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私が選択する場所field.table =」+ fooの使用しています;。クエリ、およびデータを全く返さないを理由として混乱ここまで呼び出されdatareaderはパラメータで空に戻りますか?
public Submission GetSubmissionsByID(string x)
{
string viewQuery = "SELECT Submission.SubmissionId, Submission.CustId, Submission.BroId, Submission.Coverage, Submission.CurrentCoverage, Submission.PrimEx, Submission.Retention, Submission.EffectiveDate, Submission.Commission, Submission.Premium, Submission.Comments FROM Submission WHERE Submission.SubmissionId =" + x;
string connectionString = System.Configuration.ConfigurationManager.ConnectionStrings["MyConnectionString"].ConnectionString;
using (SqlConnection conn = new SqlConnection(connectionString))
{
conn.Open();
SqlCommand viewCmd = new SqlCommand(viewQuery, conn);
SqlDataReader dr = null;
dr = viewCmd.ExecuteReader();
Submission tempSubmission = new Submission();
tempSubmission.SubmissionId1 = dr.GetInt32(0);
tempSubmission.CustomerId1 = dr.GetInt32(1);
tempSubmission.BrokerId1 = dr.GetInt32(2);
tempSubmission.Coverage1 = dr.GetInt32(3);
tempSubmission.CurrentCoverage1 = dr.GetInt32(4);
tempSubmission.PrimEx1 = dr.GetInt32(5);
tempSubmission.Retention1 = dr.GetInt32(6);
tempSubmission.EffectiveDate1 = dr.GetDateTime(7);
tempSubmission.Commission1 = dr.GetInt32(8);
tempSubmission.Premium1 = dr.GetInt32(9);
tempSubmission.Comment1 = dr.GetString(10);
return tempSubmission;
}
}
を、照会値Xが有効である場合、上のデータと。その行はまた、一定/有効な値にXを設定して失敗した。
string x = Request.QueryString["SubmissionId"];
SubmissionService ss = new SubmissionService();
Submission sub = ss.getSubmissionByID(x);
viewQueryはどのようなものに見えるん連結後? – gbn