MAX日付のSELECT行

Question

最新の日付の行を選択したいと思います。私はIDとリリースの両方を選択することができないようです。

T.Released = MAX（T.Released）は私にとっては機能しません。私はMS SQLを使用しています

SELECT ID , Released 
FROM (SELECT [id] 
     ,[Released]  
    FROM [dbo].[PressReleases] 
    where id in 
    (
     ..... 
    )) as T 

Where T.Released = MAX (T.Released) 

id Released 
3 2016-05-26 19:30:41.100 
214 2016-07-04 10:10:32.500 
244 2017-01-20 12:20:29.900 
247 2017-03-09 15:50:38.600 
235 2017-06-01 18:10:38.900 
237 NULL 

Answer 1

サブクエリでMAX Released-Dateを選択するだけです。

SELECT [id] 
     ,[Released]  
    FROM [dbo].[PressReleases] 
WHERE Released = ( 
        SELECT MAX(Released) 
         FROM [dbo].[PressReleases] 
         -- Select here your T Table with the Where Conditions 
       ) 

Answer 2

サブクエリに列が必要です。

SELECT ID , Released 
FROM (SELECT [id] 
     ,[Released]  
    FROM [dbo].[PressReleases] 
    where id in 
    (
     ..... 
    )) as T  
Where T.Released = MAX (T.Released)