エラーが発生しましたこのシーザー暗号でリストオブジェクトを呼び出すことができません

Question

plaintext =[ 
     "this is a test", 
     "caesar’s wife must be above suspicion", 
     "as shatner would say: you, should, also, be, able, to, handle, punctuation.", 
     "to mimic chris walken: 3, 2, 1, why must you, pause, in strange places?",] 

shift = 3 
def caesar(plaintext): 


    alphabet=["a","b","c","d","e","f","g","h","i","j","k","l", 
    "m","n","o","p","q","r","s","t","u","v","w","x","y","z"] 


    dic={} 
    for i in range(0,len 
         (alphabet)): 
     dic[alphabet[i]]=alphabet[(i+shift)%len(alphabet)] 


    ciphertext="" 
    for l in plaintext(): 
     if l in dic: 
      l=dic[l] 
     ciphertext+=l 

    return ciphertext 



print [caesar(plaintext)] 

なぜ私にエラーが出るのか分かりません。私は援助が必要です。私は括弧を入れて、パラセシスを置き換えようとしましたが、それでもそのエラーが出ています。

Traceback (most recent call last): 
    File "C:/Users/iii/Desktop/y.py", line 33, in <module> 
    print (caesar(plaintext)) 
    File "C:/Users/iii/Desktop/y.py", line 24, in caesar 
    for l in plaintext(): 
TypeError: 'list' object is not callable 

Answer 1

1. まず、print(caesar(plaintext))は、Python 3.xで印刷する方法であります
2. また、それにlen()を呼び出さずにリストを反復することはできません：あなたは、文字列をインクリメントすることはできませんfor l in range(len(plaintext)):
3. ので、私はあなたが本当に変数ciphertextに1を追加したい場合は、その数作るお勧め：ciphertext=0

この変更されたコードは、あなたが望むものであればエラーなしで実行されますが、私はそれが本当であるかどうかは分かりません。

plaintext =[ 
     "this is a test", 
     "caesar’s wife must be above suspicion", 
     "as shatner would say: you, should, also, be, able, to, handle, punctuation.", 
     "to mimic chris walken: 3, 2, 1, why must you, pause, in strange places?",] 

shift = 3 
def caesar(plaintext): 
    alphabet=["a","b","c","d","e","f","g","h","i","j","k","l", 
    "m","n","o","p","q","r","s","t","u","v","w","x","y","z"] 

    dic={} 
    for i in range(0,len(alphabet)): 
     dic[alphabet[i]]=alphabet[(i+shift)%len(alphabet)] 

    ciphertext=0 
    for l in range(len(plaintext)): 
     if l in dic: 
      l=dic[l] 
     ciphertext+=l 

    return ciphertext 

print(caesar(plaintext)) 

EDIT

あなたはシーザー暗号を作りたい場合は、this web siteはPythonでそれを作る方法を説明するの偉大な仕事をしていません。