public void onCreate(Bundle savedInstanceState) { 
     super.onCreate(savedInstanceState); 
     setContentView(R.layout.activity_main); 

     TextView output = (TextView) findViewById(R.id.textView1); 
     String strJson="{\n" + 
       "\t\"status\": 1,\n" + 
       "\t\"data\": [{\n" + 
       "\t\t\"restaurent_id\": \"1\",\n" + 
       "\t\t\"user_id\": \"6\",\n" + 
       "\t\t\"zone_id\": \"1\",\n" + 
       "\t\t\"restaurentAddress\": {\n" + 
       "\t\t\t\"restaurent_address_id\": \"1\"\n" + 
       "\t\t},\n" + 
       "\t\t\"restaurentInfo\": {\n" + 
       "\t\t\t\"restaurent_info_id\": \"1\",\n" + 
       "\t\t\t\"restaurent_bussiness_owner_name\": \"Vijay\"\n" + 
       "\t\t},\n" + 
       "\t\t\"restaurentSetting\": {\n" + 
       "\t\t\t\"restaurent_setting_id\": \"1\",\n" + 
       "\t\t\t\"minimum_purcase\": \"200\",\n" + 
       "\t\t\t\"payment_method_id\": \"1\",\n" + 
       "\t\t\t\"title\": \"Best Hotel\"\n" + 
       "\t\t},\n" + 
       "\t\t\"zone\": {\n" + 
       "\t\t\t\"zone_id\": \"1\",\n" + 
       "\t\t\t\"by_zipcode\": \"1\"\n" + 
       "\t\t}\n" + 
       "\n" + 
       "\t}]\n" + 
       "}"; 
     String dataoutput = ""; 
     try { 
      JSONObject jsonRootObject = new JSONObject(strJson); 

      //Get the instance of JSONArray that contains JSONObjects 
      JSONObject status = jsonRootObject.optJSONObject("status"); 
      JSONArray Dataarray =status.getJSONArray("data"); 

      //Iterate the jsonArray and print the info of JSONObjects 
      for(int i=0; i < Dataarray.length(); i++){ 
       JSONObject jsonObject = Dataarray.getJSONObject(i); 
JSONObject Data = jsonObject.getJSONObject("restaurentAddress"); 

       for(int j = 0 ; j < Data.length(); j++){ 
        JSONObject GetData =Data.getJSONObject(String.valueOf(j)); 
       int id = Integer.parseInt(GetData.getString("restaurent_address_id")); 
       String postcode = GetData.getString("postcode"); 
       String addresss = GetData.getString("restaurent_address"); 


       dataoutput += " : \n id= "+ id +" \n postcode= "+ postcode +" \n address= "+ addresss +" \n "; 
      }} 
      output.setText(dataoutput); 
     } catch (JSONException e) {e.printStackTrace();} 
    } 
} 

Answer 1

はこれを試してみてください：私はこれを試してみまし完了

try { 
    JSONObject object = (JSONObject) new JSONTokener(YOUR_JSON_STRING).nextValue(); 
    String restaurentAddressId = object.getJSONArray("data").getJSONObject(0).getJSONObject("restaurentAddress").getString("restaurent_address_id"); 
    String restaurentInfoId = object.getJSONArray("data").getJSONObject(1).getJSONObject("restaurentInfo").getString("restaurent_info_id"); 
    String restaurentBizOwnerName = object.getJSONArray("data").getJSONObject(1).getJSONObject("restaurentInfo").getString("restaurent_business_owner_name"); 

} 
catch (JSONException e) { 
} 

Answer 2

その

try { 
     JSONObject jsonRootObject = new JSONObject(strJson); 

     //Get the instance of JSONArray that contains JSONObjects 
     JSONArray mainnode =jsonRootObject.getJSONArray("data"); 

     //Iterate the jsonArray and print the info of JSONObjects 
     for(int i=0; i < mainnode.length(); i++){ 
      JSONObject jsonObject = mainnode.getJSONObject(i); 
      JSONObject Data = jsonObject.getJSONObject("restaurentInfo"); 
       int id = Integer.parseInt(Data.getString("restaurent_info_id")); 
       String postcode = Data.getString("restaurent_phone_number"); 
       String addresss = Data.getString("restaurent_bussiness_owner_name"); 


       dataoutput += " : \n restaurent_id= "+ id +" \n restaurent_info_id= "+ postcode +" \n restaurent_address_id= "+ addresss +" \n "; 

     } 
     output.setText(dataoutput); 
    } catch (JSONException e) {e.printStackTrace();} 
} 

私だけ削除ステータスオブジェクト

と別のループのために協力いただきありがとうございますが、あなたからの少しのヘルプを手に入れた:)