私はレコードの数を選択するには、次のクエリを書いている:私は今何したいのですがどのようなこれを一括更新するにはどうすればよいですか?
select
b.building_name ,
lp.lease_id ,
lp.suite_id ,
lp.suite_name ,
lp.tenant_trading_name ,
sco.scca_uplift as 'Current GST Uplift Jan 2011' ,
nu.new_uplift as 'GST Uplift Jan 2011 Post-Change' ,
lp.scca_broad_category_code ,
lp.scca_sales_group_code ,
lp.scca_fine_categories_code ,
lp.scca_notes_code
, '(lease_id = ''' + lp.lease_id + ''' and suite_id ='''
+ lp.suite_id + ''') or' as 'Base SQL Output'
from
property.lease_period lp
inner join property.property b
on b.building_id = lp.building_id
inner join
(
select scca_uplift ,
scca_broad_category_code ,
scca_fine_categories_code ,
scca_sales_group_code
from property.lease_period
where period_id = 252
) sco
on sco.scca_broad_category_code = lp.scca_broad_category_code
and sco.scca_sales_group_code = lp.scca_sales_group_code
and sco.scca_fine_categories_code = lp.scca_fine_categories_code
inner join
(
-- Department Store
select '10' as scca_broad_category_code,
'100' as scca_sales_group_code,
'1000' as scca_fine_categories_code,
109.8 as new_uplift
-- Discount Department Stores
union all
select '10' as scca_broad_category_code,
'110' as scca_sales_group_code,
'1100' as scca_fine_categories_code,
109.5 as new_uplift
-- Supermarket
union all
select '10' as scca_broad_category_code,
'130' as scca_sales_group_code,
'1300' as scca_fine_categories_code,
105.0 as new_uplift
-- Newsagents and Stationary
union all
select '30' as scca_broad_category_code,
'340' as scca_sales_group_code,
'3403' as scca_fine_categories_code,
110.0 as new_uplift
-- Discount Variety
union all
select '30' as scca_broad_category_code,
'350' as scca_sales_group_code,
'3502' as scca_fine_categories_code,
109.5 as new_uplift
-- Optometrist
union all
select '30' as scca_broad_category_code,
'380' as scca_sales_group_code,
'3801' as scca_fine_categories_code,
110.0 as new_uplift
) nu
on nu.scca_broad_category_code = lp.scca_broad_category_code
and nu.scca_sales_group_code = lp.scca_sales_group_code
and nu.scca_fine_categories_code = lp.scca_fine_categories_code
where
(
-- Department Store
( lp.scca_broad_category_code = '10' and
lp.scca_sales_group_code = '100' and
lp.scca_fine_categories_code = '1000' and
lp.scca_notes_code in ('10001', '10002'))
-- Discount Department Store
or
( lp.scca_broad_category_code = '10' and
lp.scca_sales_group_code = '110' and
lp.scca_fine_categories_code = '1100' and
lp.scca_notes_code in ('11001', '11002', '11003', '11004'))
-- Supermarket
or
( lp.scca_broad_category_code = '10' and
lp.scca_sales_group_code = '130' and
lp.scca_fine_categories_code = '1300' and
lp.scca_notes_code in ('13001', '13002', '13003', '13004', '13005',
'13006', '13007', '13007',
'13008', '13009', '13010', '13011', '13012',
'13013', '13014'))
-- Newsagents and Stationary
or
( lp.scca_broad_category_code = '30' and
lp.scca_sales_group_code = '340' and
lp.scca_fine_categories_code = '3403')
-- Discount Variety
or
( lp.scca_broad_category_code = '30' and
lp.scca_sales_group_code = '350' and
lp.scca_fine_categories_code = '3502')
-- Optometrist
or
( lp.scca_broad_category_code = '30' and
lp.scca_sales_group_code = '380' and
lp.scca_fine_categories_code = '3801')
)
and b.building_id <> 42000
and lp.scca_uplift is not null
and lp.period_id >= 252
order by
b.building_name ,
scca_broad_category_code ,
scca_sales_group_code ,
scca_fine_categories_code ,
scca_notes_code
はnu.new_uplift列を取り、ことを各行に適用されますクエリを記述で現在表示されている値で表示されています(混乱する文章、別の方法で説明する必要がある場合は教えてください)。私はCTEを使用してこれを行うことができると思ったが、私はサブクエリを使用しているので可能だとは思わない。そのことを念頭に置いて - 私はここで何を利用すべきですか?
素晴らしいです。どうもありがとうございました。 – Codingo