2017-05-30 9 views
-4

グループは動作していません。私は選択オプションで数式を使用している可能性があります。あなたも それを使用する必要がありますGROUP BY句で、私はnamesをsuposeようにするには、エイリアスを使用しているグループはLaravelで働いていません。5.2

select FLOOR(SUM(DATEDIFF(rd.checkin_date,rd.created_at))/COUNT(DATEDIFF(rd.checkin_date,rd.created_at))) AS names, 
COUNT(rd.id) as totbooking, 
SUM(DATEDIFF(rd.checkout_date,rd.checkin_date)) AS nights, 
round(SUM(CASE WHEN h.currency_id=151 THEN rd.total_cents WHEN h.currency_id!=151 THEN rd.total_cents/cur.exchange_rate ELSE 0 END)/100) AS revenue, 
round((round(SUM(CASE WHEN h.currency_id=151 THEN rd.total_cents WHEN h.currency_id!=151 THEN rd.total_cents/cur.exchange_rate ELSE 0 END)/100))/(SUM(DATEDIFF(rd.checkout_date,rd.checkin_date)))) as adr, FLOOR((FLOOR(SUM(CASE WHEN h.currency_id=151 THEN rd.total_cents WHEN h.currency_id!=151 THEN rd.total_cents/cur.exchange_rate ELSE 0 END)/100))/COUNT(rd.id)) as atp, FLOOR(SUM(DATEDIFF(rd.checkin_date,rd.created_at))/COUNT(DATEDIFF(rd.checkin_date,rd.created_at))) as leadtime, 
SUM(DATEDIFF(rd.checkout_date,rd.checkin_date))/(COUNT(rd.id)) as alos, (SUM(DATEDIFF(rd.checkout_date,rd.checkin_date))/(h.total_rooms * 31))*100 as share from `reservation_details` as `rd` 
left join `hotels` as `h` on `rd`.`hotel_id` = `h`.`id` 
left join `currencies` as `cur` on `cur`.`id` = `h`.`currency_id` 
left join `chains` as `c` on `c`.`id` = `h`.`chain_id` 
where `rd`.`status` >= 50 and date(rd.created_at) >= "2017-04-30" and date(rd.created_at) <= "2017-05-30" GROUP BY names 
+1

あなたのフォーマットは?読むことができません – nacho

+1

エラーは表示されません。それから私はそれを働かせています。 – Chay22

+0

@nacho今すぐチェックしてください –

答えて

0

を行う必要がありhotelsに属し方法?あなたが私たちにいくつかのデータを見せてもらうと助けになるでしょう

select names,sum(totbooking),sum(nights),sum(revenue),sum(adr),leadtime,sum(alos),sum(share) 
from (
    select FLOOR(SUM(DATEDIFF(rd.checkin_date,rd.created_at))/COUNT(DATEDIFF(rd.checkin_date,rd.created_at))) AS names, COUNT(rd.id) as totbooking, 
    SUM(DATEDIFF(rd.checkout_date,rd.checkin_date)) AS nights,round(SUM(CASE WHEN h.currency_id=151 THEN rd.total_cents WHEN h.currency_id!=151 THEN rd.total_cents/cur.exchange_rate ELSE 0 END)/100) AS revenue, 
    round((round(SUM(CASE WHEN h.currency_id=151 THEN rd.total_cents WHEN h.currency_id!=151 THEN rd.total_cents/cur.exchange_rate ELSE 0 END)/100))/(SUM(DATEDIFF(rd.checkout_date,rd.checkin_date)))) as adr, FLOOR((FLOOR(SUM(CASE WHEN h.currency_id=151 THEN rd.total_cents WHEN h.currency_id!=151 THEN rd.total_cents/cur.exchange_rate ELSE 0 END)/100))/COUNT(rd.id)) as atp, FLOOR(SUM(DATEDIFF(rd.checkin_date,rd.created_at))/COUNT(DATEDIFF(rd.checkin_date,rd.created_at))) as leadtime, 
    SUM(DATEDIFF(rd.checkout_date,rd.checkin_date))/(COUNT(rd.id)) as alos, (SUM(DATEDIFF(rd.checkout_date,rd.checkin_date))/(h.total_rooms * 31))*100 as share 
    from `reservation_details` as `rd` 
    left join `hotels` as `h` on `rd`.`hotel_id` = `h`.`id` 
    left join `currencies` as `cur` on `cur`.`id` = `h`.`currency_id` 
    left join `chains` as `c` on `c`.`id` = `h`.`chain_id` 
    where `rd`.`status` >= 50 and date(rd.created_at) >= "2017-04-30" and date(rd.created_at) <= "2017-05-30") 
group by names 
+0

を使用して1行を返しますが、リストが必要です@nacho –

+0

@Rakesh Tripathiデータがあるテーブルをアップロードして必要なものを見ると、 – nacho

0

はそうあなたはドンは、あなたがこのことをしてみてくださいなぜそれをこのよう

GROUP BY h.names 
+0

彼の「名前」は「フロア(SUM(DATEDIFF(rd.checkin_date、rd.created_at))/ COUNT(DATEDIFF(rd.checkin_date、rd.created_at)))」という名前を意味します)AS名 ' –

+0

申し訳ありません、それを見ませんでした – nacho

+0

正しい@HoàngĐăng –

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