どのようにSQL Serverで列の賢さと行の合計を合計するには？

Question

私は何を探していますが合計行と列レベルの両方で起こるべき

ある

ある

以下

をご覧ください

私の試み

declare @t table(aggrementid varchar(20), bom_pos int, bucket int null, paymentstatus varchar(50)) 

insert into @t 
    select '1', 3000, null, null 
    union all 
    select '2', 3000, 0, 'Non-Delinquient' 
    union all 
    select '3', 4000, 0, 'Non-Delinquient' 
    union all 
    select '4', 5000, 0, 'Non-Delinquient' 
    union all 
    select '5', 7000, 0, 'NPA' 
    union all 
    select '6', 8000, 1, 'NPA' 

Select 
    bucket, 
    [Non-Delinquient], [NPA], [RollBack], [RollForward], 
    [Stabilized], [Normalized], [PaymentStatusY], 
    Total = iif([Non-Delinquient] is null, 0, [Non-Delinquient]) + 
     iif([NPA] is null, 0, [NPA]) + 
     iif([RollBack] is null, 0, [RollBack]) + 
     iif([RollForward] is null, 0, [RollForward]) + 
     iif([Stabilized] is null, 0, [Stabilized]) + 
     iif([Normalized] is null, 0, [Normalized]) + 
     iif([PaymentStatusY] is null, 0, [PaymentStatusY]) 
From 
    (Select 
     --aggrementid, 
     bom_pos, 
     bucket, paymentstatus  
    From 
     @t) as PivotSource 
PIVOT 
    (sum(bom_pos) FOR paymentstatus IN ([Non-Delinquient], [NPA],[RollBack],[RollForward],[Stabilized],[Normalized],[PaymentStatusY]) 
    ) as Pvt 
Where 
    bucket is not null 

これは、この結果を返します：

私が進めて助けてください。同じ等

Answer 1

をロールアップ機能を使用することによって達成することができればまた、私はあなたがGROUPING SETS

declare @t table(aggrementid varchar(20), bom_pos int, bucket int null, paymentstatus varchar(50)) 

insert into @t 
    select '1', 3000, null, null 
    union all 
    select '2', 3000, 0, 'Non-Delinquient' 
    union all 
    select '3', 4000, 0, 'Non-Delinquient' 
    union all 
    select '4', 5000, 0, 'Non-Delinquient' 
    union all 
    select '5', 7000, 0, 'NPA' 
    union all 
    select '6', 8000, 1, 'NPA' 

Select 
    isnull(CAST(bucket AS varchar(10)),'Total') bucket, 
    SUM([Non-Delinquient]) [Non-Delinquient], 
    SUM([NPA]) [NPA], 
    SUM([RollBack]) [RollBack], 
    SUM([RollForward]) [RollForward], 
    SUM([Stabilized]) [Stabilized], 
    SUM([Normalized]) [Normalized], 
    SUM([PaymentStatusY]) [PaymentStatusY], 
    SUM(isnull([Non-Delinquient],0) + isnull([NPA],0) + isnull([RollBack],0) + isnull([RollForward],0) + isnull([Stabilized],0) + isnull([Normalized],0) + isnull([PaymentStatusY],0)) Total 
From 
    (Select 
     --aggrementid, 
     bom_pos, 
     bucket, paymentstatus  
    From 
     @t) as PivotSource 
PIVOT 
    (sum(bom_pos) FOR paymentstatus IN ([Non-Delinquient], [NPA],[RollBack],[RollForward],[Stabilized],[Normalized],[PaymentStatusY]) 
    ) as Pvt 
Where 
    bucket is not null 
GROUP BY GROUPING SETS(
         (bucket), 
         () 
        ) 

でGROUP BYを使用することができると思うも、それは

SELECT 
    CASE GROUPING_ID(GroupID,SubgroupID) 
    WHEN 3 THEN 'Total' 
    WHEN 1 THEN 'Subtotal by Group' 
    WHEN 0 THEN '' 
    END RowTitle, 

    GroupID, 
    SubgroupID, 
    SUM(Value) Value 
FROM 
    (
    SELECT 1 GroupID,1 SubgroupID,10 Value 
    UNION ALL SELECT 1 GroupID,2 SubgroupID,5 Value 
    UNION ALL SELECT 1 GroupID,3 SubgroupID,5 Value 
    UNION ALL SELECT 2 GroupID,1 SubgroupID,11 Value 
    UNION ALL SELECT 2 GroupID,2 SubgroupID,12 Value 
) q 
GROUP BY GROUPING SETS(
      (GroupID,SubgroupID), 
      (GroupID), 
      () 
     ) 

をどのように機能するかを理解するため、次の例を参照してください。

SUMとCASEを代わりに使用することもできます。PIVOT。私にとってそれはもっとはっきりしています。

SELECT 
    bucket, 
    SUM(CASE WHEN paymentstatus='Non-Delinquient' THEN bom_pos END) [Non-Delinquient], 
    SUM(CASE WHEN paymentstatus='NPA' THEN bom_pos END) [NPA], 
    SUM(CASE WHEN paymentstatus='RollBack' THEN bom_pos END) [RollBack], 
    SUM(CASE WHEN paymentstatus='RollForward' THEN bom_pos END) [RollForward], 
    SUM(CASE WHEN paymentstatus='Stabilized' THEN bom_pos END) [Stabilized], 
    SUM(CASE WHEN paymentstatus='Normalized' THEN bom_pos END) [Normalized], 
    SUM(CASE WHEN paymentstatus='PaymentStatusY' THEN bom_pos END) [PaymentStatusY], 
    SUM(bom_pos) Total 
FROM @t 
WHERE paymentstatus IN('Non-Delinquient', 'NPA','RollBack','RollForward','Stabilized','Normalized','PaymentStatusY') 
GROUP BY GROUPING SETS(
         (bucket), 
         () 
        ) 

Answer 2

declare @t table(aggrementid varchar(20), bom_pos int, bucket nvarchar(max) null, paymentstatus varchar(50)) 

insert into @t 
    select '1', 3000, null, null 
    union all 
    select '2', 3000, 0, 'Non-Delinquient' 
    union all 
    select '3', 4000, 0, 'Non-Delinquient' 
    union all 
    select '4', 5000, 0, 'Non-Delinquient' 
    union all 
    select '5', 7000, 0, 'NPA' 
    union all 
    select '6', 8000, 1, 'NPA' 



Select 
    bucket, 
    [Non-Delinquient], [NPA], [RollBack], [RollForward], 
    [Stabilized], [Normalized], [PaymentStatusY], 
    Total = isnull([Non-Delinquient],0) + 
      isnull([NPA],0) + 
      isnull([RollBack],0) + 
      isnull([RollForward],0) + 
      isnull([Stabilized],0) + 
      isnull([Normalized],0) + 
      isnull([PaymentStatusY],0) 
From 
    (Select 
     --aggrementid, 
     bom_pos, 
     bucket, paymentstatus  
    From 
     @t) as PivotSource 
PIVOT 
    (sum(bom_pos) FOR paymentstatus IN ([Non-Delinquient], [NPA],[RollBack],[RollForward],[Stabilized],[Normalized],[PaymentStatusY]) 
    ) as Pvt 
Where 
    bucket is not null 

    union all 

    Select 
    'Total', 
    sum([Non-Delinquient]), sum([NPA]), sum([RollBack]), sum([RollForward]), 
    sum([Stabilized]), sum([Normalized]), sum([PaymentStatusY]), 
    Total = (isnull(sum([Non-Delinquient]),0) + 
      isnull(sum([NPA]),0) + 
      isnull(sum([RollBack]),0) + 
      isnull(sum([RollForward]),0) + 
      isnull(sum([Stabilized]),0) + 
      isnull(sum([Normalized]),0) + 
      isnull(sum([PaymentStatusY]),0)) 
From 
    (Select 
     --aggrementid, 
     bom_pos, 
     bucket, paymentstatus  
    From 
     @t) as PivotSource 
PIVOT 
    (sum(bom_pos) FOR paymentstatus IN ([Non-Delinquient], [NPA],[RollBack],[RollForward],[Stabilized],[Normalized],[PaymentStatusY]) 
    ) as Pvt 
Where 
    bucket is not null