2012-02-21 14 views

答えて

6

が、これがDecimalFormatはからで、あなたはのNumberFormatのドキュメントを読んでいる: 参照してください:http://docs.oracle.com/javase/1.4.2/docs/api/java/text/DecimalFormat.html

Scientific Notation

Numbers in scientific notation are expressed as the product of a mantissa and a power of ten, for example, 1234 can be expressed as 1.234 x 10^3. The mantissa is often in the range 1.0 <= x < 10.0, but it need not be. DecimalFormat can be instructed to format and parse scientific notation only via a pattern; there is currently no factory method that creates a scientific notation format. In a pattern, the exponent character immediately followed by one or more digit characters indicates scientific notation. Example: "0.###E0" formats the number 1234 as "1.234E3".

  • The number of digit characters after the exponent character gives the minimum exponent digit count. There is no maximum. Negative exponents are formatted using the localized minus sign, not the prefix and suffix from the pattern. This allows patterns such as "0.###E0 m/s".

  • The minimum and maximum number of integer digits are interpreted together:

    • If the maximum number of integer digits is greater than their minimum number and greater than 1, it forces the exponent to be a multiple of the maximum number of integer digits, and the minimum number of integer digits to be interpreted as 1. The most common use of this is to generate engineering notation, in which the exponent is a multiple of three, e.g., "##0.#####E0". Using this pattern, the number 12345 formats to "12.345E3", and 123456 formats to "123.456E3".

    • Otherwise, the minimum number of integer digits is achieved by adjusting the exponent. Example: 0.0formatted with "00.###E0" yields "12.3E-4".

  • The number of significant digits in the mantissa is the sum of the minimum integer and maximum fraction digits, and is unaffected by the maximum integer digits. For example, 12345 formatted with "##0.##E0" is "12.3E3". To show all digits, set the significant digits count to zero. The number of significant digits does not affect parsing.

  • Exponential patterns may not contain grouping separators.

+0

私はこれを試しました: 'BigDecimal d = new BigDecimal(" 55 "); DecimalFormat df =新しいDecimalFormat( "0。### E0"); System.out.println(df.format(d.toString())); '、しかし、私にエラーが表示されます:"指定されたオブジェクトを数値としてフォーマットできません " –

+0

これで動作します。 'と' d'。ありがとう:) –

0

このようなものをお探しですか?

YY^XX(モッズQQ)

int fastMod(int YY, int XX, int QQ){ 
    int ZZ;            //declare variables 
    int RR = 1; 

    while (XX != 0){         //while XX != 0 
     ZZ = XX % 2;         //mod XX by 2 
     XX= XX/2;          //divide XX by 2 
     if (ZZ == 1)         //if ZZ is one 
     RR = (RR * YY) % QQ;       //mod (RR*YY) by QQ 
     YY= (YY * YY) % QQ;        //mod (YY*YY) by QQ  
    } 
    return RR;           //return int 
} 

あなたはGIANTの数字を使用して起動すると、あなたがモジュラー算術演算を使用する必要があります。 これは、RSAアルゴリズムのように大きな素数を生成する場合に特に便利になります。ここでカバーモジュラー算術の 基礎: http://www.brainjammer.com/math/modular-arithmetic/

+0

私はそれを取得しません。これはBigDecimalを指数関数形式に変換する際にどのように役立ちますか? –

+0

重要なのは、モジュラ算術を使用しない限り、大きな数字では扱えないことです。 –

2

は、このヘルプあなたをしていますか?

BigDecimal bd = new BigDecimal(3.134e67); 
String.valueOf(bd.doubleValue()) 
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