sys argvのPythonエスケープ特殊文字

Question

sys.argvを使用するスクリプトがあり、入力に特殊文字（セミコロン）が含まれている可能性があります。私が持っている

..私は単なる文字列として入力する必要がありますが、セミコロンがアップし、すべてを台無し：

def myscript(text) 
    print text 


a = myscript(sys.argv[1]) 
print a 

私は試してみてください。

>> python script.py "With these words she greeted Prince Vasili Kuragin, a man of high rank and importance, who was the first to arrive at her reception. Anna Pavlovna had had a cough for some days. She was, as she said, suffering" from la grippe; grippe being then a new word in St. Petersburg"" 

私が手：

'With these words she greeted Prince Vasili Kuragin, a man of high rank and importance, who was the first to arrive at her reception. Anna Pavlovna had had a cough for some days. She was, as she said, suffering' 
None 
bash: grippe: command not found 

私はその中に何が入っていても、文字列全体をスクリプトに入れたいだけです。

私が試した：

a = myscript(repr(sys.argv[1])) 
a = myscript(str(sys.argv[1])) 

Answer 1

それは、Pythonの問題ではありません、あなたは、呼び出し元のシェルにそれをエスケープする必要があります。単に引用符を\"とし、セミコロンを\;とするだけです。

$ python testme.py "With these words she greeted Prince Vasili Kuragin, a man of high rank and importance, who was the first to arrive at her reception. Anna Pavlovna had had a cough for some days. She was, as she said, suffering\" from la grippe; grippe being then a new word in St. Petersburg\"" 

With these words she greeted Prince Vasili Kuragin, a man of high rank and importance, who was the first to arrive at her reception. Anna Pavlovna had had a cough for some days. She was, as she said, suffering" from la grippe; grippe being then a new word in St. Petersburg" 

Answer 2

これは、bashの問題だ、Pythonの問題ではありません。 Bashは;（セミコロン）が新しいbashコマンドを分離していると考えています。あなたはそれをエスケープする必要があります。