参照

Question

SELECT Temp.rating, Temp.avgage 
FROM (SELECT S.rating, AVG (S.age) AS avgage 
FROM Sailors S 
GROUP BY S.rating) AS Temp 
WHERE Temp.avgage = (SELECT MIN (Temp.avgage) 
FROM Temp) 

このようなSQLクエリを考えてみMySQLのモニタは、このエラーを与える：

ERROR 1146 (42S02): Table 'testDB.Temp' doesn't exist

が、私はこのエラーを回避するために何をすべき？あなたはネクタイを処理する方法に応じて

Answer 1

SELECT Temp.rating, Temp.avgage 
FROM 
    (SELECT S.rating, AVG(S.age) AS avgage 
    FROM Sailors S 
    GROUP BY S.rating 
) AS Temp 
WHERE Temp.avgage = 
     (SELECT MIN (Temp.avgage) 
     FROM Temp    --- the error is here 
    ) 

---

、あなただけ使用できます。

SELECT Temp.rating, Temp.avgage 
FROM 
    (SELECT S.rating, AVG(S.age) AS avgage 
    FROM Sailors S 
    GROUP BY S.rating 
) AS Temp 
ORDER BY Temp.avgage 
LIMIT 1 

または単純同等：

SELECT S.rating, AVG(S.age) AS avgage 
FROM Sailors S 
GROUP BY S.rating 
ORDER BY avgage 
LIMIT 1 

---

またはこのいずれか（すべての結び付いた結果が表示されます）：

SELECT Temp.rating, Temp.avgage 
FROM 
    (SELECT S.rating, AVG(S.age) AS avgage 
    FROM Sailors S 
    GROUP BY S.rating 
) AS Temp 
WHERE Temp.avgage = 
     (SELECT AVG(S.age) AS avgage 
     FROM Sailors S 
     GROUP BY S.rating 
     ORDER BY avgage 
     LIMIT 1    
    )