私はPostCSSで書かれたコードを持っています。今私は、PostCSSプラグインを使用せずに「通常の」CSSで同じ効果を達成したいと思います。これは可能ですか?はいの場合、どうですか?PostCSSを「通常の」CSSに変換する
これはばかげた質問のように聞こえるかもしれませんが、私はHTML/CSSへの新たなんだが
コードがCodepenにここにある:https://codepen.io/MightyFool/pen/jLKVqQはここ
HTML:ここ
<p>
"Attractive things make people </a> <a class="link-1" href="#">feel good</a>, which in turn makes them think more</a> <a class="link-1" href="#">Creatively</a>. How does that make something easier to use? Simple, by making it easier for <a class="link-2">people</a> to find solutions to the problems they encounter." <strong>- Don Norman</strong>
</p>\
がありますPostCSS CSS:
@use postcss-simple-vars;
@use postcss-nested;
@import 'https://fonts.googleapis.com/css?family=Open+Sans';
$underlineColor: #00458D;
$underlineHeight: 1px;
* {
box-sizing: border-box;
}
html, body {
font-family: 'Open Sans', sans-serif;
width: 100%;
height: 100%;
display: flex;
align-items: center;
justify-content: center;
}
body {
border: 8px solid $underlineColor;
}
a {
cursor: pointer;
}
strong {
margin-top: 16px;
display: block;
font-weight: 700;
}
p {
padding: 24px;
max-width: 760px;
font-size: 16px;
font-weight: 500;
line-height: 24px;
}
.link-1 {
position: relative;
text-decoration: none;
display: inline-block;
color: #00458D;
padding: 0 1px;
transition: color ease 0.25s;
&::after {
content: '';
position: absolute;
z-index: -1;
width: 100%;
height: $underlineHeight;
left: 0;
bottom: 0;
background-color: $underlineColor;
transition: all ease 0.25s;
}
&:active {
position: relative;
text-decoration: none;
display: inline-block;
background-color: #D42E1C;
}
&:hover {
color: white;
&::after {
height: 100%;
}
}
}