2つのそれぞれのドロップダウンから選択された月と日を入力してください

Question

を押すと選択した月と日の日を表示する必要がありますボタンを押します。

onchange()私はREQUESTとGETをURLから入手しようとしましたが、間違ったことをしています。 1 /方法+「形式」2 /割り当てる$のVARSにおけるアクション：私はあなたのコード内のいくつかのことが欠けている現在のコードが静的であることを知っていて、2003年

<table> 
<tr> 
    <form id="frmA" class="form-inline" role="form" > 
     <td align="right"> 
      <select id="month" name="month" class="form-control" required="required"> 
       <option value="">Select Month...</option> 
       <option value='1'>January</option> 
       <option value='2'>February</option> 
       <option value='3'>March</option> 
       <option value='4'>April</option> 
       <option value='5'>May</option> 
       <option value='6'>June</option> 
       <option value='7'>July</option> 
       <option value='8'>August</option> 
       <option value='9'>September</option> 
       <option value='10'>October</option> 
       <option value='11'>November</option> 
       <option value='12'>December</option> 
      </select> 
     </td> 
     <td> 
      <select id="year" name="year" class="form-control" required="required"> 
      <?php 
       foreach (range(date('Y'), $earliest_year) as $x) { 
       print '<option value="'.$x.'"'.($x === $already_selected_value ? ' 
       selected="selected"' : '').'>'.$x.'</option>';} 
       ?> 
      </select> 
     </td> 
     <td> 
      <input type="submit" value="Go!" /> 
     </td> 
    </form> 
</tr> 
<table> 
    <tbody> 
     <?php 
      $date = '2003-09-01'; 
      $end = '2003-09-' . date('t', strtotime($date)); 
      i=1; 
      while(strtotime($date) <= strtotime($end) && $i <= strtotime($end)) { 
       $day_num = date("d/m/Y", strtotime($date)); 
       $day_name = date('l', strtotime($date)); 
       $date = date("Y-m-d", strtotime("+1 day", strtotime($date))); 
       echo "<tr><td>$day_num - $day_name</td></tr>"; 
       i++; 
      } 
      ?> 
    </tbody> 
</table> 

Answer 1

の唯一の第九の月の値を表示しますそれらをオンラインで使用する前に - > $ date = '2003-09-01';

<table> 
<tbody> 
<?php 

error_reporting(E_ALL); 
ini_set('display_errors', 1); 

$month = $_POST['month']; 
$year = $_POST['year']; 

$date = "$year-$month-01"; 
$end = "$year-$month-" . date('t', strtotime($date)); 

echo"[ $month/$year/$date/$end ]"; 
/* code below will throw an error 
$i=1; 
while((strtotime($date) <= strtotime($end)) && ($i <= strtotime($end))  ) { 
$day_num = date("d/m/Y", strtotime($date)); 
$day_name = date('l', strtotime($date)); 
$date = date("Y-m-d", strtotime("+1 day", strtotime($date))); 
echo "<tr><td>$day_num - $day_name</td></tr>"; 
i++; 
} 
*/ 
?> 
</tbody> 
</table> 

<table> 
<tr> 
<form id="frmA" class="form-inline" role="form" method="post" action="mypage.php" > 
<td align="right"> 

<select id="month" name="month" class="form-control" required="required"> 
        <option value="">Select Month...</option> 
        <option value='1'>January</option> 
        <option value='2'>February</option> 
        <option value='3'>March</option> 
        <option value='4'>April</option> 
        <option value='5'>May</option> 
        <option value='6'>June</option> 
        <option value='7'>July</option> 
        <option value='8'>August</option> 
        <option value='9'>September</option> 
        <option value='10'>October</option> 
        <option value='11'>November</option> 
        <option value='12'>December</option> 
    </select> 
</td> 

<td> 
<select id="year" name="year" class="form-control" required="required"> 
<?php 
foreach (range(date('Y'), $earliest_year) as $x) { 
print '<option value="'.$x.'"'.($x === $already_selected_value ? ' 
selected="selected"' : '').'>'.$x.'</option>';} 
?> 
</select> 
</td> 

<td> 
<input type="submit" value="Go!" /> 
</td> 
</form> 
</tr></tbody> 
</table> 

Answer 2

<table> 
<tbody> 
<?php 

error_reporting(E_ALL); 
ini_set('display_errors', 1); 

$month = $_REQUEST['month']; 
$year = $_REQUEST['year']; 

$date = "$year-$month-01"; 
$end = "$year-$month-" . date('t', strtotime($date)); 

$i=1; 
while((strtotime($date) <= strtotime($end)) && ($i <= strtotime($end)) ) { 
$day_num = date("d/m/Y", strtotime($date)); 
$day_name = date('l', strtotime($date)); 
$date = date("Y-m-d", strtotime("+1 day", strtotime($date))); 
echo "<tr><td>$day_num - $day_name</td></tr>"; 
$i++; 
} 
?> 
</tbody> 
</table> 
<form id="frmA" class="form-inline" role="form" method="post" action="mypage.php" > 
<table> 
<tr> 
<td align="right"> 

<select id="month" name="month" class="form-control" required="required"> 
        <option value="">Select Month...</option> 
        <option value='1'>January</option> 
        <option value='2'>February</option> 
        <option value='3'>March</option> 
        <option value='4'>April</option> 
        <option value='5'>May</option> 
        <option value='6'>June</option> 
        <option value='7'>July</option> 
        <option value='8'>August</option> 
        <option value='9'>September</option> 
        <option value='10'>October</option> 
        <option value='11'>November</option> 
        <option value='12'>December</option> 
</select> 
</td> 

<td> 
<select id="year" name="year" class="form-control" required="required"> 
<?php 
foreach (range(date('Y'), $earliest_year) as $x) { 
print '<option value="'.$x.'"'.($x === $already_selected_value ?'selected="selected"' : '').'>'.$x.'</option>';} 
?> 
</select> 
</td> 

<td> 
<input type="submit" value="Go!" /> 
</td> 

</tr> 
</table> 
</form>