sql join counts

Question

私は2つの異なるカウントを返すこのステートメントを持っており、私はその月についてこれらのカウントに参加しようとしています。以下は現在の私の声明です。問題は2番目のテーブルのSTRAFTとしてCOUNT（SecondColl。*）です。このようなことをすることはできますか？

WITH cte as(
    SELECT * FROM K1 
    UNION ALL 
    SELECT * FROM K2 
    UNION ALL 
    SELECT * FROM K3 
    UNION ALL 
    SELECT * FROM K4 
), FirstColl as (SELECT * FROM (Select DP, RN, ET, ED, DT, COUNT(*)OVER(PARTITION BY DP, RN) AS your_count 
      from cte) a WHERE your_count = 1 and ET = 'Complete' and DT = 'STR' 
), SecondColl as (SELECT * FROM (Select DP, RN, ET, ED, DT, COUNT(*)OVER(PARTITION BY DP, RN) AS your_count 
      from cte) a WHERE your_count = 1 and ET = 'Complete' and DT = 'NCD' 
) 
SELECT MONTH(ED) as STRMnth, COUNT(*) as STRRFT , COUNT(SecondColl.*) as STRAFT 
FROM FirstColl 
inner join SecondColl where MONTH(ED) = SecondColl.MONTH(ED) 
group by MONTH(ED) 
order by STRMnth asc 

Answer 1

これを試してみてください：

WITH cte as(
    SELECT * FROM K1 
    UNION ALL 
    SELECT * FROM K2 
    UNION ALL 
    SELECT * FROM K3 
    UNION ALL 
    SELECT * FROM K4 
), FirstColl as (SELECT * FROM (Select DP, RN, ET, ED, DT, COUNT(*)OVER(PARTITION BY DP, RN) AS your_count 
      from cte) a WHERE your_count = 1 and ET = 'Complete' and DT = 'STR' 
), SecondColl as (SELECT * FROM (Select DP, RN, ET, ED, DT, COUNT(*)OVER(PARTITION BY DP, RN) AS your_count 
      from cte) a WHERE your_count = 1 and ET = 'Complete' and DT = 'NCD' 
) 
select 
    a.STRMnth, a.cnt1 as STRRFT, b.cnt2 as STRAFT 
from 
    (select month(ED) as STRMnth, count(*) as cnt1 from FirstColl group by month(ED)) a 
    left join 
    (select month(ED) as STRMnth, count(*) as cnt2 from SecondColl group by month(ED)) b 
     on a.STRMnth = b.STRMnth 
order by a.STRMnth asc 

UPDATE1：

WITH cte as(
     SELECT * FROM K1 
     UNION ALL 
     SELECT * FROM K2 
     UNION ALL 
     SELECT * FROM K3 
     UNION ALL 
     SELECT * FROM K4 
    ), FirstColl as (SELECT * FROM (Select DP, RN, ET, ED, DT, COUNT(*)OVER(PARTITION BY DP, RN) AS your_count 
       from cte) a WHERE your_count = 1 and ET = 'Complete' and DT = 'STR' 
    ), SecondColl as (SELECT * FROM (Select DP, RN, ET, ED, DT, COUNT(*)OVER(PARTITION BY DP, RN) AS your_count 
       from cte) a WHERE your_count = 1 and ET = 'Complete' and DT = 'NCD' 
    ), ThirdColl as (SELECT Distinct ED, DP, RN FROM cte WHERE DT = 'STR') 
    select 
     a.STRMnth, a.cnt1 as STRRFT, b.cnt2 as STRAFT 
    from 
     (select month(ED) as STRMnth, count(*) as cnt1 from FirstColl group by month(ED)) a 
     left join 
     (select month(ED) as STRMnth, count(*) as cnt2 from SecondColl group by month(ED)) b 
      on a.STRMnth = b.STRMnth 
     left join 
     (select month(ED) as STRMnth, count(*) as cnt3 from ThirdColl group by month(ED)) c 
      on a.STRMnth = c.STRMnth 
    order by a.STRMnth asc 

アップデート2：

WITH cte as(
     SELECT * FROM K1 
     UNION ALL 
     SELECT * FROM K2 
     UNION ALL 
     SELECT * FROM K3 
     UNION ALL 
     SELECT * FROM K4 
    ), FirstColl as (SELECT * FROM (Select DP, RN, ET, ED, DT, COUNT(*)OVER(PARTITION BY DP, RN) AS your_count 
       from cte) a WHERE your_count = 1 and ET = 'Complete' and DT = 'STR' 
    ), SecondColl as (SELECT * FROM (Select DP, RN, ET, ED, DT, COUNT(*)OVER(PARTITION BY DP, RN) AS your_count 
       from cte) a WHERE your_count = 1 and ET = 'Complete' and DT = 'NCD' 
    ), ThirdColl as (SELECT distinct ED, DP, RN FROM K1 WHERE Defect_Type = 'STR') 
    select 
     a.STRMnth, a.cnt1 as STRRFT, b.cnt2 as STRAFT 
    from 
     (select month(ED) as STRMnth, count(*) as cnt1 from FirstColl group by month(ED)) a 
     left join 
     (select month(ED) as STRMnth, count(*) as cnt2 from SecondColl group by month(ED)) b 
      on a.STRMnth = b.STRMnth 
     left join 
     (select month(ED) as STRMnth, count(*) as cnt3 from ThirdColl group by month(ED)) c 
      on a.STRMnth = c.STRMnth 
    order by a.STRMnth asc