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私はTicTacToeプログラムをやっていますが、唯一の欠けている部分は、ゲームを終了するか、再生するかをユーザーが選択できるようにすることです。私はゲームに "戻る"方法を見つけることができません。ゲームに戻るには？ゲームを終了した後
import java.io.*;
public class Expierment
{
static char c1 [] = new char[10];
static char c2 [] = new char[10];
static char c3 [] = new char[10];
static char p1;
static char p2;
static boolean gameOver = false;
public static void main(String args[])
{
int counter = 0;
int p1Wins = 0;
int p2Wins = 0;
int r1 = 0;
int r2 = 0;
int r3 = 0;
int r4 = 0;
int r5 = 0;
int r6 = 0;
int r7 = 0;
int r8 = 0;
int r9 = 0;
int pick1 = 0;
int pick2 = 0;
int pick3 = 0;
int pick4 = 0;
int pick5 = 0;
int pick6 = 0;
int pick7 = 0;
int pick8 = 0;
int pick9 = 0;
char turn = 'X';
int choice = menu();
switch(choice)
{
case 1:
System.out.println("The game is called 'Tic-Tac-Toe', you should have known it. If you don't, search it.") ;
case 2:
gameOver = false;
break;
case 3:
System.out.println("\nSee you next time !!");
return;
default:
System.out.println("\nYou hit the wrong key......\n");
return;
}//end of switch
System.out.println("\nPlayer 1 initials ?");
String n1 = GCS();
p1 = n1.charAt(0);
System.out.println("\nPlayer 2 initials ?");
String n2 = GCS();
p2 = n2.charAt(0);
c1[2]='1';
c2[2]='2';
c3[2]='3';
c1[1]='4';
c2[1]='5';
c3[1]='6';
c1[0]='7';
c2[0]='8';
c3[0]='9';
printBoard();
while(gameOver!=true)
{
System.out.println("Which spot ?");
int pick = Integer. parseInt(GCS());
switch (pick)
{
case 1:
if (r1<1)
{
c1[2] = turn;
r1++;
}
else
{
System.out.println("That column is full, pick another.\n");
continue;
}
break;
case 2:
if (r2<1)
{
c2[2] = turn;
r2++;
}
else
{
System.out.println("That column is full, pick another.\n");
continue;
}
break;
case 3:
if (r3<1)
{
c3[2] = turn;
r3++;
}
else
{
System.out.println("That column is full, pick another.\n");
continue;
}
break;
case 4:
if (r4<1)
{
c1[1] = turn;
r4++;
}
else
{
System.out.println("That column is full, pick another.\n");
continue;
}
break;
case 5:
if (r5<1)
{
c2[1] = turn;
r5++;
}
else
{
System.out.println("That column is full, pick another.\n");
continue;
}
break;
case 6:
if (r6<1)
{
c3[1] = turn;
r6++;
}
else
{
System.out.println("That column is full, pick another.\n");
continue;
}
break;
case 7:
if (r7<1)
{
c1[0] = turn;
r7++;
}
else
{
System.out.println("That column is full, pick another.\n");
continue;
}
break;
case 8:
if (r8<1)
{
c2[0] = turn;
r8++;
}
else
{
System.out.println("That column is full, pick another.\n");
continue;
}
break;
case 9:
if (r9<1)
{
c3[0] = turn;
r9++;
}
else
{
System.out.println("That column is full, pick another.\n");
continue;
}
break;
default:
System.out.println("Seriously?! Pick a possible spot.\n");
continue;
}//end of switch
if (turn=='X') turn = 'O';
else turn = 'X';
printBoard();
if (checkWinner())
{
while(gameOver==true)
{
int Echoice = EGM();
switch(Echoice)
{
case 1:
System.out.println("The game is called 'Tic-Tac-Toe', you should have known it. If you don't, search it.") ;
case 2:
gameOver = false;
menu();
break;
case 3:
System.out.println("\nSee you next time !!");
return;
default:
System.out.println("\nYou hit the wrong key......\n");
return;
}//end of switch
}//end of while true
return;
}
counter ++;
if (counter==9)
{
System.out.println("\n\nYou tied.\n");
return;
}
}//end of while not true
}//end of main
public static boolean checkWinner()
{
for (int k=0; k<2; k++)
{
if ((c1[k]!=' ')&&(c1[k]==c2[k])&&(c1[k]==c3[k]))
{
System.out.println("\nYo " + c1[k] + " is the winner!\n");
gameOver=true;
return true;
}//checks column 1-3 horizontally
}//end of horizontal check
for (int m=0; m<2; m++)
{
if((c1[m]!=' ')&&(c1[m]==c1[m+1])&&(c1[m+1]==c1[m+2])&&(c1[m]==c1[m+2]))
{
System.out.println("\nYo " + c1[m] + " is the winner!\n");
gameOver=true;
return true;
}//checks column 1 vertically
if((c2[m]!=' ')&&(c2[m]==c2[m+1])&&(c2[m+1]==c2[m+2])&&(c2[m]==c2[m+2]))
{
System.out.println("\nYo " + c2[m] + " is the winner!\n");
gameOver=true;
return true;
}//checks column 2 vertically
if((c3[m]!=' ')&&(c3[m]==c3[m+1])&&(c3[m+1]==c3[m+2])&&(c3[m]==c1[m+2]))
{
System.out.println("\nYo " + c3[m] + " is the winner!\n");
gameOver=true;
return true;
}//checks column 3 vertically
if ((c1[m]!=' ')&&(c1[m]==c2[m+1])&&(c1[m]==c3[m+2]))
{
System.out.println("\nYo " + c1[m] + " is the winner!\n");
gameOver=true;
return true;
}//checks upward diagonal
if ((c3[m]!=' ')&&(c3[m]==c2[m+1])&&(c3[m]==c1[m+2]))
{
System.out.println("\nYo " + c1[m] + " is the winner!\n");
gameOver=true;
return true;
}
}//end of vertical check
return false;
}//end of checkWinner
public static void printBoard()
{
System.out.println("_______");
for (int j = 2; j > -1; j--)
{
System.out.println("|" + c1[j] + "|" + c2[j] + "|" + c3[j] + "|");
System.out.println("-------");
}
}//end of printBoard
public static int menu()
{
System.out.println("Tic-Tac-Toe ~ Main Menu\n\n1. Instructions\n2. Play a 1 player game"+"\n3. Exit\n");
int selection = Integer.parseInt(GCS());
return selection;
}//end of menu
public static int EGM()
{
System.out.println("Tic-Tac-Toe ~ End of Game Menu\n\n1. Instructions\n2. Play again"+"\n3. Exit\n");
int Eselection = Integer.parseInt(GCS());
return Eselection;
}
public static String GCS()
{
int noMoreInput=-1;
char enterKeyHit='\n';
int InputChar;
StringBuffer InputBuffer = new StringBuffer(100);
try
{
InputChar=System.in.read();
while(InputChar != noMoreInput)
{
if((char)InputChar !=enterKeyHit)
{
InputBuffer.append((char)InputChar);
}
else
{
InputBuffer.setLength(InputBuffer.length()-1);
break;
}
InputChar=System.in.read();
}
}
catch (IOException IOX)
{
System.err.println(IOX);
}
return InputBuffer.toString();
}//end of GCS
}//end of public class
あなたの質問とは無関係に、このコードを書き換えて、 'pick1'、' pick2'、...、 'pick9'変数の必要性を排除することをお勧めします。これと同じような変数のコレクションを書くことが決まれば、 'int [] pick = new int [9]'のように配列を使ってほとんどいつでも書き換えることができます。これにより、すべての値に 'pick [0]'、...、 'pick [8]'としてアクセスすることができますが、もっと重要なのは、プログラムでインデックスを生成できることです。これは、あなたが時間をとって喜んでいるならば、 'switch'ステートメントをわずか数行のコードに圧縮することができます。 – templatetypedef
フォーマットを修正してください –
いくつかのヒントr1-r9、pick1-pick9は代わりに配列を使用し、csと同じものを文字列の配列に変更し、c [0] = "741"のように初期化します。 – hhafez